%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM676^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:56:59 EDT 2023

% Result   : Theorem 3.62s 3.79s
% Output   : Proof 3.62s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : NUM676^1 : TPTP v8.1.2. Released v3.7.0.
% 0.13/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n003.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Fri Aug 25 14:15:08 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.62/3.79  SZS status Theorem for theBenchmark.p
% 3.62/3.79  SZS output start Proof for theBenchmark.p
% 3.62/3.79  Clause #0 (by assumption #[]): Eq (Eq x y) True
% 3.62/3.79  Clause #1 (by assumption #[]): Eq (more z u) True
% 3.62/3.79  Clause #2 (by assumption #[]): Eq (∀ (Xx Xy Xz : nat), more Xx Xy → more (pl Xz Xx) (pl Xz Xy)) True
% 3.62/3.79  Clause #3 (by assumption #[]): Eq (Not (more (pl x z) (pl y u))) True
% 3.62/3.79  Clause #4 (by clausification #[0]): Eq x y
% 3.62/3.79  Clause #5 (by clausification #[3]): Eq (more (pl x z) (pl y u)) False
% 3.62/3.79  Clause #6 (by forward demodulation #[5, 4]): Eq (more (pl y z) (pl y u)) False
% 3.62/3.79  Clause #7 (by clausification #[2]): ∀ (a : nat), Eq (∀ (Xy Xz : nat), more a Xy → more (pl Xz a) (pl Xz Xy)) True
% 3.62/3.79  Clause #8 (by clausification #[7]): ∀ (a a_1 : nat), Eq (∀ (Xz : nat), more a a_1 → more (pl Xz a) (pl Xz a_1)) True
% 3.62/3.79  Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 : nat), Eq (more a a_1 → more (pl a_2 a) (pl a_2 a_1)) True
% 3.62/3.79  Clause #10 (by clausification #[9]): ∀ (a a_1 a_2 : nat), Or (Eq (more a a_1) False) (Eq (more (pl a_2 a) (pl a_2 a_1)) True)
% 3.62/3.79  Clause #11 (by superposition #[10, 1]): ∀ (a : nat), Or (Eq (more (pl a z) (pl a u)) True) (Eq False True)
% 3.62/3.79  Clause #12 (by clausification #[11]): ∀ (a : nat), Eq (more (pl a z) (pl a u)) True
% 3.62/3.79  Clause #13 (by superposition #[12, 6]): Eq True False
% 3.62/3.79  Clause #15 (by clausification #[13]): False
% 3.62/3.79  SZS output end Proof for theBenchmark.p
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