%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : NUM673^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:56:58 EDT 2023

% Result   : Theorem 3.55s 3.78s
% Output   : Proof 3.55s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : NUM673^1 : TPTP v8.1.2. Released v3.7.0.
% 0.13/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n004.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Fri Aug 25 16:44:38 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.55/3.78  SZS status Theorem for theBenchmark.p
% 3.55/3.78  SZS output start Proof for theBenchmark.p
% 3.55/3.78  Clause #0 (by assumption #[]): Eq (more x y) True
% 3.55/3.78  Clause #1 (by assumption #[]): Eq (∀ (Xx Xy Xz : nat), more Xx Xy → more (pl Xx Xz) (pl Xy Xz)) True
% 3.55/3.78  Clause #2 (by assumption #[]): Eq (∀ (Xx Xy : nat), Eq (pl Xx Xy) (pl Xy Xx)) True
% 3.55/3.78  Clause #3 (by assumption #[]): Eq (Not (more (pl z x) (pl z y))) True
% 3.55/3.78  Clause #4 (by clausification #[3]): Eq (more (pl z x) (pl z y)) False
% 3.55/3.78  Clause #5 (by clausification #[2]): ∀ (a : nat), Eq (∀ (Xy : nat), Eq (pl a Xy) (pl Xy a)) True
% 3.55/3.78  Clause #6 (by clausification #[5]): ∀ (a a_1 : nat), Eq (Eq (pl a a_1) (pl a_1 a)) True
% 3.55/3.78  Clause #7 (by clausification #[6]): ∀ (a a_1 : nat), Eq (pl a a_1) (pl a_1 a)
% 3.55/3.78  Clause #8 (by clausification #[1]): ∀ (a : nat), Eq (∀ (Xy Xz : nat), more a Xy → more (pl a Xz) (pl Xy Xz)) True
% 3.55/3.78  Clause #9 (by clausification #[8]): ∀ (a a_1 : nat), Eq (∀ (Xz : nat), more a a_1 → more (pl a Xz) (pl a_1 Xz)) True
% 3.55/3.78  Clause #10 (by clausification #[9]): ∀ (a a_1 a_2 : nat), Eq (more a a_1 → more (pl a a_2) (pl a_1 a_2)) True
% 3.55/3.78  Clause #11 (by clausification #[10]): ∀ (a a_1 a_2 : nat), Or (Eq (more a a_1) False) (Eq (more (pl a a_2) (pl a_1 a_2)) True)
% 3.55/3.78  Clause #12 (by superposition #[11, 0]): ∀ (a : nat), Or (Eq (more (pl x a) (pl y a)) True) (Eq False True)
% 3.55/3.78  Clause #13 (by clausification #[12]): ∀ (a : nat), Eq (more (pl x a) (pl y a)) True
% 3.55/3.78  Clause #16 (by superposition #[13, 7]): ∀ (a : nat), Eq (more (pl a x) (pl y a)) True
% 3.55/3.78  Clause #24 (by superposition #[16, 7]): ∀ (a : nat), Eq (more (pl a x) (pl a y)) True
% 3.55/3.78  Clause #25 (by superposition #[24, 4]): Eq True False
% 3.55/3.78  Clause #27 (by clausification #[25]): False
% 3.55/3.78  SZS output end Proof for theBenchmark.p
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