TSTP Solution File: NUM638^1 by cocATP---0.2.0
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% File : cocATP---0.2.0
% Problem : NUM638^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n186.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32218.625MB
% OS : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan 8 13:11:14 EST 2018
% Result : Theorem 1.31s
% Output : Proof 1.31s
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.04 % Problem : NUM638^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.05 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.24 % Computer : n186.star.cs.uiowa.edu
% 0.02/0.24 % Model : x86_64 x86_64
% 0.02/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.24 % Memory : 32218.625MB
% 0.02/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.24 % CPULimit : 300
% 0.02/0.24 % DateTime : Fri Jan 5 11:18:00 CST 2018
% 0.02/0.24 % CPUTime :
% 0.02/0.26 Python 2.7.13
% 1.31/1.56 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 1.31/1.56 FOF formula (<kernel.Constant object at 0x2aca99094710>, <kernel.Type object at 0x2aca9908d050>) of role type named nat_type
% 1.31/1.56 Using role type
% 1.31/1.56 Declaring nat:Type
% 1.31/1.56 FOF formula (<kernel.Constant object at 0x2aca99094908>, <kernel.Constant object at 0x2aca9908d710>) of role type named x
% 1.31/1.56 Using role type
% 1.31/1.56 Declaring x:nat
% 1.31/1.56 FOF formula (<kernel.Constant object at 0x2aca99094710>, <kernel.Constant object at 0x2aca9908d3b0>) of role type named n_1
% 1.31/1.56 Using role type
% 1.31/1.56 Declaring n_1:nat
% 1.31/1.56 FOF formula (not (((eq nat) x) n_1)) of role axiom named n
% 1.31/1.56 A new axiom: (not (((eq nat) x) n_1))
% 1.31/1.56 FOF formula (<kernel.Constant object at 0x2aca99094710>, <kernel.DependentProduct object at 0x2aca9908d830>) of role type named suc
% 1.31/1.56 Using role type
% 1.31/1.56 Declaring suc:(nat->nat)
% 1.31/1.56 FOF formula (<kernel.Constant object at 0x2aca99094710>, <kernel.DependentProduct object at 0x2aca9908d320>) of role type named some
% 1.31/1.56 Using role type
% 1.31/1.56 Declaring some:((nat->Prop)->Prop)
% 1.31/1.56 FOF formula (forall (Xx:nat) (Xy:nat), ((((eq nat) (suc Xx)) (suc Xy))->(((eq nat) Xx) Xy))) of role axiom named ax4
% 1.31/1.56 A new axiom: (forall (Xx:nat) (Xy:nat), ((((eq nat) (suc Xx)) (suc Xy))->(((eq nat) Xx) Xy)))
% 1.31/1.56 FOF formula (forall (Xx:nat), ((not (((eq nat) Xx) n_1))->(some (fun (Xu:nat)=> (((eq nat) Xx) (suc Xu)))))) of role axiom named satz3
% 1.31/1.56 A new axiom: (forall (Xx:nat), ((not (((eq nat) Xx) n_1))->(some (fun (Xu:nat)=> (((eq nat) Xx) (suc Xu))))))
% 1.31/1.56 FOF formula (((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False))->False) of role conjecture named satz3a
% 1.31/1.56 Conjecture to prove = (((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False))->False):Prop
% 1.31/1.56 We need to prove ['(((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False))->False)']
% 1.31/1.56 Parameter nat:Type.
% 1.31/1.56 Parameter x:nat.
% 1.31/1.56 Parameter n_1:nat.
% 1.31/1.56 Axiom n:(not (((eq nat) x) n_1)).
% 1.31/1.56 Parameter suc:(nat->nat).
% 1.31/1.56 Parameter some:((nat->Prop)->Prop).
% 1.31/1.56 Axiom ax4:(forall (Xx:nat) (Xy:nat), ((((eq nat) (suc Xx)) (suc Xy))->(((eq nat) Xx) Xy))).
% 1.31/1.56 Axiom satz3:(forall (Xx:nat), ((not (((eq nat) Xx) n_1))->(some (fun (Xu:nat)=> (((eq nat) Xx) (suc Xu)))))).
% 1.31/1.56 Trying to prove (((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False))->False)
% 1.31/1.56 Found satz300:=(satz30 n):(some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))
% 1.31/1.56 Found (satz30 n) as proof of (some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))
% 1.31/1.56 Found ((satz3 x) n) as proof of (some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))
% 1.31/1.56 Found ((satz3 x) n) as proof of (some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))
% 1.31/1.56 Found x0000:=(x000 x1):(((eq nat) (suc Xx_0)) (suc Xy))
% 1.31/1.56 Found (x000 x1) as proof of (((eq nat) (suc Xx_0)) (suc Xy))
% 1.31/1.56 Found ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1) as proof of (((eq nat) (suc Xx_0)) (suc Xy))
% 1.31/1.56 Found ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1) as proof of (((eq nat) (suc Xx_0)) (suc Xy))
% 1.31/1.56 Found (ax400 ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)) as proof of (((eq nat) Xx_0) Xy)
% 1.31/1.56 Found ((ax40 Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)) as proof of (((eq nat) Xx_0) Xy)
% 1.31/1.56 Found (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)) as proof of (((eq nat) Xx_0) Xy)
% 1.31/1.56 Found (fun (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1))) as proof of (((eq nat) Xx_0) Xy)
% 1.31/1.56 Found (fun (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1))) as proof of ((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))
% 1.31/1.56 Found (fun (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1))) as proof of ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy)))
% 1.31/1.57 Found (fun (Xx_0:nat) (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1))) as proof of (forall (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))
% 1.31/1.57 Found (fun (Xx_0:nat) (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1))) as proof of (forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))
% 1.31/1.57 Found ((x0 (fun (Xx_0:nat) (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)))) ((satz3 x) n)) as proof of False
% 1.31/1.57 Found (fun (x0:((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False)))=> ((x0 (fun (Xx_0:nat) (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)))) ((satz3 x) n))) as proof of False
% 1.31/1.57 Found (fun (x0:((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False)))=> ((x0 (fun (Xx_0:nat) (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)))) ((satz3 x) n))) as proof of (((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False))->False)
% 1.31/1.57 Got proof (fun (x0:((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False)))=> ((x0 (fun (Xx_0:nat) (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)))) ((satz3 x) n)))
% 1.31/1.57 Time elapsed = 1.029380s
% 1.31/1.57 node=152 cost=174.000000 depth=13
% 1.31/1.57::::::::::::::::::::::
% 1.31/1.57 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 1.31/1.57 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 1.31/1.57 (fun (x0:((forall (Xx_0:nat) (Xy:nat), ((((eq nat) x) (suc Xx_0))->((((eq nat) x) (suc Xy))->(((eq nat) Xx_0) Xy))))->((some (fun (Xu:nat)=> (((eq nat) x) (suc Xu))))->False)))=> ((x0 (fun (Xx_0:nat) (Xy:nat) (x00:(((eq nat) x) (suc Xx_0))) (x1:(((eq nat) x) (suc Xy)))=> (((ax4 Xx_0) Xy) ((x00 (fun (x2:nat)=> (((eq nat) x2) (suc Xy)))) x1)))) ((satz3 x) n)))
% 1.31/1.57 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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