TSTP Solution File: NUM617+3 by Duper---1.0

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% File     : Duper---1.0
% Problem  : NUM617+3 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:56:32 EDT 2023

% Result   : Theorem 8.82s 9.09s
% Output   : Proof 8.82s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : NUM617+3 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.15/0.35  % Computer : n006.cluster.edu
% 0.15/0.35  % Model    : x86_64 x86_64
% 0.15/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35  % Memory   : 8042.1875MB
% 0.15/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36  % CPULimit   : 300
% 0.15/0.36  % WCLimit    : 300
% 0.15/0.36  % DateTime   : Fri Aug 25 12:00:37 EDT 2023
% 0.15/0.36  % CPUTime    : 
% 8.82/9.09  SZS status Theorem for theBenchmark.p
% 8.82/9.09  SZS output start Proof for theBenchmark.p
% 8.82/9.09  Clause #99 (by assumption #[]): Eq (And (∀ (W0 : Iota), aElementOf0 W0 xQ → aElementOf0 W0 szNzAzT0) (aSubsetOf0 xQ szNzAzT0)) True
% 8.82/9.09  Clause #105 (by assumption #[]): Eq (And (∀ (W0 : Iota), aElementOf0 W0 xP → aElementOf0 W0 xQ) (aSubsetOf0 xP xQ)) True
% 8.82/9.09  Clause #111 (by assumption #[]): Eq (And (And (And (aElement0 xx) (aElementOf0 xx xQ)) (Ne xx (szmzizndt0 xQ))) (aElementOf0 xx xP)) True
% 8.82/9.09  Clause #112 (by assumption #[]): Eq (Not (aElementOf0 xx szNzAzT0)) True
% 8.82/9.09  Clause #127 (by clausification #[112]): Eq (aElementOf0 xx szNzAzT0) False
% 8.82/9.09  Clause #811 (by clausification #[99]): Eq (∀ (W0 : Iota), aElementOf0 W0 xQ → aElementOf0 W0 szNzAzT0) True
% 8.82/9.09  Clause #814 (by clausification #[811]): ∀ (a : Iota), Eq (aElementOf0 a xQ → aElementOf0 a szNzAzT0) True
% 8.82/9.09  Clause #815 (by clausification #[814]): ∀ (a : Iota), Or (Eq (aElementOf0 a xQ) False) (Eq (aElementOf0 a szNzAzT0) True)
% 8.82/9.09  Clause #1640 (by clausification #[105]): Eq (∀ (W0 : Iota), aElementOf0 W0 xP → aElementOf0 W0 xQ) True
% 8.82/9.09  Clause #1641 (by clausification #[1640]): ∀ (a : Iota), Eq (aElementOf0 a xP → aElementOf0 a xQ) True
% 8.82/9.09  Clause #1642 (by clausification #[1641]): ∀ (a : Iota), Or (Eq (aElementOf0 a xP) False) (Eq (aElementOf0 a xQ) True)
% 8.82/9.09  Clause #2288 (by clausification #[111]): Eq (aElementOf0 xx xP) True
% 8.82/9.09  Clause #2291 (by superposition #[2288, 1642]): Or (Eq True False) (Eq (aElementOf0 xx xQ) True)
% 8.82/9.09  Clause #2292 (by clausification #[2291]): Eq (aElementOf0 xx xQ) True
% 8.82/9.09  Clause #2293 (by superposition #[2292, 815]): Or (Eq True False) (Eq (aElementOf0 xx szNzAzT0) True)
% 8.82/9.09  Clause #2296 (by clausification #[2293]): Eq (aElementOf0 xx szNzAzT0) True
% 8.82/9.09  Clause #2297 (by superposition #[2296, 127]): Eq True False
% 8.82/9.09  Clause #2333 (by clausification #[2297]): False
% 8.82/9.09  SZS output end Proof for theBenchmark.p
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