TSTP Solution File: NUM606+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM606+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n010.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:28:01 EDT 2022
% Result : Theorem 0.60s 0.79s
% Output : Refutation 0.60s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 8
% Syntax : Number of clauses : 16 ( 9 unt; 0 nHn; 16 RR)
% Number of literals : 32 ( 0 equ; 20 neg)
% Maximal clause size : 6 ( 2 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-2 aty)
% Number of functors : 7 ( 7 usr; 7 con; 0-0 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(2,axiom,
aSet0(szNzAzT0),
file('NUM606+1.p',unknown),
[] ).
cnf(3,axiom,
isCountable0(szNzAzT0),
file('NUM606+1.p',unknown),
[] ).
cnf(17,axiom,
aSubsetOf0(xS,szNzAzT0),
file('NUM606+1.p',unknown),
[] ).
cnf(20,axiom,
aSubsetOf0(xO,xS),
file('NUM606+1.p',unknown),
[] ).
cnf(21,axiom,
aSubsetOf0(xQ,xO),
file('NUM606+1.p',unknown),
[] ).
cnf(22,axiom,
~ aSubsetOf0(xQ,szNzAzT0),
file('NUM606+1.p',unknown),
[] ).
cnf(67,axiom,
( ~ aSet0(u)
| ~ aSubsetOf0(v,u)
| aSet0(v) ),
file('NUM606+1.p',unknown),
[] ).
cnf(147,axiom,
( ~ aSet0(u)
| ~ aSet0(v)
| ~ aSet0(w)
| ~ aSubsetOf0(u,v)
| ~ aSubsetOf0(v,w)
| aSubsetOf0(u,w) ),
file('NUM606+1.p',unknown),
[] ).
cnf(206,plain,
( ~ aSet0(u)
| ~ aSubsetOf0(v,u)
| ~ aSubsetOf0(w,v)
| aSubsetOf0(w,u) ),
inference(mrr,[status(thm)],[147,67]),
[iquote('0:MRR:147.0,147.1,67.2,67.2')] ).
cnf(219,plain,
( ~ aSet0(szNzAzT0)
| ~ aSubsetOf0(xQ,u)
| ~ aSubsetOf0(u,szNzAzT0) ),
inference(res,[status(thm),theory(equality)],[206,22]),
[iquote('0:Res:206.3,22.0')] ).
cnf(224,plain,
( ~ aSubsetOf0(u,szNzAzT0)
| ~ aSubsetOf0(xQ,u) ),
inference(mrr,[status(thm)],[219,2]),
[iquote('0:MRR:219.0,2.0')] ).
cnf(910,plain,
( ~ aSet0(szNzAzT0)
| ~ aSubsetOf0(u,xS)
| aSubsetOf0(u,szNzAzT0) ),
inference(res,[status(thm),theory(equality)],[17,206]),
[iquote('0:Res:17.0,206.1')] ).
cnf(921,plain,
( ~ aSubsetOf0(u,xS)
| aSubsetOf0(u,szNzAzT0) ),
inference(ssi,[status(thm)],[910,3,2]),
[iquote('0:SSi:910.0,3.0,2.0')] ).
cnf(940,plain,
aSubsetOf0(xO,szNzAzT0),
inference(res,[status(thm),theory(equality)],[20,921]),
[iquote('0:Res:20.0,921.0')] ).
cnf(942,plain,
~ aSubsetOf0(xQ,xO),
inference(res,[status(thm),theory(equality)],[940,224]),
[iquote('0:Res:940.0,224.0')] ).
cnf(947,plain,
$false,
inference(mrr,[status(thm)],[942,21]),
[iquote('0:MRR:942.0,21.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11 % Problem : NUM606+1 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.12 % Command : run_spass %d %s
% 0.11/0.33 % Computer : n010.cluster.edu
% 0.11/0.33 % Model : x86_64 x86_64
% 0.11/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33 % Memory : 8042.1875MB
% 0.11/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33 % CPULimit : 300
% 0.11/0.33 % WCLimit : 600
% 0.11/0.33 % DateTime : Wed Jul 6 01:59:47 EDT 2022
% 0.11/0.33 % CPUTime :
% 0.60/0.79
% 0.60/0.79 SPASS V 3.9
% 0.60/0.79 SPASS beiseite: Proof found.
% 0.60/0.79 % SZS status Theorem
% 0.60/0.79 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.60/0.79 SPASS derived 538 clauses, backtracked 24 clauses, performed 2 splits and kept 460 clauses.
% 0.60/0.79 SPASS allocated 101023 KBytes.
% 0.60/0.79 SPASS spent 0:00:00.45 on the problem.
% 0.60/0.79 0:00:00.04 for the input.
% 0.60/0.79 0:00:00.29 for the FLOTTER CNF translation.
% 0.60/0.79 0:00:00.01 for inferences.
% 0.60/0.79 0:00:00.00 for the backtracking.
% 0.60/0.79 0:00:00.07 for the reduction.
% 0.60/0.79
% 0.60/0.79
% 0.60/0.79 Here is a proof with depth 3, length 16 :
% 0.60/0.79 % SZS output start Refutation
% See solution above
% 0.60/0.79 Formulae used in the proof : mNATSet m__3435 m__4998 m__5093 m__ mDefSub mSubTrans
% 0.60/0.79
%------------------------------------------------------------------------------