TSTP Solution File: NUM586+3 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM586+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:27:48 EDT 2022
% Result : Theorem 1.86s 2.05s
% Output : Refutation 1.86s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 6
% Syntax : Number of clauses : 13 ( 6 unt; 0 nHn; 13 RR)
% Number of literals : 23 ( 0 equ; 15 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 4 ( 2 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-2 aty)
% Number of functors : 14 ( 14 usr; 9 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(15,axiom,
aElementOf0(xi,szNzAzT0),
file('NUM586+3.p',unknown),
[] ).
cnf(36,axiom,
aElementOf0(skc85,szDzozmdt0(sdtlpdtrp0(xC,xi))),
file('NUM586+3.p',unknown),
[] ).
cnf(44,axiom,
equal(sdtlpdtrp0(sdtlpdtrp0(xC,xi),skc85),xx),
file('NUM586+3.p',unknown),
[] ).
cnf(120,axiom,
( ~ aElementOf0(u,szNzAzT0)
| ~ aElementOf0(v,szDzozmdt0(sdtlpdtrp0(xC,u)))
| equal(sbrdtbr0(v),xk) ),
file('NUM586+3.p',unknown),
[] ).
cnf(199,axiom,
( ~ aElementOf0(u,szNzAzT0)
| ~ aElementOf0(v,szDzozmdt0(sdtlpdtrp0(xC,u)))
| aSubsetOf0(v,sdtmndt0(sdtlpdtrp0(xN,u),szmzizndt0(sdtlpdtrp0(xN,u)))) ),
file('NUM586+3.p',unknown),
[] ).
cnf(242,axiom,
( ~ aSubsetOf0(u,sdtmndt0(sdtlpdtrp0(xN,xi),szmzizndt0(sdtlpdtrp0(xN,xi))))
| ~ equal(sbrdtbr0(u),xk)
| ~ equal(sdtlpdtrp0(sdtlpdtrp0(xC,xi),u),xx) ),
file('NUM586+3.p',unknown),
[] ).
cnf(316,plain,
( ~ aSubsetOf0(skc85,sdtmndt0(sdtlpdtrp0(xN,xi),szmzizndt0(sdtlpdtrp0(xN,xi))))
| ~ equal(sbrdtbr0(skc85),xk) ),
inference(res,[status(thm),theory(equality)],[44,242]),
[iquote('0:Res:44.0,242.2')] ).
cnf(1898,plain,
( ~ aElementOf0(xi,szNzAzT0)
| equal(sbrdtbr0(skc85),xk) ),
inference(res,[status(thm),theory(equality)],[36,120]),
[iquote('0:Res:36.0,120.1')] ).
cnf(1905,plain,
equal(sbrdtbr0(skc85),xk),
inference(mrr,[status(thm)],[1898,15]),
[iquote('0:MRR:1898.0,15.0')] ).
cnf(1909,plain,
( ~ aSubsetOf0(skc85,sdtmndt0(sdtlpdtrp0(xN,xi),szmzizndt0(sdtlpdtrp0(xN,xi))))
| ~ equal(xk,xk) ),
inference(rew,[status(thm),theory(equality)],[1905,316]),
[iquote('0:Rew:1905.0,316.1')] ).
cnf(1910,plain,
~ aSubsetOf0(skc85,sdtmndt0(sdtlpdtrp0(xN,xi),szmzizndt0(sdtlpdtrp0(xN,xi)))),
inference(obv,[status(thm),theory(equality)],[1909]),
[iquote('0:Obv:1909.1')] ).
cnf(6816,plain,
( ~ aElementOf0(xi,szNzAzT0)
| ~ aElementOf0(skc85,szDzozmdt0(sdtlpdtrp0(xC,xi))) ),
inference(res,[status(thm),theory(equality)],[199,1910]),
[iquote('0:Res:199.2,1910.0')] ).
cnf(6817,plain,
$false,
inference(mrr,[status(thm)],[6816,15,36]),
[iquote('0:MRR:6816.0,6816.1,15.0,36.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : NUM586+3 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.11 % Command : run_spass %d %s
% 0.11/0.32 % Computer : n009.cluster.edu
% 0.11/0.32 % Model : x86_64 x86_64
% 0.11/0.32 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.32 % Memory : 8042.1875MB
% 0.11/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.32 % CPULimit : 300
% 0.11/0.32 % WCLimit : 600
% 0.11/0.32 % DateTime : Thu Jul 7 08:31:37 EDT 2022
% 0.11/0.32 % CPUTime :
% 1.86/2.05
% 1.86/2.05 SPASS V 3.9
% 1.86/2.05 SPASS beiseite: Proof found.
% 1.86/2.05 % SZS status Theorem
% 1.86/2.05 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 1.86/2.05 SPASS derived 5100 clauses, backtracked 791 clauses, performed 16 splits and kept 3112 clauses.
% 1.86/2.05 SPASS allocated 103795 KBytes.
% 1.86/2.05 SPASS spent 0:00:01.69 on the problem.
% 1.86/2.05 0:00:00.04 for the input.
% 1.86/2.05 0:00:00.68 for the FLOTTER CNF translation.
% 1.86/2.05 0:00:00.07 for inferences.
% 1.86/2.05 0:00:00.02 for the backtracking.
% 1.86/2.05 0:00:00.82 for the reduction.
% 1.86/2.05
% 1.86/2.05
% 1.86/2.05 Here is a proof with depth 2, length 13 :
% 1.86/2.05 % SZS output start Refutation
% See solution above
% 1.86/2.05 Formulae used in the proof : m__4200 m__4200_02 m__4151 m__
% 1.86/2.05
%------------------------------------------------------------------------------