TSTP Solution File: NUM551+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : NUM551+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:19:26 EDT 2022

% Result   : Theorem 2.65s 2.88s
% Output   : Refutation 2.65s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : NUM551+1 : TPTP v8.1.0. Released v4.0.0.
% 0.10/0.12  % Command  : sos-script %s
% 0.13/0.33  % Computer : n015.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Wed Jul  6 08:57:18 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.13/0.36  ----- Otter 3.2, August 2001 -----
% 0.13/0.36  The process was started by sandbox on n015.cluster.edu,
% 0.13/0.36  Wed Jul  6 08:57:18 2022
% 0.13/0.36  The command was "./sos".  The process ID is 25214.
% 0.13/0.36  
% 0.13/0.36  set(prolog_style_variables).
% 0.13/0.36  set(auto).
% 0.13/0.36     dependent: set(auto1).
% 0.13/0.36     dependent: set(process_input).
% 0.13/0.36     dependent: clear(print_kept).
% 0.13/0.36     dependent: clear(print_new_demod).
% 0.13/0.36     dependent: clear(print_back_demod).
% 0.13/0.36     dependent: clear(print_back_sub).
% 0.13/0.36     dependent: set(control_memory).
% 0.13/0.36     dependent: assign(max_mem, 12000).
% 0.13/0.36     dependent: assign(pick_given_ratio, 4).
% 0.13/0.36     dependent: assign(stats_level, 1).
% 0.13/0.36     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.36     dependent: assign(sos_limit, 5000).
% 0.13/0.36     dependent: assign(max_weight, 60).
% 0.13/0.36  clear(print_given).
% 0.13/0.36  
% 0.13/0.36  formula_list(usable).
% 0.13/0.36  
% 0.13/0.36  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=8.
% 0.13/0.36  
% 0.13/0.36  This ia a non-Horn set with equality.  The strategy will be
% 0.13/0.36  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.13/0.36  unit deletion, with positive clauses in sos and nonpositive
% 0.13/0.36  clauses in usable.
% 0.13/0.36  
% 0.13/0.36     dependent: set(knuth_bendix).
% 0.13/0.36     dependent: set(para_from).
% 0.13/0.36     dependent: set(para_into).
% 0.13/0.36     dependent: clear(para_from_right).
% 0.13/0.36     dependent: clear(para_into_right).
% 0.13/0.36     dependent: set(para_from_vars).
% 0.13/0.36     dependent: set(eq_units_both_ways).
% 0.13/0.36     dependent: set(dynamic_demod_all).
% 0.13/0.36     dependent: set(dynamic_demod).
% 0.13/0.36     dependent: set(order_eq).
% 0.13/0.36     dependent: set(back_demod).
% 0.13/0.36     dependent: set(lrpo).
% 0.13/0.36     dependent: set(hyper_res).
% 0.13/0.36     dependent: set(unit_deletion).
% 0.13/0.36     dependent: set(factor).
% 0.13/0.36  
% 0.13/0.36  ------------> process usable:
% 0.13/0.36  114 back subsumes 113.
% 0.13/0.36  
% 0.13/0.36  ------------> process sos:
% 0.13/0.36    Following clause subsumed by 149 during input processing: 0 [copy,149,flip.1] {-} A=A.
% 0.13/0.36  149 back subsumes 124.
% 0.13/0.36  149 back subsumes 119.
% 0.13/0.36  149 back subsumes 118.
% 0.13/0.36  149 back subsumes 116.
% 0.13/0.36  149 back subsumes 112.
% 0.13/0.37  149 back subsumes 106.
% 0.13/0.37  
% 0.13/0.37  ======= end of input processing =======
% 0.46/0.70  
% 0.46/0.70  Stopped by limit on insertions
% 0.46/0.70  
% 0.46/0.70  
% 0.46/0.70  Failed to model usable list: disabling FINDER
% 0.46/0.70  
% 0.46/0.70  
% 0.46/0.70  
% 0.46/0.70  -------------- Softie stats --------------
% 0.46/0.70  
% 0.46/0.70  UPDATE_STOP: 300
% 0.46/0.70  SFINDER_TIME_LIMIT: 2
% 0.46/0.70  SHORT_CLAUSE_CUTOFF: 4
% 0.46/0.70  number of clauses in intial UL: 123
% 0.46/0.70  number of clauses initially in problem: 140
% 0.46/0.70  percentage of clauses intially in UL: 87
% 0.46/0.70  percentage of distinct symbols occuring in initial UL: 94
% 0.46/0.70  percent of all initial clauses that are short: 100
% 0.46/0.70  absolute distinct symbol count: 36
% 0.46/0.70     distinct predicate count: 9
% 0.46/0.70     distinct function count: 19
% 0.46/0.70     distinct constant count: 8
% 0.46/0.70  
% 0.46/0.70  ---------- no more Softie stats ----------
% 0.46/0.70  
% 0.46/0.70  
% 0.46/0.70  
% 0.46/0.70  =========== start of search ===========
% 1.91/2.10  
% 1.91/2.10  
% 1.91/2.10  Changing weight limit from 60 to 53.
% 1.91/2.10  
% 1.91/2.10  Resetting weight limit to 53 after 40 givens.
% 1.91/2.10  
% 2.65/2.88  
% 2.65/2.88  -------- PROOF -------- 
% 2.65/2.88  % SZS status Theorem
% 2.65/2.88  % SZS output start Refutation
% 2.65/2.88  
% 2.65/2.88  -----> EMPTY CLAUSE at   2.50 sec ----> 6460 [hyper,6334,105,511] {-} $F.
% 2.65/2.88  
% 2.65/2.88  Length of proof is 2.  Level of proof is 2.
% 2.65/2.88  
% 2.65/2.88  ---------------- PROOF ----------------
% 2.65/2.88  % SZS status Theorem
% 2.65/2.88  % SZS output start Refutation
% 2.65/2.88  
% 2.65/2.88  1 [] {+} -aSet0(A)| -aElementOf0(B,A)|aElement0(B).
% 2.65/2.88  4 [] {+} A=slcrc0| -aSet0(A)|aElementOf0($f1(A),A).
% 2.65/2.88  104 [] {+} xQ!=slcrc0.
% 2.65/2.88  105 [] {+} -aElement0(A)| -aElementOf0(A,xQ).
% 2.65/2.88  145 [] {-} aSet0(xQ).
% 2.65/2.88  511 [hyper,145,4,unit_del,104] {-} aElementOf0($f1(xQ),xQ).
% 2.65/2.88  6334 [hyper,511,1,145] {-} aElement0($f1(xQ)).
% 2.65/2.88  6460 [hyper,6334,105,511] {-} $F.
% 2.65/2.88  
% 2.65/2.88  % SZS output end Refutation
% 2.65/2.88  ------------ end of proof -------------
% 2.65/2.88  
% 2.65/2.88  
% 2.65/2.88  Search stopped by max_proofs option.
% 2.65/2.88  
% 2.65/2.88  
% 2.65/2.88  Search stopped by max_proofs option.
% 2.65/2.88  
% 2.65/2.88  ============ end of search ============
% 2.65/2.88  
% 2.65/2.88  That finishes the proof of the theorem.
% 2.65/2.88  
% 2.65/2.88  Process 25214 finished Wed Jul  6 08:57:21 2022
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