TSTP Solution File: NUM521+3 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM521+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:27:04 EDT 2022

% Result   : Theorem 0.22s 0.50s
% Output   : Refutation 0.22s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :   13
% Syntax   : Number of clauses     :   31 (  19 unt;   2 nHn;  31 RR)
%            Number of literals    :   51 (   0 equ;  29 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    6 (   5 usr;   2 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    aNaturalNumber0(sz10),
    file('NUM521+3.p',unknown),
    [] ).

cnf(3,axiom,
    aNaturalNumber0(xn),
    file('NUM521+3.p',unknown),
    [] ).

cnf(4,axiom,
    aNaturalNumber0(xm),
    file('NUM521+3.p',unknown),
    [] ).

cnf(5,axiom,
    aNaturalNumber0(xp),
    file('NUM521+3.p',unknown),
    [] ).

cnf(7,axiom,
    isPrime0(xp),
    file('NUM521+3.p',unknown),
    [] ).

cnf(20,axiom,
    ~ sdtlseqdt0(xp,xn),
    file('NUM521+3.p',unknown),
    [] ).

cnf(21,axiom,
    ~ sdtlseqdt0(xp,xm),
    file('NUM521+3.p',unknown),
    [] ).

cnf(24,axiom,
    ( ~ sdtlseqdt0(xn,xp)
    | skC0 ),
    file('NUM521+3.p',unknown),
    [] ).

cnf(25,axiom,
    ( ~ aNaturalNumber0(u)
    | sdtlseqdt0(u,u) ),
    file('NUM521+3.p',unknown),
    [] ).

cnf(30,axiom,
    ( ~ aNaturalNumber0(u)
    | equal(sdtasdt0(u,sz10),u) ),
    file('NUM521+3.p',unknown),
    [] ).

cnf(34,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ equal(sdtasdt0(xp,u),xn) ),
    file('NUM521+3.p',unknown),
    [] ).

cnf(44,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | sdtlseqdt0(v,u)
    | sdtlseqdt0(u,v) ),
    file('NUM521+3.p',unknown),
    [] ).

cnf(48,axiom,
    ( ~ skC0
    | ~ sdtlseqdt0(xm,xp)
    | equal(xp,xm)
    | equal(xp,xn) ),
    file('NUM521+3.p',unknown),
    [] ).

cnf(133,plain,
    ~ equal(sdtasdt0(xp,sz10),xn),
    inference(res,[status(thm),theory(equality)],[2,34]),
    [iquote('0:Res:2.0,34.0')] ).

cnf(148,plain,
    equal(xp,xm),
    inference(spt,[spt(split,[position(s1)])],[48]),
    [iquote('1:Spt:48.2')] ).

cnf(167,plain,
    isPrime0(xm),
    inference(rew,[status(thm),theory(equality)],[148,7]),
    [iquote('1:Rew:148.0,7.0')] ).

cnf(171,plain,
    ~ sdtlseqdt0(xm,xm),
    inference(rew,[status(thm),theory(equality)],[148,21]),
    [iquote('1:Rew:148.0,21.0')] ).

cnf(189,plain,
    ~ aNaturalNumber0(xm),
    inference(res,[status(thm),theory(equality)],[25,171]),
    [iquote('1:Res:25.1,171.0')] ).

cnf(190,plain,
    $false,
    inference(ssi,[status(thm)],[189,4,167]),
    [iquote('1:SSi:189.0,4.0,167.0')] ).

cnf(191,plain,
    ~ equal(xp,xm),
    inference(spt,[spt(split,[position(sa)])],[190,148]),
    [iquote('1:Spt:190.0,48.2,148.0')] ).

cnf(192,plain,
    ( ~ skC0
    | ~ sdtlseqdt0(xm,xp)
    | equal(xp,xn) ),
    inference(spt,[spt(split,[position(s2)])],[48]),
    [iquote('1:Spt:190.0,48.0,48.1,48.3')] ).

cnf(194,plain,
    ( ~ sdtlseqdt0(xn,xp)
    | ~ sdtlseqdt0(xm,xp)
    | equal(xp,xn) ),
    inference(res,[status(thm),theory(equality)],[24,192]),
    [iquote('1:Res:24.1,192.0')] ).

cnf(210,plain,
    ( ~ aNaturalNumber0(xp)
    | ~ equal(xp,xn) ),
    inference(spl,[status(thm),theory(equality)],[30,133]),
    [iquote('0:SpL:30.1,133.0')] ).

cnf(211,plain,
    ~ equal(xp,xn),
    inference(ssi,[status(thm)],[210,5,7]),
    [iquote('0:SSi:210.0,5.0,7.0')] ).

cnf(214,plain,
    ( ~ sdtlseqdt0(xn,xp)
    | ~ sdtlseqdt0(xm,xp) ),
    inference(mrr,[status(thm)],[194,211]),
    [iquote('1:MRR:194.2,211.0')] ).

cnf(364,plain,
    ( ~ aNaturalNumber0(xn)
    | ~ aNaturalNumber0(xp)
    | sdtlseqdt0(xn,xp) ),
    inference(res,[status(thm),theory(equality)],[44,20]),
    [iquote('0:Res:44.2,20.0')] ).

cnf(367,plain,
    ( ~ aNaturalNumber0(xp)
    | ~ aNaturalNumber0(xm)
    | sdtlseqdt0(xm,xp) ),
    inference(res,[status(thm),theory(equality)],[44,21]),
    [iquote('0:Res:44.3,21.0')] ).

cnf(369,plain,
    sdtlseqdt0(xn,xp),
    inference(ssi,[status(thm)],[364,5,7,3]),
    [iquote('0:SSi:364.1,364.0,5.0,7.0,3.0')] ).

cnf(371,plain,
    ~ sdtlseqdt0(xm,xp),
    inference(mrr,[status(thm)],[214,369]),
    [iquote('1:MRR:214.0,369.0')] ).

cnf(375,plain,
    sdtlseqdt0(xm,xp),
    inference(ssi,[status(thm)],[367,4,5,7]),
    [iquote('0:SSi:367.1,367.0,4.0,5.0,7.0')] ).

cnf(376,plain,
    $false,
    inference(mrr,[status(thm)],[375,371]),
    [iquote('1:MRR:375.0,371.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem  : NUM521+3 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.14/0.35  % Computer : n026.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % WCLimit  : 600
% 0.14/0.35  % DateTime : Thu Jul  7 20:02:54 EDT 2022
% 0.14/0.35  % CPUTime  : 
% 0.22/0.50  
% 0.22/0.50  SPASS V 3.9 
% 0.22/0.50  SPASS beiseite: Proof found.
% 0.22/0.50  % SZS status Theorem
% 0.22/0.50  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.22/0.50  SPASS derived 212 clauses, backtracked 94 clauses, performed 4 splits and kept 318 clauses.
% 0.22/0.50  SPASS allocated 97955 KBytes.
% 0.22/0.50  SPASS spent	0:00:00.14 on the problem.
% 0.22/0.50  		0:00:00.04 for the input.
% 0.22/0.50  		0:00:00.04 for the FLOTTER CNF translation.
% 0.22/0.50  		0:00:00.00 for inferences.
% 0.22/0.50  		0:00:00.00 for the backtracking.
% 0.22/0.50  		0:00:00.03 for the reduction.
% 0.22/0.50  
% 0.22/0.50  
% 0.22/0.50  Here is a proof with depth 2, length 31 :
% 0.22/0.50  % SZS output start Refutation
% See solution above
% 0.22/0.50  Formulae used in the proof : mSortsC_01 m__1837 m__1860 m__1870 m__2075 m__2287 mLERefl m_MulUnit m__ mLETotal
% 0.22/0.50  
%------------------------------------------------------------------------------