%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM468+2 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:30 EDT 2022

% Result   : Theorem 0.74s 1.00s
% Output   : Refutation 0.74s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   11 (   7 unt;   0 nHn;  11 RR)
%            Number of literals    :   22 (   0 equ;  15 neg)
%            Maximal clause size   :    4 (   2 avg)
%            Maximal term depth    :    4 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    9 (   9 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aNaturalNumber0(xl),
    file('NUM468+2.p',unknown),
    [] ).

cnf(11,axiom,
    aNaturalNumber0(sdtsldt0(xm,xl)),
    file('NUM468+2.p',unknown),
    [] ).

cnf(12,axiom,
    aNaturalNumber0(sdtsldt0(xn,xl)),
    file('NUM468+2.p',unknown),
    [] ).

cnf(19,axiom,
    equal(sdtasdt0(xl,sdtsldt0(xm,xl)),xm),
    file('NUM468+2.p',unknown),
    [] ).

cnf(20,axiom,
    equal(sdtasdt0(xl,sdtsldt0(xn,xl)),xn),
    file('NUM468+2.p',unknown),
    [] ).

cnf(35,axiom,
    ~ equal(sdtasdt0(xl,sdtpldt0(sdtsldt0(xm,xl),sdtsldt0(xn,xl))),sdtpldt0(xm,xn)),
    file('NUM468+2.p',unknown),
    [] ).

cnf(56,axiom,
    ( ~ aNaturalNumber0(u)
    | ~ aNaturalNumber0(v)
    | ~ aNaturalNumber0(w)
    | equal(sdtasdt0(w,sdtpldt0(v,u)),sdtpldt0(sdtasdt0(w,v),sdtasdt0(w,u))) ),
    file('NUM468+2.p',unknown),
    [] ).

cnf(4093,plain,
    ( ~ aNaturalNumber0(sdtsldt0(xn,xl))
    | ~ aNaturalNumber0(sdtsldt0(xm,xl))
    | ~ aNaturalNumber0(xl)
    | ~ equal(sdtpldt0(sdtasdt0(xl,sdtsldt0(xm,xl)),sdtasdt0(xl,sdtsldt0(xn,xl))),sdtpldt0(xm,xn)) ),
    inference(spl,[status(thm),theory(equality)],[56,35]),
    [iquote('0:SpL:56.3,35.0')] ).

cnf(4094,plain,
    ( ~ aNaturalNumber0(sdtsldt0(xn,xl))
    | ~ aNaturalNumber0(sdtsldt0(xm,xl))
    | ~ aNaturalNumber0(xl)
    | ~ equal(sdtpldt0(xm,xn),sdtpldt0(xm,xn)) ),
    inference(rew,[status(thm),theory(equality)],[19,4093,20]),
    [iquote('0:Rew:19.0,4093.3,20.0,4093.3')] ).

cnf(4095,plain,
    ( ~ aNaturalNumber0(sdtsldt0(xn,xl))
    | ~ aNaturalNumber0(sdtsldt0(xm,xl))
    | ~ aNaturalNumber0(xl) ),
    inference(obv,[status(thm),theory(equality)],[4094]),
    [iquote('0:Obv:4094.3')] ).

cnf(4096,plain,
    $false,
    inference(ssi,[status(thm)],[4095,3,11,12]),
    [iquote('0:SSi:4095.2,4095.1,4095.0,3.0,11.0,12.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : NUM468+2 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n014.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Wed Jul  6 08:05:37 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.74/1.00  
% 0.74/1.00  SPASS V 3.9 
% 0.74/1.00  SPASS beiseite: Proof found.
% 0.74/1.00  % SZS status Theorem
% 0.74/1.00  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.74/1.00  SPASS derived 2498 clauses, backtracked 618 clauses, performed 21 splits and kept 1595 clauses.
% 0.74/1.00  SPASS allocated 100451 KBytes.
% 0.74/1.00  SPASS spent	0:00:00.62 on the problem.
% 0.74/1.00  		0:00:00.04 for the input.
% 0.74/1.00  		0:00:00.04 for the FLOTTER CNF translation.
% 0.74/1.00  		0:00:00.03 for inferences.
% 0.74/1.00  		0:00:00.01 for the backtracking.
% 0.74/1.00  		0:00:00.46 for the reduction.
% 0.74/1.00  
% 0.74/1.00  
% 0.74/1.00  Here is a proof with depth 1, length 11 :
% 0.74/1.00  % SZS output start Refutation
% See solution above
% 0.74/1.00  Formulae used in the proof : m__1240 m__ mAMDistr
% 0.74/1.00  
%------------------------------------------------------------------------------