TSTP Solution File: NUM427+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : NUM427+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Mon Jul 18 14:26:04 EDT 2022

% Result   : Theorem 0.19s 0.53s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :   11
% Syntax   : Number of clauses     :   21 (  11 unt;   4 nHn;  21 RR)
%            Number of literals    :   51 (   0 equ;  29 neg)
%            Maximal clause size   :    6 (   2 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-3 aty)
%            Number of functors    :   11 (  11 usr;   8 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(3,axiom,
    aInteger0(xa),
    file('NUM427+1.p',unknown),
    [] ).

cnf(4,axiom,
    aInteger0(xb),
    file('NUM427+1.p',unknown),
    [] ).

cnf(5,axiom,
    aInteger0(xq),
    file('NUM427+1.p',unknown),
    [] ).

cnf(6,axiom,
    aInteger0(xn),
    file('NUM427+1.p',unknown),
    [] ).

cnf(8,axiom,
    ~ equal(xq,sz00),
    file('NUM427+1.p',unknown),
    [] ).

cnf(10,axiom,
    ~ sdteqdtlpzmzozddtrp0(xb,xa,xq),
    file('NUM427+1.p',unknown),
    [] ).

cnf(11,axiom,
    ( ~ aInteger0(u)
    | aInteger0(smndt0(u)) ),
    file('NUM427+1.p',unknown),
    [] ).

cnf(22,axiom,
    equal(sdtasdt0(xq,smndt0(xn)),sdtpldt0(xb,smndt0(xa))),
    file('NUM427+1.p',unknown),
    [] ).

cnf(24,axiom,
    ( ~ aInteger0(u)
    | ~ aInteger0(v)
    | aInteger0(sdtasdt0(v,u)) ),
    file('NUM427+1.p',unknown),
    [] ).

cnf(35,axiom,
    ( ~ aInteger0(u)
    | ~ aInteger0(v)
    | ~ aInteger0(w)
    | ~ equal(sdtasdt0(w,v),u)
    | aDivisorOf0(w,u)
    | equal(w,sz00) ),
    file('NUM427+1.p',unknown),
    [] ).

cnf(38,axiom,
    ( ~ aInteger0(u)
    | ~ aInteger0(v)
    | ~ aInteger0(w)
    | ~ aDivisorOf0(u,sdtpldt0(w,smndt0(v)))
    | equal(u,sz00)
    | sdteqdtlpzmzozddtrp0(w,v,u) ),
    file('NUM427+1.p',unknown),
    [] ).

cnf(40,plain,
    ( ~ aInteger0(xb)
    | ~ aInteger0(xa)
    | ~ aInteger0(xq)
    | ~ aDivisorOf0(xq,sdtpldt0(xb,smndt0(xa)))
    | equal(xq,sz00) ),
    inference(res,[status(thm),theory(equality)],[38,10]),
    [iquote('0:Res:38.4,10.0')] ).

cnf(41,plain,
    ~ aDivisorOf0(xq,sdtpldt0(xb,smndt0(xa))),
    inference(mrr,[status(thm)],[40,4,3,5,8]),
    [iquote('0:MRR:40.0,40.1,40.2,40.4,4.0,3.0,5.0,8.0')] ).

cnf(72,plain,
    ( ~ aInteger0(smndt0(xn))
    | ~ aInteger0(xq)
    | aInteger0(sdtpldt0(xb,smndt0(xa))) ),
    inference(spr,[status(thm),theory(equality)],[22,24]),
    [iquote('0:SpR:22.0,24.2')] ).

cnf(80,plain,
    aInteger0(sdtpldt0(xb,smndt0(xa))),
    inference(ssi,[status(thm)],[72,5,11,6]),
    [iquote('0:SSi:72.1,72.0,5.0,11.1,6.0')] ).

cnf(411,plain,
    ( ~ aInteger0(u)
    | ~ aInteger0(smndt0(xn))
    | ~ aInteger0(xq)
    | ~ equal(sdtpldt0(xb,smndt0(xa)),u)
    | aDivisorOf0(xq,u)
    | equal(xq,sz00) ),
    inference(spl,[status(thm),theory(equality)],[22,35]),
    [iquote('0:SpL:22.0,35.3')] ).

cnf(431,plain,
    ( ~ aInteger0(u)
    | ~ equal(sdtpldt0(xb,smndt0(xa)),u)
    | aDivisorOf0(xq,u)
    | equal(xq,sz00) ),
    inference(ssi,[status(thm)],[411,5,11,6]),
    [iquote('0:SSi:411.2,411.1,5.0,11.1,6.0')] ).

cnf(432,plain,
    ( ~ aInteger0(u)
    | ~ equal(sdtpldt0(xb,smndt0(xa)),u)
    | aDivisorOf0(xq,u) ),
    inference(mrr,[status(thm)],[431,8]),
    [iquote('0:MRR:431.3,8.0')] ).

cnf(863,plain,
    ( ~ aInteger0(sdtpldt0(xb,smndt0(xa)))
    | aDivisorOf0(xq,sdtpldt0(xb,smndt0(xa))) ),
    inference(eqr,[status(thm),theory(equality)],[432]),
    [iquote('0:EqR:432.1')] ).

cnf(865,plain,
    aDivisorOf0(xq,sdtpldt0(xb,smndt0(xa))),
    inference(ssi,[status(thm)],[863,80]),
    [iquote('0:SSi:863.0,80.0')] ).

cnf(866,plain,
    $false,
    inference(mrr,[status(thm)],[865,41]),
    [iquote('0:MRR:865.0,41.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : NUM427+1 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.13  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n012.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Wed Jul  6 13:28:30 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.19/0.53  
% 0.19/0.53  SPASS V 3.9 
% 0.19/0.53  SPASS beiseite: Proof found.
% 0.19/0.53  % SZS status Theorem
% 0.19/0.53  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.19/0.53  SPASS derived 458 clauses, backtracked 0 clauses, performed 1 splits and kept 194 clauses.
% 0.19/0.53  SPASS allocated 98521 KBytes.
% 0.19/0.53  SPASS spent	0:00:00.18 on the problem.
% 0.19/0.53  		0:00:00.04 for the input.
% 0.19/0.53  		0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.53  		0:00:00.01 for inferences.
% 0.19/0.53  		0:00:00.00 for the backtracking.
% 0.19/0.53  		0:00:00.07 for the reduction.
% 0.19/0.53  
% 0.19/0.53  
% 0.19/0.53  Here is a proof with depth 2, length 21 :
% 0.19/0.53  % SZS output start Refutation
% See solution above
% 0.19/0.53  Formulae used in the proof : m__704 m__747 m__ mIntNeg m__767 mIntMult mDivisor mEquMod
% 0.19/0.53  
%------------------------------------------------------------------------------