TSTP Solution File: MSC011+1 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : MSC011+1 : TPTP v8.1.2. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 09:27:00 EDT 2023

% Result   : Theorem 0.13s 0.37s
% Output   : Proof 0.13s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : MSC011+1 : TPTP v8.1.2. Released v3.2.0.
% 0.00/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.34  % Computer : n018.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Thu Aug 24 13:54:13 EDT 2023
% 0.13/0.34  % CPUTime  : 
% 0.13/0.37  Command-line arguments: --set-join --lhs-weight 1 --no-flatten-goal --complete-subsets --goal-heuristic
% 0.13/0.37  
% 0.13/0.37  % SZS status Theorem
% 0.13/0.37  
% 0.13/0.37  % SZS output start Proof
% 0.13/0.37  Take the following subset of the input axioms:
% 0.13/0.37    fof(d_cons, axiom, ![A2]: ((drunk(A2) & not_drunk(A2)) => goal)).
% 0.13/0.37    fof(goal_to_be_proved, conjecture, goal).
% 0.13/0.37    fof(neg_phi, axiom, ![A]: (drunk(A) & neg_psi)).
% 0.13/0.37    fof(neg_psi_ax, axiom, neg_psi => ?[A3]: not_drunk(A3)).
% 0.13/0.37  
% 0.13/0.37  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.13/0.37  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.13/0.37  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.13/0.37    fresh(y, y, x1...xn) = u
% 0.13/0.37    C => fresh(s, t, x1...xn) = v
% 0.13/0.37  where fresh is a fresh function symbol and x1..xn are the free
% 0.13/0.37  variables of u and v.
% 0.13/0.37  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.13/0.37  input problem has no model of domain size 1).
% 0.13/0.37  
% 0.13/0.37  The encoding turns the above axioms into the following unit equations and goals:
% 0.13/0.37  
% 0.13/0.37  Axiom 1 (neg_phi_1): neg_psi = true.
% 0.13/0.37  Axiom 2 (neg_phi): drunk(X) = true.
% 0.13/0.37  Axiom 3 (neg_psi_ax): fresh(X, X) = true.
% 0.13/0.37  Axiom 4 (neg_psi_ax): fresh(neg_psi, true) = not_drunk(a).
% 0.13/0.37  Axiom 5 (d_cons): fresh3(X, X) = true.
% 0.13/0.37  Axiom 6 (d_cons): fresh2(X, X, Y) = goal.
% 0.13/0.37  Axiom 7 (d_cons): fresh2(not_drunk(X), true, X) = fresh3(drunk(X), true).
% 0.13/0.37  
% 0.13/0.37  Goal 1 (goal_to_be_proved): goal = true.
% 0.13/0.37  Proof:
% 0.13/0.37    goal
% 0.13/0.37  = { by axiom 6 (d_cons) R->L }
% 0.13/0.37    fresh2(neg_psi, neg_psi, a)
% 0.13/0.37  = { by axiom 1 (neg_phi_1) }
% 0.13/0.37    fresh2(true, neg_psi, a)
% 0.13/0.37  = { by axiom 3 (neg_psi_ax) R->L }
% 0.13/0.37    fresh2(fresh(neg_psi, neg_psi), neg_psi, a)
% 0.13/0.37  = { by axiom 1 (neg_phi_1) }
% 0.13/0.37    fresh2(fresh(neg_psi, true), neg_psi, a)
% 0.13/0.37  = { by axiom 4 (neg_psi_ax) }
% 0.13/0.37    fresh2(not_drunk(a), neg_psi, a)
% 0.13/0.37  = { by axiom 1 (neg_phi_1) }
% 0.13/0.37    fresh2(not_drunk(a), true, a)
% 0.13/0.37  = { by axiom 7 (d_cons) }
% 0.13/0.37    fresh3(drunk(a), true)
% 0.13/0.37  = { by axiom 2 (neg_phi) }
% 0.13/0.37    fresh3(true, true)
% 0.13/0.37  = { by axiom 1 (neg_phi_1) R->L }
% 0.13/0.37    fresh3(neg_psi, true)
% 0.13/0.37  = { by axiom 1 (neg_phi_1) R->L }
% 0.13/0.37    fresh3(neg_psi, neg_psi)
% 0.13/0.37  = { by axiom 5 (d_cons) }
% 0.13/0.37    true
% 0.13/0.37  % SZS output end Proof
% 0.13/0.37  
% 0.13/0.37  RESULT: Theorem (the conjecture is true).
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