TSTP Solution File: MSC011+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : MSC011+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:06:19 EDT 2022

% Result   : Theorem 1.68s 1.89s
% Output   : Refutation 1.68s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    5
% Syntax   : Number of clauses     :    8 (   6 unt;   0 nHn;   7 RR)
%            Number of literals    :   11 (   0 equ;   4 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   3 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   1 con; 0-0 aty)
%            Number of variables   :    2 (   1 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ drunk(A)
    | ~ not_drunk(A)
    | goal ),
    file('MSC011+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ neg_psi
    | not_drunk(dollar_c1) ),
    file('MSC011+1.p',unknown),
    [] ).

cnf(3,axiom,
    ~ goal,
    file('MSC011+1.p',unknown),
    [] ).

cnf(4,axiom,
    drunk(A),
    file('MSC011+1.p',unknown),
    [] ).

cnf(5,axiom,
    neg_psi,
    file('MSC011+1.p',unknown),
    [] ).

cnf(6,plain,
    not_drunk(dollar_c1),
    inference(hyper,[status(thm)],[5,2]),
    [iquote('hyper,5,2')] ).

cnf(7,plain,
    goal,
    inference(hyper,[status(thm)],[6,1,4]),
    [iquote('hyper,6,1,4')] ).

cnf(8,plain,
    $false,
    inference(binary,[status(thm)],[7,3]),
    [iquote('binary,7.1,3.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : MSC011+1 : TPTP v8.1.0. Released v3.2.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n029.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 09:09:14 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.68/1.89  ----- Otter 3.3f, August 2004 -----
% 1.68/1.89  The process was started by sandbox2 on n029.cluster.edu,
% 1.68/1.89  Wed Jul 27 09:09:14 2022
% 1.68/1.89  The command was "./otter".  The process ID is 25499.
% 1.68/1.89  
% 1.68/1.89  set(prolog_style_variables).
% 1.68/1.89  set(auto).
% 1.68/1.89     dependent: set(auto1).
% 1.68/1.89     dependent: set(process_input).
% 1.68/1.89     dependent: clear(print_kept).
% 1.68/1.89     dependent: clear(print_new_demod).
% 1.68/1.89     dependent: clear(print_back_demod).
% 1.68/1.89     dependent: clear(print_back_sub).
% 1.68/1.89     dependent: set(control_memory).
% 1.68/1.89     dependent: assign(max_mem, 12000).
% 1.68/1.89     dependent: assign(pick_given_ratio, 4).
% 1.68/1.89     dependent: assign(stats_level, 1).
% 1.68/1.89     dependent: assign(max_seconds, 10800).
% 1.68/1.89  clear(print_given).
% 1.68/1.89  
% 1.68/1.89  formula_list(usable).
% 1.68/1.89  all A (drunk(A)¬_drunk(A)->goal).
% 1.68/1.89  all A (drunk(A)&neg_psi).
% 1.68/1.89  neg_psi-> (exists A not_drunk(A)).
% 1.68/1.89  -goal.
% 1.68/1.89  end_of_list.
% 1.68/1.89  
% 1.68/1.89  -------> usable clausifies to:
% 1.68/1.89  
% 1.68/1.89  list(usable).
% 1.68/1.89  0 [] -drunk(A)| -not_drunk(A)|goal.
% 1.68/1.89  0 [] drunk(A).
% 1.68/1.89  0 [] neg_psi.
% 1.68/1.89  0 [] -neg_psi|not_drunk($c1).
% 1.68/1.89  0 [] -goal.
% 1.68/1.89  end_of_list.
% 1.68/1.89  
% 1.68/1.89  SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=3.
% 1.68/1.89  
% 1.68/1.89  This is a Horn set without equality.  The strategy will
% 1.68/1.89  be hyperresolution, with satellites in sos and nuclei
% 1.68/1.89  in usable.
% 1.68/1.89  
% 1.68/1.89     dependent: set(hyper_res).
% 1.68/1.89     dependent: clear(order_hyper).
% 1.68/1.89  
% 1.68/1.89  ------------> process usable:
% 1.68/1.89  ** KEPT (pick-wt=5): 1 [] -drunk(A)| -not_drunk(A)|goal.
% 1.68/1.89  ** KEPT (pick-wt=3): 2 [] -neg_psi|not_drunk($c1).
% 1.68/1.89  ** KEPT (pick-wt=1): 3 [] -goal.
% 1.68/1.89  
% 1.68/1.89  ------------> process sos:
% 1.68/1.89  ** KEPT (pick-wt=2): 4 [] drunk(A).
% 1.68/1.89  ** KEPT (pick-wt=1): 5 [] neg_psi.
% 1.68/1.89  
% 1.68/1.89  ======= end of input processing =======
% 1.68/1.89  
% 1.68/1.89  =========== start of search ===========
% 1.68/1.89  
% 1.68/1.89  -------- PROOF -------- 
% 1.68/1.89  
% 1.68/1.89  ----> UNIT CONFLICT at   0.00 sec ----> 8 [binary,7.1,3.1] $F.
% 1.68/1.89  
% 1.68/1.89  Length of proof is 2.  Level of proof is 2.
% 1.68/1.89  
% 1.68/1.89  ---------------- PROOF ----------------
% 1.68/1.89  % SZS status Theorem
% 1.68/1.89  % SZS output start Refutation
% See solution above
% 1.68/1.89  ------------ end of proof -------------
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Search stopped by max_proofs option.
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Search stopped by max_proofs option.
% 1.68/1.89  
% 1.68/1.89  ============ end of search ============
% 1.68/1.89  
% 1.68/1.89  -------------- statistics -------------
% 1.68/1.89  clauses given                  3
% 1.68/1.89  clauses generated              2
% 1.68/1.89  clauses kept                   7
% 1.68/1.89  clauses forward subsumed       0
% 1.68/1.89  clauses back subsumed          1
% 1.68/1.89  Kbytes malloced              976
% 1.68/1.89  
% 1.68/1.89  ----------- times (seconds) -----------
% 1.68/1.89  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.68/1.89  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.68/1.89  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.68/1.89  
% 1.68/1.89  That finishes the proof of the theorem.
% 1.68/1.89  
% 1.68/1.89  Process 25499 finished Wed Jul 27 09:09:16 2022
% 1.68/1.89  Otter interrupted
% 1.68/1.89  PROOF FOUND
%------------------------------------------------------------------------------