TSTP Solution File: MGT037+2 by Crossbow---0.1

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Crossbow---0.1
% Problem  : MGT037+2 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : do_Crossbow---0.1 %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 21:58:25 EDT 2022

% Result   : CounterSatisfiable 5.24s 5.40s
% Output   : FiniteModel 5.24s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : MGT037+2 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.13  % Command    : do_Crossbow---0.1 %s
% 0.14/0.34  % Computer : n017.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 600
% 0.14/0.34  % DateTime   : Thu Jun  9 10:23:34 EDT 2022
% 0.14/0.35  % CPUTime    : 
% 0.14/0.35  /export/starexec/sandbox2/solver/bin
% 0.14/0.35  crossbow.opt
% 0.14/0.35  do_Crossbow---0.1
% 0.14/0.35  eprover
% 0.14/0.35  runsolver
% 0.14/0.35  starexec_run_Crossbow---0.1
% 5.24/5.40  % SZS status CounterSatisfiable for theBenchmark.p
% 5.24/5.40  % SZS output start FiniteModel for theBenchmark.p
% 5.24/5.40  % domain size: 3
% 5.24/5.40  fof(interp, fi_domain, ![X] : (X = 0 | X = 1 | X = 2)).
% 5.24/5.40  fof(interp, fi_functors, an_organisation = 1).
% 5.24/5.40  fof(interp, fi_functors, appear(0, 0) = 1 & appear(0, 1) = 1 & appear(0, 2) = 1 &
% 5.24/5.40    appear(1, 0) = 2 &
% 5.24/5.40    appear(1, 1) = 2 &
% 5.24/5.40    appear(1, 2) = 2 &
% 5.24/5.40    appear(2, 0) = 0 &
% 5.24/5.40    appear(2, 1) = 0 &
% 5.24/5.40    appear(2, 2) = 0).
% 5.24/5.40  fof(interp, fi_functors, cardinality_at_time(0, 0) = 0 &
% 5.24/5.40    cardinality_at_time(0, 1) = 1 &
% 5.24/5.40    cardinality_at_time(0, 2) = 0 &
% 5.24/5.40    cardinality_at_time(1, 0) = 0 &
% 5.24/5.40    cardinality_at_time(1, 1) = 2 &
% 5.24/5.40    cardinality_at_time(1, 2) = 0 &
% 5.24/5.40    cardinality_at_time(2, 0) = 1 &
% 5.24/5.40    cardinality_at_time(2, 1) = 2 &
% 5.24/5.40    cardinality_at_time(2, 2) = 0).
% 5.24/5.40  fof(interp, fi_predicates, ~constant(0) & ~constant(1) & ~constant(2)).
% 5.24/5.40  fof(interp, fi_predicates, decreases(0) & ~decreases(1) & decreases(2)).
% 5.24/5.40  fof(interp, fi_functors, efficient_producers = 0).
% 5.24/5.40  fof(interp, fi_predicates, environment(0) & environment(1) & environment(2)).
% 5.24/5.40  fof(interp, fi_functors, equilibrium(0) = 1 & equilibrium(1) = 1 &
% 5.24/5.40    equilibrium(2) = 1).
% 5.24/5.40  fof(interp, fi_functors, esk1_2(0, 0) = 1 & esk1_2(0, 1) = 1 & esk1_2(0, 2) = 0 &
% 5.24/5.40    esk1_2(1, 0) = 1 &
% 5.24/5.40    esk1_2(1, 1) = 1 &
% 5.24/5.40    esk1_2(1, 2) = 0 &
% 5.24/5.40    esk1_2(2, 0) = 1 &
% 5.24/5.40    esk1_2(2, 1) = 1 &
% 5.24/5.40    esk1_2(2, 2) = 0).
% 5.24/5.40  fof(interp, fi_functors, esk2_2(0, 0) = 2 & esk2_2(0, 1) = 2 & esk2_2(0, 2) = 0 &
% 5.24/5.40    esk2_2(1, 0) = 2 &
% 5.24/5.40    esk2_2(1, 1) = 2 &
% 5.24/5.40    esk2_2(1, 2) = 0 &
% 5.24/5.40    esk2_2(2, 0) = 2 &
% 5.24/5.40    esk2_2(2, 1) = 2 &
% 5.24/5.40    esk2_2(2, 2) = 0).
% 5.24/5.40  fof(interp, fi_functors, esk3_0 = 0).
% 5.24/5.40  fof(interp, fi_functors, esk4_0 = 0).
% 5.24/5.40  fof(interp, fi_functors, first_movers = 1).
% 5.24/5.40  fof(interp, fi_predicates, ~greater(0, 0) & greater(0, 1) & greater(0, 2) &
% 5.24/5.40    greater(1, 0) &
% 5.24/5.40    greater(1, 1) &
% 5.24/5.40    ~greater(1, 2) &
% 5.24/5.40    ~greater(2, 0) &
% 5.24/5.40    ~greater(2, 1) &
% 5.24/5.40    ~greater(2, 2)).
% 5.24/5.40  fof(interp, fi_predicates, ~greater_or_equal(0, 0) & greater_or_equal(0, 1) &
% 5.24/5.40    ~greater_or_equal(0, 2) &
% 5.24/5.40    ~greater_or_equal(1, 0) &
% 5.24/5.40    ~greater_or_equal(1, 1) &
% 5.24/5.40    ~greater_or_equal(1, 2) &
% 5.24/5.40    ~greater_or_equal(2, 0) &
% 5.24/5.40    ~greater_or_equal(2, 1) &
% 5.24/5.40    ~greater_or_equal(2, 2)).
% 5.24/5.40  fof(interp, fi_functors, growth_rate(0, 0) = 0 & growth_rate(0, 1) = 1 &
% 5.24/5.40    growth_rate(0, 2) = 0 &
% 5.24/5.40    growth_rate(1, 0) = 0 &
% 5.24/5.40    growth_rate(1, 1) = 2 &
% 5.24/5.40    growth_rate(1, 2) = 0 &
% 5.24/5.40    growth_rate(2, 0) = 0 &
% 5.24/5.40    growth_rate(2, 1) = 0 &
% 5.24/5.40    growth_rate(2, 2) = 0).
% 5.24/5.40  fof(interp, fi_predicates, in_environment(0, 0) & in_environment(0, 1) &
% 5.24/5.40    ~in_environment(0, 2) &
% 5.24/5.40    in_environment(1, 0) &
% 5.24/5.40    in_environment(1, 1) &
% 5.24/5.40    ~in_environment(1, 2) &
% 5.24/5.40    in_environment(2, 0) &
% 5.24/5.40    in_environment(2, 1) &
% 5.24/5.40    ~in_environment(2, 2)).
% 5.24/5.40  fof(interp, fi_functors, number_of_organizations(0, 0) = 0 &
% 5.24/5.40    number_of_organizations(0, 1) = 2 &
% 5.24/5.40    number_of_organizations(0, 2) = 0 &
% 5.24/5.40    number_of_organizations(1, 0) = 0 &
% 5.24/5.40    number_of_organizations(1, 1) = 2 &
% 5.24/5.40    number_of_organizations(1, 2) = 0 &
% 5.24/5.40    number_of_organizations(2, 0) = 0 &
% 5.24/5.40    number_of_organizations(2, 1) = 2 &
% 5.24/5.40    number_of_organizations(2, 2) = 0).
% 5.24/5.40  fof(interp, fi_functors, resilience(0) = 0 & resilience(1) = 2 &
% 5.24/5.40    resilience(2) = 0).
% 5.24/5.40  fof(interp, fi_functors, resources(0, 0) = 1 & resources(0, 1) = 1 &
% 5.24/5.40    resources(0, 2) = 0 &
% 5.24/5.40    resources(1, 0) = 1 &
% 5.24/5.40    resources(1, 1) = 1 &
% 5.24/5.40    resources(1, 2) = 0 &
% 5.24/5.40    resources(2, 0) = 1 &
% 5.24/5.40    resources(2, 1) = 1 &
% 5.24/5.40    resources(2, 2) = 0).
% 5.24/5.40  fof(interp, fi_predicates, subpopulation(0, 0, 0) & subpopulation(0, 0, 1) &
% 5.24/5.40    ~subpopulation(0, 0, 2) &
% 5.24/5.40    subpopulation(0, 1, 0) &
% 5.24/5.40    subpopulation(0, 1, 1) &
% 5.24/5.40    ~subpopulation(0, 1, 2) &
% 5.24/5.40    subpopulation(0, 2, 0) &
% 5.24/5.40    subpopulation(0, 2, 1) &
% 5.24/5.40    ~subpopulation(0, 2, 2) &
% 5.24/5.40    subpopulation(1, 0, 0) &
% 5.24/5.40    subpopulation(1, 0, 1) &
% 5.24/5.40    ~subpopulation(1, 0, 2) &
% 5.24/5.40    subpopulation(1, 1, 0) &
% 5.24/5.40    subpopulation(1, 1, 1) &
% 5.24/5.40    ~subpopulation(1, 1, 2) &
% 5.24/5.40    subpopulation(1, 2, 0) &
% 5.24/5.40    subpopulation(1, 2, 1) &
% 5.24/5.40    ~subpopulation(1, 2, 2) &
% 5.24/5.40    ~subpopulation(2, 0, 0) &
% 5.24/5.40    subpopulation(2, 0, 1) &
% 5.24/5.40    ~subpopulation(2, 0, 2) &
% 5.24/5.40    ~subpopulation(2, 1, 0) &
% 5.24/5.40    subpopulation(2, 1, 1) &
% 5.24/5.40    ~subpopulation(2, 1, 2) &
% 5.24/5.40    ~subpopulation(2, 2, 0) &
% 5.24/5.40    subpopulation(2, 2, 1) &
% 5.24/5.40    ~subpopulation(2, 2, 2)).
% 5.24/5.40  fof(interp, fi_functors, zero = 0).
% 5.24/5.40  % SZS output end FiniteModel for theBenchmark.p
% 5.24/5.40  % 0 lemma(s) from E
% 5.24/5.40  % 46 pred(s)
% 5.24/5.40  % 19 func(s)
% 5.24/5.40  % 3 sort(s)
% 5.24/5.40  % 70 clause(s)
% 5.24/5.40  % Instantiating 1 (5013 ms)
% 5.24/5.40  % Solving (5013 ms)
% 5.24/5.40  % Instantiating 2 (5013 ms)
% 5.24/5.40  % Solving (5014 ms)
% 5.24/5.40  % Instantiating 3 (5014 ms)
% 5.24/5.40  % Solving (5015 ms)
% 5.24/5.40  % 
% 5.24/5.40  % 1 model found (5017 ms)
%------------------------------------------------------------------------------