TSTP Solution File: LCL809_5 by Duper---1.0
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%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : LCL809_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n015.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 07:11:21 EDT 2023
% Result : Theorem 9.46s 9.70s
% Output : Proof 9.46s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : LCL809_5 : TPTP v8.1.2. Released v6.0.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n015.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Fri Aug 25 05:59:36 EDT 2023
% 0.13/0.34 % CPUTime :
% 9.46/9.70 SZS status Theorem for theBenchmark.p
% 9.46/9.70 SZS output start Proof for theBenchmark.p
% 9.46/9.70 Clause #3 (by assumption #[]): Eq (pp (aa dB bool it (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst b) u) i))) True
% 9.46/9.70 Clause #5 (by assumption #[]): Eq (∀ (I : nat) (T : dB), pp (aa dB bool it T) → pp (aa dB bool it (aa nat dB (aa dB (fun nat dB) lift T) I))) True
% 9.46/9.70 Clause #100 (by assumption #[]): Eq
% 9.46/9.70 (∀ (A C B : Type) (R : A) (Q : B) (P : fun A (fun B C)),
% 9.46/9.70 Eq (aa A C (combc A B C P Q) R) (aa B C (aa A (fun B C) P R) Q))
% 9.46/9.70 True
% 9.46/9.70 Clause #108 (by assumption #[]): Eq
% 9.46/9.70 (Not
% 9.46/9.70 (pp
% 9.46/9.70 (aa dB bool it
% 9.46/9.70 (aa nat dB (aa dB (fun nat dB) lift (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst b) u) i))
% 9.46/9.70 (zero_zero nat)))))
% 9.46/9.70 True
% 9.46/9.70 Clause #123 (by clausification #[5]): ∀ (a : nat), Eq (∀ (T : dB), pp (aa dB bool it T) → pp (aa dB bool it (aa nat dB (aa dB (fun nat dB) lift T) a))) True
% 9.46/9.70 Clause #124 (by clausification #[123]): ∀ (a : dB) (a_1 : nat), Eq (pp (aa dB bool it a) → pp (aa dB bool it (aa nat dB (aa dB (fun nat dB) lift a) a_1))) True
% 9.46/9.70 Clause #125 (by clausification #[124]): ∀ (a : dB) (a_1 : nat),
% 9.46/9.70 Or (Eq (pp (aa dB bool it a)) False) (Eq (pp (aa dB bool it (aa nat dB (aa dB (fun nat dB) lift a) a_1))) True)
% 9.46/9.70 Clause #129 (by superposition #[125, 3]): ∀ (a : nat),
% 9.46/9.70 Or
% 9.46/9.70 (Eq
% 9.46/9.70 (pp
% 9.46/9.70 (aa dB bool it
% 9.46/9.70 (aa nat dB
% 9.46/9.70 (aa dB (fun nat dB) lift (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst b) u) i)) a)))
% 9.46/9.70 True)
% 9.46/9.70 (Eq False True)
% 9.46/9.70 Clause #2031 (by clausification #[100]): ∀ (a : Type),
% 9.46/9.70 Eq
% 9.46/9.70 (∀ (C B : Type) (R : a) (Q : B) (P : fun a (fun B C)),
% 9.46/9.70 Eq (aa a C (combc a B C P Q) R) (aa B C (aa a (fun B C) P R) Q))
% 9.46/9.70 True
% 9.46/9.70 Clause #2032 (by clausification #[2031]): ∀ (a a_1 : Type),
% 9.46/9.70 Eq
% 9.46/9.70 (∀ (B : Type) (R : a) (Q : B) (P : fun a (fun B a_1)),
% 9.46/9.70 Eq (aa a a_1 (combc a B a_1 P Q) R) (aa B a_1 (aa a (fun B a_1) P R) Q))
% 9.46/9.70 True
% 9.46/9.70 Clause #2033 (by clausification #[2032]): ∀ (a a_1 a_2 : Type),
% 9.46/9.70 Eq
% 9.46/9.70 (∀ (R : a) (Q : a_1) (P : fun a (fun a_1 a_2)),
% 9.46/9.70 Eq (aa a a_2 (combc a a_1 a_2 P Q) R) (aa a_1 a_2 (aa a (fun a_1 a_2) P R) Q))
% 9.46/9.70 True
% 9.46/9.70 Clause #2034 (by clausification #[2033]): ∀ (a a_1 a_2 : Type) (a_3 : a_1),
% 9.46/9.70 Eq
% 9.46/9.70 (∀ (Q : a) (P : fun a_1 (fun a a_2)),
% 9.46/9.70 Eq (aa a_1 a_2 (combc a_1 a a_2 P Q) a_3) (aa a a_2 (aa a_1 (fun a a_2) P a_3) Q))
% 9.46/9.70 True
% 9.46/9.70 Clause #2035 (by clausification #[2034]): ∀ (a a_1 a_2 : Type) (a_3 : a_1) (a_4 : a),
% 9.46/9.70 Eq
% 9.46/9.70 (∀ (P : fun a (fun a_1 a_2)), Eq (aa a a_2 (combc a a_1 a_2 P a_3) a_4) (aa a_1 a_2 (aa a (fun a_1 a_2) P a_4) a_3))
% 9.46/9.70 True
% 9.46/9.70 Clause #2036 (by clausification #[2035]): ∀ (a a_1 a_2 : Type) (a_3 : fun a_1 (fun a_2 a)) (a_4 : a_2) (a_5 : a_1),
% 9.46/9.70 Eq (Eq (aa a_1 a (combc a_1 a_2 a a_3 a_4) a_5) (aa a_2 a (aa a_1 (fun a_2 a) a_3 a_5) a_4)) True
% 9.46/9.70 Clause #2037 (by clausification #[2036]): ∀ (a a_1 a_2 : Type) (a_3 : fun a_1 (fun a_2 a)) (a_4 : a_2) (a_5 : a_1),
% 9.46/9.70 Eq (aa a_1 a (combc a_1 a_2 a a_3 a_4) a_5) (aa a_2 a (aa a_1 (fun a_2 a) a_3 a_5) a_4)
% 9.46/9.70 Clause #2987 (by clausification #[108]): Eq
% 9.46/9.70 (pp
% 9.46/9.70 (aa dB bool it
% 9.46/9.70 (aa nat dB (aa dB (fun nat dB) lift (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst b) u) i))
% 9.46/9.70 (zero_zero nat))))
% 9.46/9.70 False
% 9.46/9.70 Clause #2988 (by forward demodulation #[2987, 2037]): Eq
% 9.46/9.70 (pp
% 9.46/9.70 (aa dB bool it
% 9.46/9.70 (aa dB dB (combc dB nat dB lift (zero_zero nat))
% 9.46/9.70 (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst b) u) i))))
% 9.46/9.70 False
% 9.46/9.70 Clause #2989 (by forward demodulation #[2988, 2037]): Eq
% 9.46/9.70 (pp
% 9.46/9.70 (aa dB bool it
% 9.46/9.70 (aa dB dB (combc dB nat dB lift (zero_zero nat))
% 9.46/9.70 (aa dB dB (combc dB nat dB (aa dB (fun dB (fun nat dB)) subst b) i) u))))
% 9.46/9.70 False
% 9.46/9.70 Clause #3192 (by clausification #[129]): ∀ (a : nat),
% 9.46/9.70 Eq
% 9.46/9.70 (pp
% 9.46/9.70 (aa dB bool it
% 9.46/9.70 (aa nat dB (aa dB (fun nat dB) lift (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst b) u) i))
% 9.46/9.70 a)))
% 9.46/9.70 True
% 9.46/9.70 Clause #3193 (by forward demodulation #[3192, 2037]): ∀ (a : nat),
% 9.46/9.70 Eq
% 9.46/9.70 (pp
% 9.46/9.70 (aa dB bool it
% 9.46/9.70 (aa dB dB (combc dB nat dB lift a) (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst b) u) i))))
% 9.46/9.71 True
% 9.46/9.71 Clause #3194 (by forward demodulation #[3193, 2037]): ∀ (a : nat),
% 9.46/9.71 Eq
% 9.46/9.71 (pp
% 9.46/9.71 (aa dB bool it
% 9.46/9.71 (aa dB dB (combc dB nat dB lift a) (aa dB dB (combc dB nat dB (aa dB (fun dB (fun nat dB)) subst b) i) u))))
% 9.46/9.71 True
% 9.46/9.71 Clause #3199 (by superposition #[3194, 2989]): Eq True False
% 9.46/9.71 Clause #3245 (by clausification #[3199]): False
% 9.46/9.71 SZS output end Proof for theBenchmark.p
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