TSTP Solution File: LCL807-1 by Twee---2.4.2
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : LCL807-1 : TPTP v8.1.2. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 08:20:45 EDT 2023
% Result : Unsatisfiable 5.48s 1.09s
% Output : Proof 5.48s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : LCL807-1 : TPTP v8.1.2. Released v4.1.0.
% 0.00/0.13 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.34 % Computer : n020.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Fri Aug 25 05:17:00 EDT 2023
% 0.13/0.34 % CPUTime :
% 5.48/1.09 Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10
% 5.48/1.09
% 5.48/1.09 % SZS status Unsatisfiable
% 5.48/1.09
% 5.48/1.09 % SZS output start Proof
% 5.48/1.09 Take the following subset of the input axioms:
% 5.48/1.09 fof(cls_Cons_Ohyps_I1_J_1, axiom, hBOOL(hAPP(hAPP(hAPP(c_Type_Otyping, hAPP(hAPP(hAPP(c_Type_Oshift(tc_Type_Otype), v_e____), v_i____), v_T____)), v_b____), v_sko__local__XCons__Xhyps__1__1(v_T____, v_b____, v_e____, v_i____)))).
% 5.48/1.09 fof(cls_conjecture_0, negated_conjecture, ~v_thesis____).
% 5.48/1.09 fof(cls_conjecture_1, negated_conjecture, ![V_x]: (v_thesis____ | ~hBOOL(hAPP(hAPP(hAPP(c_Type_Otyping, hAPP(hAPP(hAPP(c_Type_Oshift(tc_Type_Otype), v_e____), v_i____), v_T____)), v_b____), V_x)))).
% 5.48/1.09
% 5.48/1.09 Now clausify the problem and encode Horn clauses using encoding 3 of
% 5.48/1.09 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 5.48/1.09 We repeatedly replace C & s=t => u=v by the two clauses:
% 5.48/1.09 fresh(y, y, x1...xn) = u
% 5.48/1.09 C => fresh(s, t, x1...xn) = v
% 5.48/1.09 where fresh is a fresh function symbol and x1..xn are the free
% 5.48/1.09 variables of u and v.
% 5.48/1.09 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 5.48/1.09 input problem has no model of domain size 1).
% 5.48/1.09
% 5.48/1.09 The encoding turns the above axioms into the following unit equations and goals:
% 5.48/1.09
% 5.48/1.09 Axiom 1 (cls_conjecture_1): fresh128(X, X) = true2.
% 5.48/1.09 Axiom 2 (cls_conjecture_1): fresh128(hBOOL(hAPP(hAPP(hAPP(c_Type_Otyping, hAPP(hAPP(hAPP(c_Type_Oshift(tc_Type_Otype), v_e____), v_i____), v_T____)), v_b____), X)), true2) = v_thesis____.
% 5.48/1.09 Axiom 3 (cls_Cons_Ohyps_I1_J_1): hBOOL(hAPP(hAPP(hAPP(c_Type_Otyping, hAPP(hAPP(hAPP(c_Type_Oshift(tc_Type_Otype), v_e____), v_i____), v_T____)), v_b____), v_sko__local__XCons__Xhyps__1__1(v_T____, v_b____, v_e____, v_i____))) = true2.
% 5.48/1.09
% 5.48/1.09 Goal 1 (cls_conjecture_0): v_thesis____ = true2.
% 5.48/1.09 Proof:
% 5.48/1.09 v_thesis____
% 5.48/1.09 = { by axiom 2 (cls_conjecture_1) R->L }
% 5.48/1.09 fresh128(hBOOL(hAPP(hAPP(hAPP(c_Type_Otyping, hAPP(hAPP(hAPP(c_Type_Oshift(tc_Type_Otype), v_e____), v_i____), v_T____)), v_b____), v_sko__local__XCons__Xhyps__1__1(v_T____, v_b____, v_e____, v_i____))), true2)
% 5.48/1.09 = { by axiom 3 (cls_Cons_Ohyps_I1_J_1) }
% 5.48/1.09 fresh128(true2, true2)
% 5.48/1.09 = { by axiom 1 (cls_conjecture_1) }
% 5.48/1.09 true2
% 5.48/1.09 % SZS output end Proof
% 5.48/1.09
% 5.48/1.09 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------