TSTP Solution File: LCL762_5 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : LCL762_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 07:11:07 EDT 2023

% Result   : Theorem 3.83s 4.02s
% Output   : Proof 3.83s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : LCL762_5 : TPTP v8.1.2. Released v6.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n025.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.20/0.35  % CPULimit   : 300
% 0.20/0.35  % WCLimit    : 300
% 0.20/0.35  % DateTime   : Thu Aug 24 17:22:06 EDT 2023
% 0.20/0.36  % CPUTime    : 
% 3.83/4.02  SZS status Theorem for theBenchmark.p
% 3.83/4.02  SZS output start Proof for theBenchmark.p
% 3.83/4.02  Clause #0 (by assumption #[]): Eq
% 3.83/4.02    (∀ (Ss1 : list dB) (S : dB) (M : nat),
% 3.83/4.02      Iff (Eq (var M) (foldl dB dB app S Ss1)) (And (Eq (var M) S) (Eq Ss1 (nil dB))))
% 3.83/4.02    True
% 3.83/4.02  Clause #104 (by assumption #[]): Eq (pp (aa dB bool it (foldl dB dB app (var n) (nil dB)))) True
% 3.83/4.02  Clause #105 (by assumption #[]): Eq (Not (pp (aa dB bool it (var n)))) True
% 3.83/4.02  Clause #112 (by clausification #[0]): ∀ (a : list dB),
% 3.83/4.02    Eq (∀ (S : dB) (M : nat), Iff (Eq (var M) (foldl dB dB app S a)) (And (Eq (var M) S) (Eq a (nil dB)))) True
% 3.83/4.02  Clause #113 (by clausification #[112]): ∀ (a : dB) (a_1 : list dB),
% 3.83/4.02    Eq (∀ (M : nat), Iff (Eq (var M) (foldl dB dB app a a_1)) (And (Eq (var M) a) (Eq a_1 (nil dB)))) True
% 3.83/4.02  Clause #114 (by clausification #[113]): ∀ (a : nat) (a_1 : dB) (a_2 : list dB),
% 3.83/4.02    Eq (Iff (Eq (var a) (foldl dB dB app a_1 a_2)) (And (Eq (var a) a_1) (Eq a_2 (nil dB)))) True
% 3.83/4.02  Clause #115 (by clausification #[114]): ∀ (a : nat) (a_1 : dB) (a_2 : list dB),
% 3.83/4.02    Or (Eq (Eq (var a) (foldl dB dB app a_1 a_2)) True) (Eq (And (Eq (var a) a_1) (Eq a_2 (nil dB))) False)
% 3.83/4.02  Clause #117 (by clausification #[115]): ∀ (a : nat) (a_1 : dB) (a_2 : list dB),
% 3.83/4.02    Or (Eq (And (Eq (var a) a_1) (Eq a_2 (nil dB))) False) (Eq (var a) (foldl dB dB app a_1 a_2))
% 3.83/4.02  Clause #118 (by clausification #[117]): ∀ (a : nat) (a_1 : dB) (a_2 : list dB),
% 3.83/4.02    Or (Eq (var a) (foldl dB dB app a_1 a_2)) (Or (Eq (Eq (var a) a_1) False) (Eq (Eq a_2 (nil dB)) False))
% 3.83/4.02  Clause #119 (by clausification #[118]): ∀ (a : nat) (a_1 : dB) (a_2 : list dB),
% 3.83/4.02    Or (Eq (var a) (foldl dB dB app a_1 a_2)) (Or (Eq (Eq a_2 (nil dB)) False) (Ne (var a) a_1))
% 3.83/4.02  Clause #120 (by clausification #[119]): ∀ (a : nat) (a_1 : dB) (a_2 : list dB),
% 3.83/4.02    Or (Eq (var a) (foldl dB dB app a_1 a_2)) (Or (Ne (var a) a_1) (Ne a_2 (nil dB)))
% 3.83/4.02  Clause #121 (by destructive equality resolution #[120]): ∀ (a : nat) (a_1 : list dB), Or (Eq (var a) (foldl dB dB app (var a) a_1)) (Ne a_1 (nil dB))
% 3.83/4.02  Clause #122 (by destructive equality resolution #[121]): ∀ (a : nat), Eq (var a) (foldl dB dB app (var a) (nil dB))
% 3.83/4.02  Clause #123 (by clausification #[105]): Eq (pp (aa dB bool it (var n))) False
% 3.83/4.02  Clause #249 (by forward demodulation #[104, 122]): Eq (pp (aa dB bool it (var n))) True
% 3.83/4.02  Clause #250 (by superposition #[249, 123]): Eq True False
% 3.83/4.02  Clause #252 (by clausification #[250]): False
% 3.83/4.02  SZS output end Proof for theBenchmark.p
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