TSTP Solution File: LCL670+1.001 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : LCL670+1.001 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 14:38:54 EDT 2022
% Result : Theorem 0.55s 0.75s
% Output : Refutation 0.55s
% Verified :
% SZS Type : Refutation
% Derivation depth : 9
% Number of leaves : 13
% Syntax : Number of clauses : 33 ( 13 unt; 0 nHn; 33 RR)
% Number of literals : 84 ( 0 equ; 57 neg)
% Maximal clause size : 7 ( 2 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-2 aty)
% Number of functors : 11 ( 11 usr; 6 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
r1(skc5,skc14),
file('LCL670+1.001.p',unknown),
[] ).
cnf(6,axiom,
r1(u,u),
file('LCL670+1.001.p',unknown),
[] ).
cnf(8,axiom,
r1(u,skf17(u)),
file('LCL670+1.001.p',unknown),
[] ).
cnf(10,axiom,
r1(u,skf15(u)),
file('LCL670+1.001.p',unknown),
[] ).
cnf(12,axiom,
r1(u,skf13(u)),
file('LCL670+1.001.p',unknown),
[] ).
cnf(13,axiom,
r1(u,skf12(u)),
file('LCL670+1.001.p',unknown),
[] ).
cnf(14,axiom,
r1(u,skf10(u)),
file('LCL670+1.001.p',unknown),
[] ).
cnf(19,axiom,
( ~ p2(skf15(u))
| ~ r1(skc14,u) ),
file('LCL670+1.001.p',unknown),
[] ).
cnf(20,axiom,
( ~ skP1(u)
| ~ r1(u,v)
| p2(v) ),
file('LCL670+1.001.p',unknown),
[] ).
cnf(21,axiom,
( ~ r1(u,v)
| ~ r1(skc5,u)
| p2(skf10(v)) ),
file('LCL670+1.001.p',unknown),
[] ).
cnf(24,axiom,
( ~ p2(u)
| ~ r1(skc5,v)
| ~ r1(skf13(v),u)
| skP0(v) ),
file('LCL670+1.001.p',unknown),
[] ).
cnf(25,axiom,
( ~ skP0(u)
| ~ r1(v,w)
| ~ r1(u,v)
| p2(skf17(w)) ),
file('LCL670+1.001.p',unknown),
[] ).
cnf(29,axiom,
( ~ p2(u)
| ~ p2(v)
| ~ r1(w,v)
| ~ r1(v,x)
| ~ r1(skc5,w)
| ~ r1(skf12(x),u)
| skP1(v) ),
file('LCL670+1.001.p',unknown),
[] ).
cnf(67,plain,
( ~ skP1(u)
| p2(skf15(u)) ),
inference(res,[status(thm),theory(equality)],[10,20]),
[iquote('0:Res:10.0,20.1')] ).
cnf(95,plain,
( ~ r1(skc5,u)
| p2(skf10(skf13(u))) ),
inference(res,[status(thm),theory(equality)],[12,21]),
[iquote('0:Res:12.0,21.0')] ).
cnf(108,plain,
( ~ p2(skf10(skf13(u)))
| ~ r1(skc5,u)
| skP0(u) ),
inference(res,[status(thm),theory(equality)],[14,24]),
[iquote('0:Res:14.0,24.2')] ).
cnf(116,plain,
( ~ r1(skc5,u)
| skP0(u) ),
inference(mrr,[status(thm)],[108,95]),
[iquote('0:MRR:108.0,95.1')] ).
cnf(119,plain,
( ~ skP0(u)
| ~ r1(u,skc5)
| p2(skf17(skc14)) ),
inference(res,[status(thm),theory(equality)],[1,25]),
[iquote('0:Res:1.0,25.1')] ).
cnf(124,plain,
( ~ skP0(u)
| ~ r1(u,v)
| p2(skf17(skf12(v))) ),
inference(res,[status(thm),theory(equality)],[13,25]),
[iquote('0:Res:13.0,25.1')] ).
cnf(133,plain,
( ~ skP1(u)
| ~ r1(skc14,u) ),
inference(res,[status(thm),theory(equality)],[67,19]),
[iquote('0:Res:67.1,19.0')] ).
cnf(135,plain,
skP0(skc14),
inference(res,[status(thm),theory(equality)],[1,116]),
[iquote('0:Res:1.0,116.0')] ).
cnf(136,plain,
skP0(skc5),
inference(res,[status(thm),theory(equality)],[6,116]),
[iquote('0:Res:6.0,116.0')] ).
cnf(169,plain,
( ~ p2(skf17(skf12(u)))
| ~ p2(v)
| ~ r1(w,v)
| ~ r1(v,u)
| ~ r1(skc5,w)
| skP1(v) ),
inference(res,[status(thm),theory(equality)],[8,29]),
[iquote('0:Res:8.0,29.5')] ).
cnf(178,plain,
~ skP1(skf17(skc14)),
inference(res,[status(thm),theory(equality)],[8,133]),
[iquote('0:Res:8.0,133.1')] ).
cnf(182,plain,
( ~ skP0(skc5)
| p2(skf17(skc14)) ),
inference(res,[status(thm),theory(equality)],[6,119]),
[iquote('0:Res:6.0,119.1')] ).
cnf(183,plain,
p2(skf17(skc14)),
inference(ssi,[status(thm)],[182,136]),
[iquote('0:SSi:182.0,136.0')] ).
cnf(410,plain,
( ~ p2(u)
| ~ skP0(v)
| ~ r1(w,u)
| ~ r1(u,x)
| ~ r1(skc5,w)
| ~ r1(v,x)
| skP1(u) ),
inference(sor,[status(thm)],[169,124]),
[iquote('0:SoR:169.0,124.2')] ).
cnf(626,plain,
( ~ p2(skf17(u))
| ~ skP0(v)
| ~ r1(skf17(u),w)
| ~ r1(skc5,u)
| ~ r1(v,w)
| skP1(skf17(u)) ),
inference(res,[status(thm),theory(equality)],[8,410]),
[iquote('0:Res:8.0,410.2')] ).
cnf(1668,plain,
( ~ skP0(u)
| ~ r1(skf17(skc14),v)
| ~ r1(skc5,skc14)
| ~ r1(u,v)
| skP1(skf17(skc14)) ),
inference(sor,[status(thm)],[626,183]),
[iquote('0:SoR:626.0,183.0')] ).
cnf(1674,plain,
( ~ skP0(u)
| ~ r1(skf17(skc14),v)
| ~ r1(u,v) ),
inference(mrr,[status(thm)],[1668,1,178]),
[iquote('0:MRR:1668.2,1668.4,1.0,178.0')] ).
cnf(1677,plain,
( ~ skP0(u)
| ~ r1(u,skf17(skc14)) ),
inference(res,[status(thm),theory(equality)],[6,1674]),
[iquote('0:Res:6.0,1674.1')] ).
cnf(1688,plain,
~ skP0(skc14),
inference(res,[status(thm),theory(equality)],[8,1677]),
[iquote('0:Res:8.0,1677.1')] ).
cnf(1689,plain,
$false,
inference(ssi,[status(thm)],[1688,135]),
[iquote('0:SSi:1688.0,135.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11 % Problem : LCL670+1.001 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.12 % Command : run_spass %d %s
% 0.11/0.33 % Computer : n018.cluster.edu
% 0.11/0.33 % Model : x86_64 x86_64
% 0.11/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33 % Memory : 8042.1875MB
% 0.11/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33 % CPULimit : 300
% 0.11/0.33 % WCLimit : 600
% 0.11/0.33 % DateTime : Mon Jul 4 00:41:35 EDT 2022
% 0.11/0.33 % CPUTime :
% 0.55/0.75
% 0.55/0.75 SPASS V 3.9
% 0.55/0.75 SPASS beiseite: Proof found.
% 0.55/0.75 % SZS status Theorem
% 0.55/0.75 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.55/0.75 SPASS derived 1544 clauses, backtracked 0 clauses, performed 0 splits and kept 932 clauses.
% 0.55/0.75 SPASS allocated 99474 KBytes.
% 0.55/0.75 SPASS spent 0:00:00.40 on the problem.
% 0.55/0.75 0:00:00.04 for the input.
% 0.55/0.75 0:00:00.03 for the FLOTTER CNF translation.
% 0.55/0.75 0:00:00.03 for inferences.
% 0.55/0.75 0:00:00.00 for the backtracking.
% 0.55/0.75 0:00:00.26 for the reduction.
% 0.55/0.75
% 0.55/0.75
% 0.55/0.75 Here is a proof with depth 6, length 33 :
% 0.55/0.75 % SZS output start Refutation
% See solution above
% 0.55/0.75 Formulae used in the proof : main reflexivity
% 0.55/0.75
%------------------------------------------------------------------------------