TSTP Solution File: LCL230+1 by Duper---1.0
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% File : Duper---1.0
% Problem : LCL230+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n024.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 07:09:08 EDT 2023
% Result : Theorem 5.49s 5.69s
% Output : Proof 5.49s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : LCL230+1 : TPTP v8.1.2. Released v2.0.0.
% 0.13/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n024.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Fri Aug 25 02:40:24 EDT 2023
% 0.14/0.35 % CPUTime :
% 5.49/5.69 SZS status Theorem for theBenchmark.p
% 5.49/5.69 SZS output start Proof for theBenchmark.p
% 5.49/5.69 Clause #0 (by assumption #[]): Eq (Not ((Or p q → Or p r) → Or p (q → r))) True
% 5.49/5.69 Clause #1 (by clausification #[0]): Eq ((Or p q → Or p r) → Or p (q → r)) False
% 5.49/5.69 Clause #2 (by clausification #[1]): Eq (Or p q → Or p r) True
% 5.49/5.69 Clause #3 (by clausification #[1]): Eq (Or p (q → r)) False
% 5.49/5.69 Clause #4 (by clausification #[2]): Or (Eq (Or p q) False) (Eq (Or p r) True)
% 5.49/5.69 Clause #5 (by clausification #[4]): Or (Eq (Or p r) True) (Eq q False)
% 5.49/5.69 Clause #7 (by clausification #[5]): Or (Eq q False) (Or (Eq p True) (Eq r True))
% 5.49/5.69 Clause #8 (by clausification #[3]): Eq (q → r) False
% 5.49/5.69 Clause #9 (by clausification #[3]): Eq p False
% 5.49/5.69 Clause #10 (by clausification #[8]): Eq q True
% 5.49/5.69 Clause #11 (by clausification #[8]): Eq r False
% 5.49/5.69 Clause #12 (by backward demodulation #[10, 7]): Or (Eq True False) (Or (Eq p True) (Eq r True))
% 5.49/5.69 Clause #14 (by clausification #[12]): Or (Eq p True) (Eq r True)
% 5.49/5.69 Clause #15 (by forward demodulation #[14, 9]): Or (Eq False True) (Eq r True)
% 5.49/5.69 Clause #16 (by clausification #[15]): Eq r True
% 5.49/5.69 Clause #17 (by superposition #[16, 11]): Eq True False
% 5.49/5.69 Clause #18 (by clausification #[17]): False
% 5.49/5.69 SZS output end Proof for theBenchmark.p
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