TSTP Solution File: LCL230+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : LCL230+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 07:09:08 EDT 2023

% Result   : Theorem 5.49s 5.69s
% Output   : Proof 5.49s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : LCL230+1 : TPTP v8.1.2. Released v2.0.0.
% 0.13/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n024.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Aug 25 02:40:24 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 5.49/5.69  SZS status Theorem for theBenchmark.p
% 5.49/5.69  SZS output start Proof for theBenchmark.p
% 5.49/5.69  Clause #0 (by assumption #[]): Eq (Not ((Or p q → Or p r) → Or p (q → r))) True
% 5.49/5.69  Clause #1 (by clausification #[0]): Eq ((Or p q → Or p r) → Or p (q → r)) False
% 5.49/5.69  Clause #2 (by clausification #[1]): Eq (Or p q → Or p r) True
% 5.49/5.69  Clause #3 (by clausification #[1]): Eq (Or p (q → r)) False
% 5.49/5.69  Clause #4 (by clausification #[2]): Or (Eq (Or p q) False) (Eq (Or p r) True)
% 5.49/5.69  Clause #5 (by clausification #[4]): Or (Eq (Or p r) True) (Eq q False)
% 5.49/5.69  Clause #7 (by clausification #[5]): Or (Eq q False) (Or (Eq p True) (Eq r True))
% 5.49/5.69  Clause #8 (by clausification #[3]): Eq (q → r) False
% 5.49/5.69  Clause #9 (by clausification #[3]): Eq p False
% 5.49/5.69  Clause #10 (by clausification #[8]): Eq q True
% 5.49/5.69  Clause #11 (by clausification #[8]): Eq r False
% 5.49/5.69  Clause #12 (by backward demodulation #[10, 7]): Or (Eq True False) (Or (Eq p True) (Eq r True))
% 5.49/5.69  Clause #14 (by clausification #[12]): Or (Eq p True) (Eq r True)
% 5.49/5.69  Clause #15 (by forward demodulation #[14, 9]): Or (Eq False True) (Eq r True)
% 5.49/5.69  Clause #16 (by clausification #[15]): Eq r True
% 5.49/5.69  Clause #17 (by superposition #[16, 11]): Eq True False
% 5.49/5.69  Clause #18 (by clausification #[17]): False
% 5.49/5.69  SZS output end Proof for theBenchmark.p
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