TSTP Solution File: KRS259+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : KRS259+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 03:31:00 EDT 2022

% Result   : Theorem 1.61s 1.80s
% Output   : Refutation 1.61s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   12 (   7 unt;   0 nHn;  12 RR)
%            Number of literals    :   19 (   0 equ;  10 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :   11 (  11 usr;   9 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    model(u,skc57),
    file('KRS259+1.p',unknown),
    [] ).

cnf(8,axiom,
    model(skc75,skc72),
    file('KRS259+1.p',unknown),
    [] ).

cnf(9,axiom,
    ~ mighta(tac,thm),
    file('KRS259+1.p',unknown),
    [] ).

cnf(50,axiom,
    ( ~ model(skf61(u,v),u)
    | status__dfg(w,u,thm) ),
    file('KRS259+1.p',unknown),
    [] ).

cnf(89,axiom,
    ( ~ model(u,v)
    | ~ model(skf64(w),w)
    | status__dfg(v,w,tac) ),
    file('KRS259+1.p',unknown),
    [] ).

cnf(92,axiom,
    ( ~ status__dfg(u,v,w)
    | ~ status__dfg(u,v,x)
    | mighta(x,w) ),
    file('KRS259+1.p',unknown),
    [] ).

cnf(112,plain,
    ( ~ status__dfg(u,v,thm)
    | ~ status__dfg(u,v,tac) ),
    inference(res,[status(thm),theory(equality)],[92,9]),
    [iquote('0:Res:92.2,9.0')] ).

cnf(334,plain,
    status__dfg(u,skc57,thm),
    inference(res,[status(thm),theory(equality)],[1,50]),
    [iquote('0:Res:1.0,50.0')] ).

cnf(1593,plain,
    ( ~ model(u,v)
    | status__dfg(v,skc57,tac) ),
    inference(res,[status(thm),theory(equality)],[1,89]),
    [iquote('0:Res:1.0,89.1')] ).

cnf(6830,plain,
    status__dfg(skc72,skc57,tac),
    inference(res,[status(thm),theory(equality)],[8,1593]),
    [iquote('0:Res:8.0,1593.0')] ).

cnf(7499,plain,
    ~ status__dfg(skc72,skc57,thm),
    inference(res,[status(thm),theory(equality)],[6830,112]),
    [iquote('0:Res:6830.0,112.1')] ).

cnf(7507,plain,
    $false,
    inference(mrr,[status(thm)],[7499,334]),
    [iquote('0:MRR:7499.0,334.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13  % Problem  : KRS259+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% 0.03/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n023.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Tue Jun  7 15:20:23 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 1.61/1.80  
% 1.61/1.80  SPASS V 3.9 
% 1.61/1.80  SPASS beiseite: Proof found.
% 1.61/1.80  % SZS status Theorem
% 1.61/1.80  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 1.61/1.80  SPASS derived 7256 clauses, backtracked 48 clauses, performed 31 splits and kept 3739 clauses.
% 1.61/1.80  SPASS allocated 89518 KBytes.
% 1.61/1.80  SPASS spent	0:00:01.41 on the problem.
% 1.61/1.80  		0:00:00.04 for the input.
% 1.61/1.80  		0:00:00.20 for the FLOTTER CNF translation.
% 1.61/1.80  		0:00:00.04 for inferences.
% 1.61/1.80  		0:00:00.01 for the backtracking.
% 1.61/1.80  		0:00:01.07 for the reduction.
% 1.61/1.80  
% 1.61/1.80  
% 1.61/1.80  Here is a proof with depth 3, length 12 :
% 1.61/1.80  % SZS output start Refutation
% See solution above
% 1.61/1.80  Formulae used in the proof : tautology non_thm_spt mighta_tac_thm thm tac mighta
% 1.61/1.80  
%------------------------------------------------------------------------------