TSTP Solution File: KRS258+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : KRS258+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 03:30:59 EDT 2022

% Result   : Theorem 2.11s 2.28s
% Output   : Refutation 2.11s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   13 (   6 unt;   2 nHn;  13 RR)
%            Number of literals    :   22 (   0 equ;  10 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :    9 (   9 usr;   7 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    model(u,skc57),
    file('KRS258+1.p',unknown),
    [] ).

cnf(9,axiom,
    ~ mighta(eqv,thm),
    file('KRS258+1.p',unknown),
    [] ).

cnf(32,axiom,
    ( model(skf61(u,v),v)
    | status__dfg(v,u,thm) ),
    file('KRS258+1.p',unknown),
    [] ).

cnf(50,axiom,
    ( ~ model(skf61(u,v),u)
    | status__dfg(w,u,thm) ),
    file('KRS258+1.p',unknown),
    [] ).

cnf(92,axiom,
    ( ~ status__dfg(u,v,w)
    | ~ status__dfg(u,v,x)
    | mighta(x,w) ),
    file('KRS258+1.p',unknown),
    [] ).

cnf(100,axiom,
    ( ~ model(skf62(u,v),u)
    | ~ model(skf62(u,v),v)
    | status__dfg(v,u,eqv) ),
    file('KRS258+1.p',unknown),
    [] ).

cnf(112,plain,
    ( ~ status__dfg(u,v,thm)
    | ~ status__dfg(u,v,eqv) ),
    inference(res,[status(thm),theory(equality)],[92,9]),
    [iquote('0:Res:92.2,9.0')] ).

cnf(341,plain,
    ( status__dfg(u,u,thm)
    | status__dfg(v,u,thm) ),
    inference(res,[status(thm),theory(equality)],[32,50]),
    [iquote('0:Res:32.0,50.0')] ).

cnf(342,plain,
    status__dfg(u,u,thm),
    inference(con,[status(thm)],[341]),
    [iquote('0:Con:341.1')] ).

cnf(3305,plain,
    ( ~ model(skf62(skc57,u),u)
    | status__dfg(u,skc57,eqv) ),
    inference(res,[status(thm),theory(equality)],[1,100]),
    [iquote('0:Res:1.0,100.0')] ).

cnf(10659,plain,
    status__dfg(skc57,skc57,eqv),
    inference(res,[status(thm),theory(equality)],[1,3305]),
    [iquote('0:Res:1.0,3305.0')] ).

cnf(10698,plain,
    ~ status__dfg(skc57,skc57,thm),
    inference(res,[status(thm),theory(equality)],[10659,112]),
    [iquote('0:Res:10659.0,112.1')] ).

cnf(10707,plain,
    $false,
    inference(mrr,[status(thm)],[10698,342]),
    [iquote('0:MRR:10698.0,342.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11  % Problem  : KRS258+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% 0.07/0.12  % Command  : run_spass %d %s
% 0.13/0.33  % Computer : n023.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Tue Jun  7 07:15:23 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 2.11/2.28  
% 2.11/2.28  SPASS V 3.9 
% 2.11/2.28  SPASS beiseite: Proof found.
% 2.11/2.28  % SZS status Theorem
% 2.11/2.28  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 2.11/2.28  SPASS derived 10423 clauses, backtracked 60 clauses, performed 47 splits and kept 5074 clauses.
% 2.11/2.28  SPASS allocated 91497 KBytes.
% 2.11/2.28  SPASS spent	0:00:01.89 on the problem.
% 2.11/2.28  		0:00:00.04 for the input.
% 2.11/2.28  		0:00:00.20 for the FLOTTER CNF translation.
% 2.11/2.28  		0:00:00.06 for inferences.
% 2.11/2.28  		0:00:00.02 for the backtracking.
% 2.11/2.28  		0:00:01.51 for the reduction.
% 2.11/2.28  
% 2.11/2.28  
% 2.11/2.28  Here is a proof with depth 3, length 13 :
% 2.11/2.28  % SZS output start Refutation
% See solution above
% 2.11/2.28  Formulae used in the proof : tautology mighta_eqv_thm thm mighta eqv
% 2.11/2.28  
%------------------------------------------------------------------------------