TSTP Solution File: KRS201+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : KRS201+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 03:30:52 EDT 2022

% Result   : Theorem 0.59s 0.76s
% Output   : Refutation 0.59s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   14 (   7 unt;   3 nHn;  14 RR)
%            Number of literals    :   23 (   0 equ;   8 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :   10 (  10 usr;   9 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(8,axiom,
    model(skc75,skc72),
    file('KRS201+1.p',unknown),
    [] ).

cnf(9,axiom,
    ~ nota(sap,thm),
    file('KRS201+1.p',unknown),
    [] ).

cnf(14,axiom,
    ~ model(skc73,skc72),
    file('KRS201+1.p',unknown),
    [] ).

cnf(18,axiom,
    ( model(u,v)
    | model(u,not__dfg(v)) ),
    file('KRS201+1.p',unknown),
    [] ).

cnf(23,axiom,
    ( ~ model(u,v)
    | status__dfg(w,v,sap) ),
    file('KRS201+1.p',unknown),
    [] ).

cnf(71,axiom,
    ( ~ model(u,v)
    | ~ status__dfg(v,w,thm)
    | model(u,w) ),
    file('KRS201+1.p',unknown),
    [] ).

cnf(82,axiom,
    ( ~ status__dfg(u,v,w)
    | nota(w,x)
    | status__dfg(u,v,x) ),
    file('KRS201+1.p',unknown),
    [] ).

cnf(112,plain,
    ( ~ status__dfg(u,v,sap)
    | status__dfg(u,v,thm) ),
    inference(res,[status(thm),theory(equality)],[82,9]),
    [iquote('0:Res:82.2,9.0')] ).

cnf(115,plain,
    status__dfg(u,skc72,sap),
    inference(res,[status(thm),theory(equality)],[8,23]),
    [iquote('0:Res:8.0,23.0')] ).

cnf(251,plain,
    status__dfg(u,skc72,thm),
    inference(res,[status(thm),theory(equality)],[115,112]),
    [iquote('0:Res:115.0,112.0')] ).

cnf(1104,plain,
    ( ~ model(u,v)
    | model(u,skc72) ),
    inference(res,[status(thm),theory(equality)],[251,71]),
    [iquote('0:Res:251.0,71.1')] ).

cnf(1219,plain,
    ( model(u,v)
    | model(u,skc72) ),
    inference(res,[status(thm),theory(equality)],[18,1104]),
    [iquote('0:Res:18.1,1104.0')] ).

cnf(1275,plain,
    model(u,skc72),
    inference(con,[status(thm)],[1219]),
    [iquote('0:Con:1219.0')] ).

cnf(1276,plain,
    $false,
    inference(unc,[status(thm)],[1275,14]),
    [iquote('0:UnC:1275.0,14.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : KRS201+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% 0.06/0.12  % Command  : run_spass %d %s
% 0.13/0.33  % Computer : n026.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Tue Jun  7 11:33:46 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.59/0.76  
% 0.59/0.76  SPASS V 3.9 
% 0.59/0.76  SPASS beiseite: Proof found.
% 0.59/0.76  % SZS status Theorem
% 0.59/0.76  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.59/0.76  SPASS derived 1145 clauses, backtracked 7 clauses, performed 8 splits and kept 986 clauses.
% 0.59/0.76  SPASS allocated 87719 KBytes.
% 0.59/0.76  SPASS spent	0:00:00.41 on the problem.
% 0.59/0.76  		0:00:00.04 for the input.
% 0.59/0.76  		0:00:00.19 for the FLOTTER CNF translation.
% 0.59/0.76  		0:00:00.01 for inferences.
% 0.59/0.76  		0:00:00.00 for the backtracking.
% 0.59/0.76  		0:00:00.15 for the reduction.
% 0.59/0.76  
% 0.59/0.76  
% 0.59/0.76  Here is a proof with depth 4, length 14 :
% 0.59/0.76  % SZS output start Refutation
% See solution above
% 0.59/0.76  Formulae used in the proof : non_thm_spt nota_sap_thm not__dfg sap thm nota
% 0.59/0.76  
%------------------------------------------------------------------------------