TSTP Solution File: KRS064+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : KRS064+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 05:43:12 EDT 2023

% Result   : Unsatisfiable 3.53s 3.70s
% Output   : Proof 3.53s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : KRS064+1 : TPTP v8.1.2. Released v3.1.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n011.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Mon Aug 28 02:03:55 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.53/3.70  SZS status Theorem for theBenchmark.p
% 3.53/3.70  SZS output start Proof for theBenchmark.p
% 3.53/3.70  Clause #0 (by assumption #[]): Eq (∀ (X : Iota), And (cowlThing X) (Not (cowlNothing X))) True
% 3.53/3.70  Clause #2 (by assumption #[]): Eq (cowlNothing i2003_11_14_17_18_08754) True
% 3.53/3.70  Clause #10 (by clausification #[0]): ∀ (a : Iota), Eq (And (cowlThing a) (Not (cowlNothing a))) True
% 3.53/3.70  Clause #11 (by clausification #[10]): ∀ (a : Iota), Eq (Not (cowlNothing a)) True
% 3.53/3.70  Clause #13 (by clausification #[11]): ∀ (a : Iota), Eq (cowlNothing a) False
% 3.53/3.70  Clause #14 (by superposition #[13, 2]): Eq False True
% 3.53/3.70  Clause #15 (by clausification #[14]): False
% 3.53/3.70  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------