TSTP Solution File: KRS035+1 by Crossbow---0.1

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Crossbow---0.1
% Problem  : KRS035+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : do_Crossbow---0.1 %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 02:43:07 EDT 2022

% Result   : Satisfiable 5.24s 5.39s
% Output   : FiniteModel 5.24s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11  % Problem    : KRS035+1 : TPTP v8.1.0. Released v3.1.0.
% 0.12/0.12  % Command    : do_Crossbow---0.1 %s
% 0.13/0.33  % Computer : n026.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit   : 300
% 0.13/0.33  % WCLimit    : 600
% 0.13/0.33  % DateTime   : Tue Jun  7 06:10:16 EDT 2022
% 0.13/0.33  % CPUTime    : 
% 0.13/0.33  /export/starexec/sandbox2/solver/bin
% 0.19/0.33  crossbow.opt
% 0.19/0.33  do_Crossbow---0.1
% 0.19/0.33  eprover
% 0.19/0.33  runsolver
% 0.19/0.33  starexec_run_Crossbow---0.1
% 5.24/5.39  % SZS status Satisfiable for theBenchmark.p
% 5.24/5.39  % SZS output start FiniteModel for theBenchmark.p
% 5.24/5.39  % domain size: 2
% 5.24/5.39  fof(interp, fi_domain, ![X] : (X = 0 | X = 1)).
% 5.24/5.39  fof(interp, fi_predicates, cSatisfiable(0) & ~cSatisfiable(1)).
% 5.24/5.39  fof(interp, fi_predicates, ~ca(0) & ca(1)).
% 5.24/5.39  fof(interp, fi_predicates, ~cowlNothing(0) & ~cowlNothing(1)).
% 5.24/5.39  fof(interp, fi_functors, esk1_1(0) = 0 & esk1_1(1) = 0).
% 5.24/5.39  fof(interp, fi_functors, esk2_1(0) = 1 & esk2_1(1) = 0).
% 5.24/5.39  fof(interp, fi_functors, esk3_1(0) = 1 & esk3_1(1) = 0).
% 5.24/5.39  fof(interp, fi_functors, i2003_11_14_17_15_44810 = 0).
% 5.24/5.39  fof(interp, fi_predicates, ~rf(0, 0) & ~rf(0, 1) & rf(1, 0) & ~rf(1, 1)).
% 5.24/5.39  fof(interp, fi_predicates, ~rinvF(0, 0) & rinvF(0, 1) & ~rinvF(1, 0) &
% 5.24/5.39    ~rinvF(1, 1)).
% 5.24/5.39  fof(interp, fi_predicates, rinvR(0, 0) & rinvR(0, 1) & ~rinvR(1, 0) &
% 5.24/5.39    ~rinvR(1, 1)).
% 5.24/5.39  fof(interp, fi_predicates, rr(0, 0) & ~rr(0, 1) & rr(1, 0) & ~rr(1, 1)).
% 5.24/5.39  fof(interp, fi_predicates, ~xsd_integer(0) & ~xsd_integer(1)).
% 5.24/5.39  fof(interp, fi_predicates, xsd_string(0) & xsd_string(1)).
% 5.24/5.39  % SZS output end FiniteModel for theBenchmark.p
% 5.24/5.39  % 0 lemma(s) from E
% 5.24/5.39  % 10 pred(s)
% 5.24/5.39  % 4 func(s)
% 5.24/5.39  % 3 sort(s)
% 5.24/5.39  % 19 clause(s)
% 5.24/5.39  % Instantiating 1 (5030 ms)
% 5.24/5.39  % Solving (5030 ms)
% 5.24/5.39  % Instantiating 2 (5030 ms)
% 5.24/5.39  % Solving (5030 ms)
% 5.24/5.39  % 
% 5.24/5.39  % 1 model found (5030 ms)
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