TSTP Solution File: KRS028+1 by Crossbow---0.1
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Crossbow---0.1
% Problem : KRS028+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : do_Crossbow---0.1 %s
% Computer : n019.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 02:43:04 EDT 2022
% Result : Satisfiable 5.19s 5.40s
% Output : FiniteModel 5.19s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : KRS028+1 : TPTP v8.1.0. Released v3.1.0.
% 0.03/0.13 % Command : do_Crossbow---0.1 %s
% 0.12/0.34 % Computer : n019.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Tue Jun 7 16:26:10 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.12/0.34 /export/starexec/sandbox/solver/bin
% 0.12/0.35 crossbow.opt
% 0.12/0.35 do_Crossbow---0.1
% 0.12/0.35 eprover
% 0.12/0.35 runsolver
% 0.12/0.35 starexec_run_Crossbow---0.1
% 5.19/5.40 % SZS status Satisfiable for theBenchmark.p
% 5.19/5.40 % SZS output start FiniteModel for theBenchmark.p
% 5.19/5.40 % domain size: 2
% 5.19/5.40 fof(interp, fi_domain, ![X] : (X = 0 | X = 1)).
% 5.19/5.40 fof(interp, fi_predicates, cSatisfiable(0) & cSatisfiable(1)).
% 5.19/5.40 fof(interp, fi_predicates, cc1(0) & ~cc1(1)).
% 5.19/5.40 fof(interp, fi_predicates, ~cc2(0) & cc2(1)).
% 5.19/5.40 fof(interp, fi_predicates, ~cowlNothing(0) & ~cowlNothing(1)).
% 5.19/5.40 fof(interp, fi_functors, esk1_1(0) = 1 & esk1_1(1) = 1).
% 5.19/5.40 fof(interp, fi_functors, esk2_1(0) = 0 & esk2_1(1) = 0).
% 5.19/5.40 fof(interp, fi_functors, esk3_1(0) = 0 & esk3_1(1) = 0).
% 5.19/5.40 fof(interp, fi_functors, i2003_11_14_17_15_19316 = 0).
% 5.19/5.40 fof(interp, fi_predicates, ~rrx(0, 0) & ~rrx(0, 1) & ~rrx(1, 0) & ~rrx(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, ~rrx1(0, 0) & ~rrx1(0, 1) & ~rrx1(1, 0) & ~rrx1(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, rrx1a(0, 0) & ~rrx1a(0, 1) & rrx1a(1, 0) &
% 5.19/5.40 ~rrx1a(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, ~rrx2(0, 0) & ~rrx2(0, 1) & ~rrx2(1, 0) & ~rrx2(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, ~rrx2a(0, 0) & rrx2a(0, 1) & ~rrx2a(1, 0) &
% 5.19/5.40 rrx2a(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, ~rrx3(0, 0) & ~rrx3(0, 1) & ~rrx3(1, 0) & ~rrx3(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, rrx3a(0, 0) & ~rrx3a(0, 1) & rrx3a(1, 0) &
% 5.19/5.40 ~rrx3a(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, ~rrx4(0, 0) & ~rrx4(0, 1) & ~rrx4(1, 0) & ~rrx4(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, ~rrx4a(0, 0) & rrx4a(0, 1) & ~rrx4a(1, 0) &
% 5.19/5.40 rrx4a(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, rrxa(0, 0) & rrxa(0, 1) & rrxa(1, 0) & rrxa(1, 1)).
% 5.19/5.40 fof(interp, fi_predicates, ~xsd_integer(0) & ~xsd_integer(1)).
% 5.19/5.40 fof(interp, fi_predicates, xsd_string(0) & xsd_string(1)).
% 5.19/5.40 % SZS output end FiniteModel for theBenchmark.p
% 5.19/5.40 % 0 lemma(s) from E
% 5.19/5.40 % 19 pred(s)
% 5.19/5.40 % 4 func(s)
% 5.19/5.40 % 6 sort(s)
% 5.19/5.40 % 28 clause(s)
% 5.19/5.40 % Instantiating 1 (5024 ms)
% 5.19/5.40 % Solving (5024 ms)
% 5.19/5.40 % Instantiating 2 (5024 ms)
% 5.19/5.40 % Solving (5025 ms)
% 5.19/5.40 %
% 5.19/5.40 % 1 model found (5025 ms)
%------------------------------------------------------------------------------