TSTP Solution File: KLE076+1 by Etableau---0.67

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : KLE076+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 01:56:57 EDT 2022

% Result   : Theorem 0.22s 0.38s
% Output   : CNFRefutation 0.22s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    3
% Syntax   : Number of formulae    :   11 (  11 unt;   0 def)
%            Number of atoms       :   11 (  10 equ)
%            Maximal formula atoms :    1 (   1 avg)
%            Number of connectives :    4 (   4   ~;   0   |;   0   &)
%                                         (   0 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    3 (   2 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :    5 (   1 sgn   4   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(goals,conjecture,
    ! [X4] : domain(multiplication(X4,domain(zero))) = zero,
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',goals) ).

fof(domain4,axiom,
    domain(zero) = zero,
    file('/export/starexec/sandbox/benchmark/Axioms/KLE001+5.ax',domain4) ).

fof(right_annihilation,axiom,
    ! [X1] : multiplication(X1,zero) = zero,
    file('/export/starexec/sandbox/benchmark/Axioms/KLE001+0.ax',right_annihilation) ).

fof(c_0_3,negated_conjecture,
    ~ ! [X4] : domain(multiplication(X4,domain(zero))) = zero,
    inference(assume_negation,[status(cth)],[goals]) ).

fof(c_0_4,negated_conjecture,
    domain(multiplication(esk1_0,domain(zero))) != zero,
    inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_3])])]) ).

cnf(c_0_5,negated_conjecture,
    domain(multiplication(esk1_0,domain(zero))) != zero,
    inference(split_conjunct,[status(thm)],[c_0_4]) ).

cnf(c_0_6,plain,
    domain(zero) = zero,
    inference(split_conjunct,[status(thm)],[domain4]) ).

fof(c_0_7,plain,
    ! [X24] : multiplication(X24,zero) = zero,
    inference(variable_rename,[status(thm)],[right_annihilation]) ).

cnf(c_0_8,negated_conjecture,
    domain(multiplication(esk1_0,zero)) != zero,
    inference(rw,[status(thm)],[c_0_5,c_0_6]) ).

cnf(c_0_9,plain,
    multiplication(X1,zero) = zero,
    inference(split_conjunct,[status(thm)],[c_0_7]) ).

cnf(c_0_10,negated_conjecture,
    $false,
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[c_0_8,c_0_9]),c_0_6])]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13  % Problem  : KLE076+1 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.13/0.35  % Computer : n020.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 600
% 0.13/0.35  % DateTime : Thu Jun 16 10:50:49 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.22/0.38  # No SInE strategy applied
% 0.22/0.38  # Auto-Mode selected heuristic G_E___208_C12_11_nc_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.22/0.38  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.22/0.38  #
% 0.22/0.38  # Presaturation interreduction done
% 0.22/0.38  
% 0.22/0.38  # Proof found!
% 0.22/0.38  # SZS status Theorem
% 0.22/0.38  # SZS output start CNFRefutation
% See solution above
% 0.22/0.38  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------