TSTP Solution File: KLE050+1 by Crossbow---0.1
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Crossbow---0.1
% Problem : KLE050+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : do_Crossbow---0.1 %s
% Computer : n024.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 01:38:00 EDT 2022
% Result : CounterSatisfiable 5.95s 6.10s
% Output : FiniteModel 5.95s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : KLE050+1 : TPTP v8.1.0. Released v4.0.0.
% 0.12/0.13 % Command : do_Crossbow---0.1 %s
% 0.13/0.34 % Computer : n024.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Thu Jun 16 15:55:18 EDT 2022
% 0.13/0.35 % CPUTime :
% 0.13/0.35 /export/starexec/sandbox2/solver/bin
% 0.13/0.35 crossbow.opt
% 0.13/0.35 do_Crossbow---0.1
% 0.13/0.35 eprover
% 0.13/0.35 runsolver
% 0.13/0.35 starexec_run_Crossbow---0.1
% 5.95/6.10 % SZS status CounterSatisfiable for theBenchmark.p
% 5.95/6.10 % SZS output start FiniteModel for theBenchmark.p
% 5.95/6.10 % domain size: 8
% 5.95/6.10 fof(interp, fi_domain, ![X] : (X = 0 | X = 1 | X = 2 | X = 3 | X = 4 | X = 5 |
% 5.95/6.10 X = 6 |
% 5.95/6.10 X = 7)).
% 5.95/6.10 fof(interp, fi_functors, addition(0, 0) = 0 & addition(0, 1) = 0 &
% 5.95/6.10 addition(0, 2) = 2 &
% 5.95/6.10 addition(0, 3) = 7 &
% 5.95/6.10 addition(0, 4) = 2 &
% 5.95/6.10 addition(0, 5) = 6 &
% 5.95/6.10 addition(0, 6) = 6 &
% 5.95/6.10 addition(0, 7) = 7 &
% 5.95/6.10 addition(1, 0) = 0 &
% 5.95/6.10 addition(1, 1) = 1 &
% 5.95/6.10 addition(1, 2) = 2 &
% 5.95/6.10 addition(1, 3) = 3 &
% 5.95/6.10 addition(1, 4) = 4 &
% 5.95/6.10 addition(1, 5) = 5 &
% 5.95/6.10 addition(1, 6) = 6 &
% 5.95/6.10 addition(1, 7) = 7 &
% 5.95/6.10 addition(2, 0) = 2 &
% 5.95/6.10 addition(2, 1) = 2 &
% 5.95/6.10 addition(2, 2) = 2 &
% 5.95/6.10 addition(2, 3) = 7 &
% 5.95/6.10 addition(2, 4) = 2 &
% 5.95/6.10 addition(2, 5) = 7 &
% 5.95/6.10 addition(2, 6) = 7 &
% 5.95/6.10 addition(2, 7) = 7 &
% 5.95/6.10 addition(3, 0) = 7 &
% 5.95/6.10 addition(3, 1) = 3 &
% 5.95/6.10 addition(3, 2) = 7 &
% 5.95/6.10 addition(3, 3) = 3 &
% 5.95/6.10 addition(3, 4) = 3 &
% 5.95/6.10 addition(3, 5) = 3 &
% 5.95/6.10 addition(3, 6) = 7 &
% 5.95/6.10 addition(3, 7) = 7 &
% 5.95/6.10 addition(4, 0) = 2 &
% 5.95/6.10 addition(4, 1) = 4 &
% 5.95/6.10 addition(4, 2) = 2 &
% 5.95/6.10 addition(4, 3) = 3 &
% 5.95/6.10 addition(4, 4) = 4 &
% 5.95/6.10 addition(4, 5) = 3 &
% 5.95/6.10 addition(4, 6) = 7 &
% 5.95/6.10 addition(4, 7) = 7 &
% 5.95/6.10 addition(5, 0) = 6 &
% 5.95/6.10 addition(5, 1) = 5 &
% 5.95/6.10 addition(5, 2) = 7 &
% 5.95/6.10 addition(5, 3) = 3 &
% 5.95/6.10 addition(5, 4) = 3 &
% 5.95/6.10 addition(5, 5) = 5 &
% 5.95/6.10 addition(5, 6) = 6 &
% 5.95/6.10 addition(5, 7) = 7 &
% 5.95/6.10 addition(6, 0) = 6 &
% 5.95/6.10 addition(6, 1) = 6 &
% 5.95/6.10 addition(6, 2) = 7 &
% 5.95/6.10 addition(6, 3) = 7 &
% 5.95/6.10 addition(6, 4) = 7 &
% 5.95/6.10 addition(6, 5) = 6 &
% 5.95/6.10 addition(6, 6) = 6 &
% 5.95/6.10 addition(6, 7) = 7 &
% 5.95/6.10 addition(7, 0) = 7 &
% 5.95/6.10 addition(7, 1) = 7 &
% 5.95/6.10 addition(7, 2) = 7 &
% 5.95/6.10 addition(7, 3) = 7 &
% 5.95/6.10 addition(7, 4) = 7 &
% 5.95/6.10 addition(7, 5) = 7 &
% 5.95/6.10 addition(7, 6) = 7 &
% 5.95/6.10 addition(7, 7) = 7).
% 5.95/6.10 fof(interp, fi_functors, c(0) = 4 & c(1) = 2 & c(2) = 1 & c(3) = 1 & c(4) = 0 &
% 5.95/6.10 c(5) = 1 &
% 5.95/6.10 c(6) = 1 &
% 5.95/6.10 c(7) = 1).
% 5.95/6.10 fof(interp, fi_predicates, ~complement(0, 0) & ~complement(0, 1) &
% 5.95/6.10 ~complement(0, 2) &
% 5.95/6.10 ~complement(0, 3) &
% 5.95/6.10 complement(0, 4) &
% 5.95/6.10 ~complement(0, 5) &
% 5.95/6.10 ~complement(0, 6) &
% 5.95/6.10 ~complement(0, 7) &
% 5.95/6.10 ~complement(1, 0) &
% 5.95/6.10 ~complement(1, 1) &
% 5.95/6.10 complement(1, 2) &
% 5.95/6.10 ~complement(1, 3) &
% 5.95/6.10 ~complement(1, 4) &
% 5.95/6.10 ~complement(1, 5) &
% 5.95/6.10 ~complement(1, 6) &
% 5.95/6.10 ~complement(1, 7) &
% 5.95/6.10 ~complement(2, 0) &
% 5.95/6.10 complement(2, 1) &
% 5.95/6.10 ~complement(2, 2) &
% 5.95/6.10 ~complement(2, 3) &
% 5.95/6.10 ~complement(2, 4) &
% 5.95/6.10 ~complement(2, 5) &
% 5.95/6.10 ~complement(2, 6) &
% 5.95/6.10 ~complement(2, 7) &
% 5.95/6.10 ~complement(3, 0) &
% 5.95/6.10 ~complement(3, 1) &
% 5.95/6.10 ~complement(3, 2) &
% 5.95/6.10 ~complement(3, 3) &
% 5.95/6.10 ~complement(3, 4) &
% 5.95/6.10 ~complement(3, 5) &
% 5.95/6.10 ~complement(3, 6) &
% 5.95/6.10 ~complement(3, 7) &
% 5.95/6.10 complement(4, 0) &
% 5.95/6.10 ~complement(4, 1) &
% 5.95/6.10 ~complement(4, 2) &
% 5.95/6.10 ~complement(4, 3) &
% 5.95/6.10 ~complement(4, 4) &
% 5.95/6.10 ~complement(4, 5) &
% 5.95/6.10 ~complement(4, 6) &
% 5.95/6.10 ~complement(4, 7) &
% 5.95/6.10 ~complement(5, 0) &
% 5.95/6.10 ~complement(5, 1) &
% 5.95/6.10 ~complement(5, 2) &
% 5.95/6.10 ~complement(5, 3) &
% 5.95/6.10 ~complement(5, 4) &
% 5.95/6.10 ~complement(5, 5) &
% 5.95/6.10 ~complement(5, 6) &
% 5.95/6.10 ~complement(5, 7) &
% 5.95/6.10 ~complement(6, 0) &
% 5.95/6.10 ~complement(6, 1) &
% 5.95/6.10 ~complement(6, 2) &
% 5.95/6.10 ~complement(6, 3) &
% 5.95/6.10 ~complement(6, 4) &
% 5.95/6.10 ~complement(6, 5) &
% 5.95/6.10 ~complement(6, 6) &
% 5.95/6.10 ~complement(6, 7) &
% 5.95/6.10 ~complement(7, 0) &
% 5.95/6.10 ~complement(7, 1) &
% 5.95/6.10 ~complement(7, 2) &
% 5.95/6.10 ~complement(7, 3) &
% 5.95/6.10 ~complement(7, 4) &
% 5.95/6.10 ~complement(7, 5) &
% 5.95/6.10 ~complement(7, 6) &
% 5.95/6.10 ~complement(7, 7)).
% 5.95/6.10 fof(interp, fi_functors, esk1_1(0) = 4 & esk1_1(1) = 2 & esk1_1(2) = 1 &
% 5.95/6.10 esk1_1(3) = 1 &
% 5.95/6.10 esk1_1(4) = 0 &
% 5.95/6.10 esk1_1(5) = 1 &
% 5.95/6.10 esk1_1(6) = 0 &
% 5.95/6.10 esk1_1(7) = 0).
% 5.95/6.10 fof(interp, fi_functors, esk2_0 = 3).
% 5.95/6.10 fof(interp, fi_functors, esk3_0 = 4).
% 5.95/6.10 fof(interp, fi_functors, esk4_0 = 0).
% 5.95/6.10 fof(interp, fi_functors, esk5_0 = 0).
% 5.95/6.10 fof(interp, fi_predicates, leq(0, 0) & ~leq(0, 1) & leq(0, 2) & ~leq(0, 3) &
% 5.95/6.10 ~leq(0, 4) &
% 5.95/6.10 ~leq(0, 5) &
% 5.95/6.10 leq(0, 6) &
% 5.95/6.10 leq(0, 7) &
% 5.95/6.10 leq(1, 0) &
% 5.95/6.10 leq(1, 1) &
% 5.95/6.10 leq(1, 2) &
% 5.95/6.10 leq(1, 3) &
% 5.95/6.10 leq(1, 4) &
% 5.95/6.10 leq(1, 5) &
% 5.95/6.10 leq(1, 6) &
% 5.95/6.10 leq(1, 7) &
% 5.95/6.10 ~leq(2, 0) &
% 5.95/6.10 ~leq(2, 1) &
% 5.95/6.10 leq(2, 2) &
% 5.95/6.10 ~leq(2, 3) &
% 5.95/6.10 ~leq(2, 4) &
% 5.95/6.10 ~leq(2, 5) &
% 5.95/6.10 ~leq(2, 6) &
% 5.95/6.10 leq(2, 7) &
% 5.95/6.10 ~leq(3, 0) &
% 5.95/6.10 ~leq(3, 1) &
% 5.95/6.10 ~leq(3, 2) &
% 5.95/6.10 leq(3, 3) &
% 5.95/6.10 ~leq(3, 4) &
% 5.95/6.10 ~leq(3, 5) &
% 5.95/6.10 ~leq(3, 6) &
% 5.95/6.10 leq(3, 7) &
% 5.95/6.10 ~leq(4, 0) &
% 5.95/6.10 ~leq(4, 1) &
% 5.95/6.10 leq(4, 2) &
% 5.95/6.11 leq(4, 3) &
% 5.95/6.11 leq(4, 4) &
% 5.95/6.11 ~leq(4, 5) &
% 5.95/6.11 ~leq(4, 6) &
% 5.95/6.11 leq(4, 7) &
% 5.95/6.11 ~leq(5, 0) &
% 5.95/6.11 ~leq(5, 1) &
% 5.95/6.11 ~leq(5, 2) &
% 5.95/6.11 leq(5, 3) &
% 5.95/6.11 ~leq(5, 4) &
% 5.95/6.11 leq(5, 5) &
% 5.95/6.11 leq(5, 6) &
% 5.95/6.11 leq(5, 7) &
% 5.95/6.11 ~leq(6, 0) &
% 5.95/6.11 ~leq(6, 1) &
% 5.95/6.11 ~leq(6, 2) &
% 5.95/6.11 ~leq(6, 3) &
% 5.95/6.11 ~leq(6, 4) &
% 5.95/6.11 ~leq(6, 5) &
% 5.95/6.11 leq(6, 6) &
% 5.95/6.11 leq(6, 7) &
% 5.95/6.11 ~leq(7, 0) &
% 5.95/6.11 ~leq(7, 1) &
% 5.95/6.11 ~leq(7, 2) &
% 5.95/6.11 ~leq(7, 3) &
% 5.95/6.11 ~leq(7, 4) &
% 5.95/6.11 ~leq(7, 5) &
% 5.95/6.11 ~leq(7, 6) &
% 5.95/6.11 leq(7, 7)).
% 5.95/6.11 fof(interp, fi_functors, multiplication(0, 0) = 0 & multiplication(0, 1) = 1 &
% 5.95/6.11 multiplication(0, 2) = 0 &
% 5.95/6.11 multiplication(0, 3) = 5 &
% 5.95/6.11 multiplication(0, 4) = 1 &
% 5.95/6.11 multiplication(0, 5) = 5 &
% 5.95/6.11 multiplication(0, 6) = 6 &
% 5.95/6.11 multiplication(0, 7) = 6 &
% 5.95/6.11 multiplication(1, 0) = 1 &
% 5.95/6.11 multiplication(1, 1) = 1 &
% 5.95/6.11 multiplication(1, 2) = 1 &
% 5.95/6.11 multiplication(1, 3) = 1 &
% 5.95/6.11 multiplication(1, 4) = 1 &
% 5.95/6.11 multiplication(1, 5) = 1 &
% 5.95/6.11 multiplication(1, 6) = 1 &
% 5.95/6.11 multiplication(1, 7) = 1 &
% 5.95/6.11 multiplication(2, 0) = 0 &
% 5.95/6.11 multiplication(2, 1) = 1 &
% 5.95/6.11 multiplication(2, 2) = 2 &
% 5.95/6.11 multiplication(2, 3) = 3 &
% 5.95/6.11 multiplication(2, 4) = 4 &
% 5.95/6.11 multiplication(2, 5) = 5 &
% 5.95/6.11 multiplication(2, 6) = 6 &
% 5.95/6.11 multiplication(2, 7) = 7 &
% 5.95/6.11 multiplication(3, 0) = 1 &
% 5.95/6.11 multiplication(3, 1) = 1 &
% 5.95/6.11 multiplication(3, 2) = 3 &
% 5.95/6.11 multiplication(3, 3) = 3 &
% 5.95/6.11 multiplication(3, 4) = 3 &
% 5.95/6.11 multiplication(3, 5) = 1 &
% 5.95/6.11 multiplication(3, 6) = 1 &
% 5.95/6.11 multiplication(3, 7) = 3 &
% 5.95/6.11 multiplication(4, 0) = 1 &
% 5.95/6.11 multiplication(4, 1) = 1 &
% 5.95/6.11 multiplication(4, 2) = 4 &
% 5.95/6.11 multiplication(4, 3) = 4 &
% 5.95/6.11 multiplication(4, 4) = 4 &
% 5.95/6.11 multiplication(4, 5) = 1 &
% 5.95/6.11 multiplication(4, 6) = 1 &
% 5.95/6.11 multiplication(4, 7) = 4 &
% 5.95/6.11 multiplication(5, 0) = 1 &
% 5.95/6.11 multiplication(5, 1) = 1 &
% 5.95/6.11 multiplication(5, 2) = 5 &
% 5.95/6.11 multiplication(5, 3) = 5 &
% 5.95/6.11 multiplication(5, 4) = 5 &
% 5.95/6.11 multiplication(5, 5) = 1 &
% 5.95/6.11 multiplication(5, 6) = 1 &
% 5.95/6.11 multiplication(5, 7) = 5 &
% 5.95/6.11 multiplication(6, 0) = 0 &
% 5.95/6.11 multiplication(6, 1) = 1 &
% 5.95/6.11 multiplication(6, 2) = 6 &
% 5.95/6.11 multiplication(6, 3) = 5 &
% 5.95/6.11 multiplication(6, 4) = 5 &
% 5.95/6.11 multiplication(6, 5) = 5 &
% 5.95/6.11 multiplication(6, 6) = 6 &
% 5.95/6.11 multiplication(6, 7) = 6 &
% 5.95/6.11 multiplication(7, 0) = 0 &
% 5.95/6.11 multiplication(7, 1) = 1 &
% 5.95/6.11 multiplication(7, 2) = 7 &
% 5.95/6.11 multiplication(7, 3) = 3 &
% 5.95/6.11 multiplication(7, 4) = 3 &
% 5.95/6.11 multiplication(7, 5) = 5 &
% 5.95/6.11 multiplication(7, 6) = 6 &
% 5.95/6.11 multiplication(7, 7) = 7).
% 5.95/6.11 fof(interp, fi_functors, one = 2).
% 5.95/6.11 fof(interp, fi_functors, star(0) = 2 & star(1) = 2 & star(2) = 2 & star(3) = 7 &
% 5.95/6.11 star(4) = 2 &
% 5.95/6.11 star(5) = 7 &
% 5.95/6.11 star(6) = 7 &
% 5.95/6.11 star(7) = 7).
% 5.95/6.11 fof(interp, fi_predicates, test(0) & test(1) & test(2) & ~test(3) & test(4) &
% 5.95/6.11 ~test(5) &
% 5.95/6.11 ~test(6) &
% 5.95/6.11 ~test(7)).
% 5.95/6.11 fof(interp, fi_functors, zero = 1).
% 5.95/6.11 % SZS output end FiniteModel for theBenchmark.p
% 5.95/6.11 % 20 lemma(s) from E
% 5.95/6.11 % cnf(cl, axiom, leq(one, one)).
% 5.95/6.11 % cnf(cl, axiom, zero != one).
% 5.95/6.11 % cnf(cl, axiom, esk4_0 != c(esk4_0)).
% 5.95/6.11 % cnf(cl, axiom, addition(A, B) = addition(A, addition(A, B))).
% 5.95/6.11 % cnf(cl, axiom, addition(A, B) = addition(A, addition(A, B))).
% 5.95/6.11 % cnf(cl, axiom, addition(one, star(one)) = star(one)).
% 5.95/6.11 % cnf(cl, axiom, leq(star(one), star(one))).
% 5.95/6.11 % cnf(cl, axiom, leq(zero, A)).
% 5.95/6.11 % cnf(cl, axiom, one = star(zero)).
% 5.95/6.11 % cnf(cl, axiom, ~leq(one, zero)).
% 5.95/6.11 % cnf(cl, axiom, zero != star(one)).
% 5.95/6.11 % cnf(cl, axiom, zero != star(A)).
% 5.95/6.11 % cnf(cl, axiom, multiplication(A, addition(A, one)) = multiplication(addition(A, one), A)).
% 5.95/6.11 % cnf(cl, axiom, multiplication(A, addition(A, one)) = multiplication(addition(A, one), A)).
% 5.95/6.11 % cnf(cl, axiom, addition(A, star(one)) = addition(addition(A, star(one)), one)).
% 5.95/6.11 % cnf(cl, axiom, addition(A, star(one)) = addition(addition(A, star(one)), one)).
% 5.95/6.11 % cnf(cl, axiom, zero != addition(A, one)).
% 5.95/6.11 % cnf(cl, axiom, zero != addition(A, one)).
% 5.95/6.11 % cnf(cl, axiom, ~leq(star(one), zero)).
% 5.95/6.11 % cnf(cl, axiom, multiplication(star(one), star(one)) != zero).
% 5.95/6.11 % 24 pred(s)
% 5.95/6.11 % 29 func(s)
% 5.95/6.11 % 1 sort(s)
% 5.95/6.11 % 87 clause(s)
% 5.95/6.11 % Instantiating 1 (5045 ms)
% 5.95/6.11 % Solving (5046 ms)
% 5.95/6.11 % Instantiating 2 (5046 ms)
% 5.95/6.11 % Solving (5047 ms)
% 5.95/6.11 % Instantiating 3 (5047 ms)
% 5.95/6.11 % Solving (5051 ms)
% 5.95/6.11 % Instantiating 4 (5053 ms)
% 5.95/6.11 % Solving (5064 ms)
% 5.95/6.11 % Instantiating 5 (5068 ms)
% 5.95/6.11 % Solving (5096 ms)
% 5.95/6.11 % Instantiating 6 (5111 ms)
% 5.95/6.11 % Solving (5165 ms)
% 5.95/6.11 % Instantiating 7 (5222 ms)
% 5.95/6.11 % Solving (5283 ms)
% 5.95/6.11 % Instantiating 8 (5472 ms)
% 5.95/6.11 % Solving (5561 ms)
% 5.95/6.11 %
% 5.95/6.11 % 1 model found (5725 ms)
%------------------------------------------------------------------------------