TSTP Solution File: KLE003+1 by Etableau---0.67

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : KLE003+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 01:56:26 EDT 2022

% Result   : Theorem 0.12s 0.37s
% Output   : CNFRefutation 0.12s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    2
% Syntax   : Number of formulae    :    8 (   4 unt;   0 def)
%            Number of atoms       :   14 (  13 equ)
%            Maximal formula atoms :    4 (   1 avg)
%            Number of connectives :   11 (   5   ~;   3   |;   1   &)
%                                         (   2 <=>;   0  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    5 (   3 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   2 con; 0-2 aty)
%            Number of variables   :    6 (   0 sgn   5   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(goals,conjecture,
    ( ! [X4] : addition(X4,X4) = X4
  <=> addition(one,one) = one ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',goals) ).

fof(additive_idempotence,axiom,
    ! [X1] : addition(X1,X1) = X1,
    file('/export/starexec/sandbox/benchmark/Axioms/KLE001+0.ax',additive_idempotence) ).

fof(c_0_2,negated_conjecture,
    ~ ( ! [X4] : addition(X4,X4) = X4
    <=> addition(one,one) = one ),
    inference(assume_negation,[status(cth)],[goals]) ).

fof(c_0_3,negated_conjecture,
    ! [X28] :
      ( ( addition(esk1_0,esk1_0) != esk1_0
        | addition(one,one) != one )
      & ( addition(X28,X28) = X28
        | addition(one,one) = one ) ),
    inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_2])])])]) ).

fof(c_0_4,plain,
    ! [X11] : addition(X11,X11) = X11,
    inference(variable_rename,[status(thm)],[additive_idempotence]) ).

cnf(c_0_5,negated_conjecture,
    ( addition(esk1_0,esk1_0) != esk1_0
    | addition(one,one) != one ),
    inference(split_conjunct,[status(thm)],[c_0_3]) ).

cnf(c_0_6,plain,
    addition(X1,X1) = X1,
    inference(split_conjunct,[status(thm)],[c_0_4]) ).

cnf(c_0_7,negated_conjecture,
    $false,
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[c_0_5,c_0_6]),c_0_6])]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : KLE003+1 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.12/0.34  % Computer : n020.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Thu Jun 16 12:38:34 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.12/0.37  # No SInE strategy applied
% 0.12/0.37  # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.12/0.37  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.12/0.37  #
% 0.12/0.37  # Presaturation interreduction done
% 0.12/0.37  
% 0.12/0.37  # Proof found!
% 0.12/0.37  # SZS status Theorem
% 0.12/0.37  # SZS output start CNFRefutation
% See solution above
% 0.12/0.37  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------