%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : KLE003+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 05:28:15 EDT 2023

% Result   : Theorem 5.69s 5.93s
% Output   : Proof 5.69s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.07  % Problem    : KLE003+1 : TPTP v8.1.2. Released v4.0.0.
% 0.06/0.08  % Command    : duper %s
% 0.07/0.27  % Computer : n032.cluster.edu
% 0.07/0.27  % Model    : x86_64 x86_64
% 0.07/0.27  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.07/0.27  % Memory   : 8042.1875MB
% 0.07/0.27  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.07/0.27  % CPULimit   : 300
% 0.07/0.27  % WCLimit    : 300
% 0.07/0.27  % DateTime   : Tue Aug 29 11:57:31 EDT 2023
% 0.07/0.27  % CPUTime    : 
% 5.69/5.93  SZS status Theorem for theBenchmark.p
% 5.69/5.93  SZS output start Proof for theBenchmark.p
% 5.69/5.93  Clause #3 (by assumption #[]): Eq (∀ (A : Iota), Eq (addition A A) A) True
% 5.69/5.93  Clause #12 (by assumption #[]): Eq (Not (Iff (∀ (X0 : Iota), Eq (addition X0 X0) X0) (Eq (addition one one) one))) True
% 5.69/5.93  Clause #19 (by clausification #[3]): ∀ (a : Iota), Eq (Eq (addition a a) a) True
% 5.69/5.93  Clause #20 (by clausification #[19]): ∀ (a : Iota), Eq (addition a a) a
% 5.69/5.93  Clause #156 (by clausification #[12]): Eq (Iff (∀ (X0 : Iota), Eq (addition X0 X0) X0) (Eq (addition one one) one)) False
% 5.69/5.93  Clause #157 (by clausification #[156]): Or (Eq (∀ (X0 : Iota), Eq (addition X0 X0) X0) False) (Eq (Eq (addition one one) one) False)
% 5.69/5.93  Clause #159 (by clausification #[157]): ∀ (a : Iota),
% 5.69/5.93    Or (Eq (Eq (addition one one) one) False) (Eq (Not (Eq (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a))) True)
% 5.69/5.93  Clause #160 (by clausification #[159]): ∀ (a : Iota), Or (Eq (Not (Eq (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a))) True) (Ne (addition one one) one)
% 5.69/5.93  Clause #161 (by clausification #[160]): ∀ (a : Iota), Or (Ne (addition one one) one) (Eq (Eq (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)) False)
% 5.69/5.93  Clause #162 (by clausification #[161]): ∀ (a : Iota), Or (Ne (addition one one) one) (Ne (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a))
% 5.69/5.93  Clause #163 (by forward demodulation #[162, 20]): ∀ (a : Iota), Or (Ne one one) (Ne (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a))
% 5.69/5.93  Clause #164 (by eliminate resolved literals #[163]): ∀ (a : Iota), Ne (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)
% 5.69/5.93  Clause #165 (by forward demodulation #[164, 20]): ∀ (a : Iota), Ne (skS.0 0 a) (skS.0 0 a)
% 5.69/5.93  Clause #166 (by eliminate resolved literals #[165]): False
% 5.69/5.93  SZS output end Proof for theBenchmark.p
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