TSTP Solution File: KLE001+1 by Vampire-SAT---4.8

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Vampire-SAT---4.8
% Problem  : KLE001+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : vampire --mode casc_sat -m 16384 --cores 7 -t %d %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Sun May  5 07:16:45 EDT 2024

% Result   : Theorem 0.14s 0.37s
% Output   : Refutation 0.14s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    4
% Syntax   : Number of formulae    :   13 (   4 unt;   0 def)
%            Number of atoms       :   26 (   6 equ)
%            Maximal formula atoms :    4 (   2 avg)
%            Number of connectives :   23 (  10   ~;   3   |;   5   &)
%                                         (   1 <=>;   4  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    7 (   4 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   3 con; 0-2 aty)
%            Number of variables   :   23 (  17   !;   6   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f49,plain,
    $false,
    inference(unit_resulting_resolution,[],[f22,f28,f31]) ).

fof(f31,plain,
    ! [X0,X1] :
      ( addition(X0,X1) != X1
      | leq(X0,X1) ),
    inference(cnf_transformation,[],[f20]) ).

fof(f20,plain,
    ! [X0,X1] :
      ( ( leq(X0,X1)
        | addition(X0,X1) != X1 )
      & ( addition(X0,X1) = X1
        | ~ leq(X0,X1) ) ),
    inference(nnf_transformation,[],[f12]) ).

fof(f12,axiom,
    ! [X0,X1] :
      ( leq(X0,X1)
    <=> addition(X0,X1) = X1 ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',order) ).

fof(f28,plain,
    ! [X0] : addition(X0,X0) = X0,
    inference(cnf_transformation,[],[f4]) ).

fof(f4,axiom,
    ! [X0] : addition(X0,X0) = X0,
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',additive_idempotence) ).

fof(f22,plain,
    ~ leq(addition(sK0,sK2),addition(sK0,sK2)),
    inference(cnf_transformation,[],[f19]) ).

fof(f19,plain,
    ( ~ leq(addition(sK0,sK2),addition(sK0,sK2))
    & leq(sK0,sK1) ),
    inference(skolemisation,[status(esa),new_symbols(skolem,[sK0,sK1,sK2])],[f17,f18]) ).

fof(f18,plain,
    ( ? [X0,X1,X2] :
        ( ~ leq(addition(X0,X2),addition(X0,X2))
        & leq(X0,X1) )
   => ( ~ leq(addition(sK0,sK2),addition(sK0,sK2))
      & leq(sK0,sK1) ) ),
    introduced(choice_axiom,[]) ).

fof(f17,plain,
    ? [X0,X1,X2] :
      ( ~ leq(addition(X0,X2),addition(X0,X2))
      & leq(X0,X1) ),
    inference(ennf_transformation,[],[f15]) ).

fof(f15,plain,
    ~ ! [X0,X1,X2] :
        ( leq(X0,X1)
       => leq(addition(X0,X2),addition(X0,X2)) ),
    inference(rectify,[],[f14]) ).

fof(f14,negated_conjecture,
    ~ ! [X3,X4,X5] :
        ( leq(X3,X4)
       => leq(addition(X3,X5),addition(X3,X5)) ),
    inference(negated_conjecture,[],[f13]) ).

fof(f13,conjecture,
    ! [X3,X4,X5] :
      ( leq(X3,X4)
     => leq(addition(X3,X5),addition(X3,X5)) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',goals) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : KLE001+1 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.14  % Command    : vampire --mode casc_sat -m 16384 --cores 7 -t %d %s
% 0.14/0.34  % Computer : n018.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Fri May  3 21:23:07 EDT 2024
% 0.14/0.35  % CPUTime    : 
% 0.14/0.35  % (12562)Running in auto input_syntax mode. Trying TPTP
% 0.14/0.36  % (12565)WARNING: value z3 for option sas not known
% 0.14/0.36  % (12566)fmb+10_1_bce=on:fmbsr=1.5:nm=32_533 on theBenchmark for (533ds/0Mi)
% 0.14/0.36  % (12565)dis+2_11_add=large:afr=on:amm=off:bd=off:bce=on:fsd=off:fde=none:gs=on:gsaa=full_model:gsem=off:irw=on:msp=off:nm=4:nwc=1.3:sas=z3:sims=off:sac=on:sp=reverse_arity_569 on theBenchmark for (569ds/0Mi)
% 0.14/0.37  % (12568)ott-10_8_av=off:bd=preordered:bs=on:fsd=off:fsr=off:fde=unused:irw=on:lcm=predicate:lma=on:nm=4:nwc=1.7:sp=frequency_522 on theBenchmark for (522ds/0Mi)
% 0.14/0.37  % (12567)ott+10_10:1_add=off:afr=on:amm=off:anc=all:bd=off:bs=on:fsr=off:irw=on:lma=on:msp=off:nm=4:nwc=4.0:sac=on:sp=reverse_frequency_531 on theBenchmark for (531ds/0Mi)
% 0.14/0.37  % (12564)fmb+10_1_bce=on:fmbdsb=on:fmbes=contour:fmbswr=3:fde=none:nm=0_793 on theBenchmark for (793ds/0Mi)
% 0.14/0.37  % (12569)ott+1_64_av=off:bd=off:bce=on:fsd=off:fde=unused:gsp=on:irw=on:lcm=predicate:lma=on:nm=2:nwc=1.1:sims=off:urr=on_497 on theBenchmark for (497ds/0Mi)
% 0.14/0.37  TRYING [1]
% 0.14/0.37  TRYING [2]
% 0.14/0.37  % (12568)Also succeeded, but the first one will report.
% 0.14/0.37  % (12569)First to succeed.
% 0.14/0.37  % (12563)fmb+10_1_bce=on:fmbas=function:fmbsr=1.2:fde=unused:nm=0_846 on theBenchmark for (846ds/0Mi)
% 0.14/0.37  % (12569)Solution written to "/export/starexec/sandbox/tmp/vampire-proof-12562"
% 0.14/0.37  % (12565)Also succeeded, but the first one will report.
% 0.14/0.37  TRYING [3]
% 0.14/0.37  % (12569)Refutation found. Thanks to Tanya!
% 0.14/0.37  % SZS status Theorem for theBenchmark
% 0.14/0.37  % SZS output start Proof for theBenchmark
% See solution above
% 0.14/0.37  % (12569)------------------------------
% 0.14/0.37  % (12569)Version: Vampire 4.8 (commit 3a798227e on 2024-05-03 07:42:47 +0200)
% 0.14/0.37  % (12569)Termination reason: Refutation
% 0.14/0.37  
% 0.14/0.37  % (12569)Memory used [KB]: 764
% 0.14/0.37  % (12569)Time elapsed: 0.003 s
% 0.14/0.37  % (12569)Instructions burned: 4 (million)
% 0.14/0.37  % (12562)Success in time 0.018 s
%------------------------------------------------------------------------------