TSTP Solution File: ITP040^1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : ITP040^1 : TPTP v8.1.2. Released v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 03:38:28 EDT 2023

% Result   : Theorem 4.06s 4.29s
% Output   : Proof 4.06s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : ITP040^1 : TPTP v8.1.2. Released v7.5.0.
% 0.11/0.13  % Command    : duper %s
% 0.12/0.34  % Computer : n011.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit   : 300
% 0.12/0.34  % WCLimit    : 300
% 0.12/0.34  % DateTime   : Sun Aug 27 14:09:55 EDT 2023
% 0.12/0.34  % CPUTime    : 
% 4.06/4.29  SZS status Theorem for theBenchmark.p
% 4.06/4.29  SZS output start Proof for theBenchmark.p
% 4.06/4.29  Clause #0 (by assumption #[]): Eq
% 4.06/4.29    (∀ (X : c) (I : denota231621370t_unit) (ODE : oDE_a_c),
% 4.06/4.29      member_c X (denota540094197_a_b_c I ODE) → member_c X (static_FVO_a_c ODE))
% 4.06/4.29    True
% 4.06/4.29  Clause #328 (by assumption #[]): Eq (member_c i2 (denota540094197_a_b_c i oDEa)) True
% 4.06/4.29  Clause #329 (by assumption #[]): Eq (Not (member_c i2 (static_FVO_a_c oDEa))) True
% 4.06/4.29  Clause #339 (by clausification #[0]): ∀ (a : c),
% 4.06/4.29    Eq
% 4.06/4.29      (∀ (I : denota231621370t_unit) (ODE : oDE_a_c),
% 4.06/4.29        member_c a (denota540094197_a_b_c I ODE) → member_c a (static_FVO_a_c ODE))
% 4.06/4.29      True
% 4.06/4.29  Clause #340 (by clausification #[339]): ∀ (a : c) (a_1 : denota231621370t_unit),
% 4.06/4.29    Eq (∀ (ODE : oDE_a_c), member_c a (denota540094197_a_b_c a_1 ODE) → member_c a (static_FVO_a_c ODE)) True
% 4.06/4.29  Clause #341 (by clausification #[340]): ∀ (a : c) (a_1 : denota231621370t_unit) (a_2 : oDE_a_c),
% 4.06/4.29    Eq (member_c a (denota540094197_a_b_c a_1 a_2) → member_c a (static_FVO_a_c a_2)) True
% 4.06/4.29  Clause #342 (by clausification #[341]): ∀ (a : c) (a_1 : denota231621370t_unit) (a_2 : oDE_a_c),
% 4.06/4.29    Or (Eq (member_c a (denota540094197_a_b_c a_1 a_2)) False) (Eq (member_c a (static_FVO_a_c a_2)) True)
% 4.06/4.29  Clause #350 (by clausification #[329]): Eq (member_c i2 (static_FVO_a_c oDEa)) False
% 4.06/4.29  Clause #351 (by superposition #[328, 342]): Or (Eq (member_c i2 (static_FVO_a_c oDEa)) True) (Eq False True)
% 4.06/4.29  Clause #569 (by clausification #[351]): Eq (member_c i2 (static_FVO_a_c oDEa)) True
% 4.06/4.29  Clause #570 (by superposition #[569, 350]): Eq True False
% 4.06/4.29  Clause #577 (by clausification #[570]): False
% 4.06/4.29  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------