TSTP Solution File: HEN005-5 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : HEN005-5 : TPTP v8.1.0. Released v1.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 13:03:03 EDT 2022
% Result : Unsatisfiable 0.18s 0.42s
% Output : Refutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 8
% Number of leaves : 6
% Syntax : Number of clauses : 16 ( 11 unt; 0 nHn; 16 RR)
% Number of literals : 23 ( 0 equ; 8 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 4 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 7 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
equal(divide(a,b),zero),
file('HEN005-5.p',unknown),
[] ).
cnf(2,axiom,
equal(divide(b,c),zero),
file('HEN005-5.p',unknown),
[] ).
cnf(3,axiom,
~ equal(divide(a,c),zero),
file('HEN005-5.p',unknown),
[] ).
cnf(5,axiom,
equal(divide(divide(divide(u,v),divide(w,v)),divide(divide(u,w),v)),zero),
file('HEN005-5.p',unknown),
[] ).
cnf(6,axiom,
equal(divide(zero,u),zero),
file('HEN005-5.p',unknown),
[] ).
cnf(7,axiom,
( ~ equal(divide(u,v),zero)
| ~ equal(divide(v,u),zero)
| equal(v,u) ),
file('HEN005-5.p',unknown),
[] ).
cnf(25,plain,
( ~ equal(zero,zero)
| ~ equal(divide(u,zero),zero)
| equal(u,zero) ),
inference(spl,[status(thm),theory(equality)],[6,7]),
[iquote('0:SpL:6.0,7.0')] ).
cnf(30,plain,
( ~ equal(divide(u,zero),zero)
| equal(u,zero) ),
inference(obv,[status(thm),theory(equality)],[25]),
[iquote('0:Obv:25.0')] ).
cnf(40,plain,
equal(divide(divide(divide(a,u),divide(b,u)),divide(zero,u)),zero),
inference(spr,[status(thm),theory(equality)],[1,5]),
[iquote('0:SpR:1.0,5.0')] ).
cnf(60,plain,
equal(divide(divide(divide(a,u),divide(b,u)),zero),zero),
inference(rew,[status(thm),theory(equality)],[6,40]),
[iquote('0:Rew:6.0,40.0')] ).
cnf(117,plain,
equal(divide(divide(divide(a,c),zero),zero),zero),
inference(spr,[status(thm),theory(equality)],[2,60]),
[iquote('0:SpR:2.0,60.0')] ).
cnf(139,plain,
( ~ equal(zero,zero)
| equal(divide(divide(a,c),zero),zero) ),
inference(spl,[status(thm),theory(equality)],[117,30]),
[iquote('0:SpL:117.0,30.0')] ).
cnf(140,plain,
equal(divide(divide(a,c),zero),zero),
inference(obv,[status(thm),theory(equality)],[139]),
[iquote('0:Obv:139.0')] ).
cnf(157,plain,
( ~ equal(zero,zero)
| equal(divide(a,c),zero) ),
inference(spl,[status(thm),theory(equality)],[140,30]),
[iquote('0:SpL:140.0,30.0')] ).
cnf(158,plain,
equal(divide(a,c),zero),
inference(obv,[status(thm),theory(equality)],[157]),
[iquote('0:Obv:157.0')] ).
cnf(159,plain,
$false,
inference(mrr,[status(thm)],[158,3]),
[iquote('0:MRR:158.0,3.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : HEN005-5 : TPTP v8.1.0. Released v1.0.0.
% 0.07/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n007.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Fri Jul 1 13:01:09 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.42
% 0.18/0.42 SPASS V 3.9
% 0.18/0.42 SPASS beiseite: Proof found.
% 0.18/0.42 % SZS status Theorem
% 0.18/0.42 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.18/0.42 SPASS derived 98 clauses, backtracked 0 clauses, performed 0 splits and kept 41 clauses.
% 0.18/0.42 SPASS allocated 63301 KBytes.
% 0.18/0.42 SPASS spent 0:00:00.07 on the problem.
% 0.18/0.42 0:00:00.03 for the input.
% 0.18/0.42 0:00:00.00 for the FLOTTER CNF translation.
% 0.18/0.42 0:00:00.00 for inferences.
% 0.18/0.42 0:00:00.00 for the backtracking.
% 0.18/0.42 0:00:00.01 for the reduction.
% 0.18/0.42
% 0.18/0.42
% 0.18/0.42 Here is a proof with depth 4, length 16 :
% 0.18/0.42 % SZS output start Refutation
% See solution above
% 0.18/0.42 Formulae used in the proof : a_divide_b_is_zero b_divide_c_is_zero prove_transitivity_of_divide_to_zero quotient_property zero_is_smallest divide_and_equal
% 0.18/0.42
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