TSTP Solution File: GRP538-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP538-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:12 EDT 2022

% Result   : Unsatisfiable 1.82s 2.04s
% Output   : Refutation 1.82s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   12 (  12 unt;   0 nHn;   3 RR)
%            Number of literals    :   12 (  11 equ;   2 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   3 con; 0-2 aty)
%            Number of variables   :   16 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(multiply(inverse(b2),b2),a2) != a2,
    file('GRP538-1.p',unknown),
    [] ).

cnf(3,axiom,
    divide(divide(A,B),divide(divide(A,C),B)) = C,
    file('GRP538-1.p',unknown),
    [] ).

cnf(5,axiom,
    multiply(A,B) = divide(A,divide(divide(C,C),B)),
    file('GRP538-1.p',unknown),
    [] ).

cnf(6,axiom,
    inverse(A) = divide(divide(B,B),A),
    file('GRP538-1.p',unknown),
    [] ).

cnf(7,axiom,
    identity = divide(A,A),
    file('GRP538-1.p',unknown),
    [] ).

cnf(9,plain,
    divide(A,A) = identity,
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[7])]),
    [iquote('copy,7,flip.1')] ).

cnf(11,plain,
    multiply(A,B) = divide(A,divide(identity,B)),
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[5])]),9])]),
    [iquote('copy,5,flip.1,demod,9,flip.1')] ).

cnf(13,plain,
    inverse(A) = divide(identity,A),
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[6])]),9])]),
    [iquote('copy,6,flip.1,demod,9,flip.1')] ).

cnf(14,plain,
    divide(identity,divide(identity,a2)) != a2,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[1]),13,11,9,11]),
    [iquote('back_demod,1,demod,13,11,9,11')] ).

cnf(15,plain,
    divide(identity,divide(divide(A,B),A)) = B,
    inference(para_into,[status(thm),theory(equality)],[3,9]),
    [iquote('para_into,3.1.1.1,8.1.1')] ).

cnf(29,plain,
    divide(identity,divide(identity,A)) = A,
    inference(para_into,[status(thm),theory(equality)],[15,9]),
    [iquote('para_into,15.1.1.2.1,8.1.1')] ).

cnf(31,plain,
    $false,
    inference(binary,[status(thm)],[29,14]),
    [iquote('binary,29.1,14.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : GRP538-1 : TPTP v8.1.0. Released v2.6.0.
% 0.07/0.12  % Command  : otter-tptp-script %s
% 0.13/0.33  % Computer : n020.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 300
% 0.13/0.33  % DateTime : Wed Jul 27 05:10:53 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 1.82/2.04  ----- Otter 3.3f, August 2004 -----
% 1.82/2.04  The process was started by sandbox on n020.cluster.edu,
% 1.82/2.04  Wed Jul 27 05:10:53 2022
% 1.82/2.04  The command was "./otter".  The process ID is 30677.
% 1.82/2.04  
% 1.82/2.04  set(prolog_style_variables).
% 1.82/2.04  set(auto).
% 1.82/2.04     dependent: set(auto1).
% 1.82/2.04     dependent: set(process_input).
% 1.82/2.04     dependent: clear(print_kept).
% 1.82/2.04     dependent: clear(print_new_demod).
% 1.82/2.04     dependent: clear(print_back_demod).
% 1.82/2.04     dependent: clear(print_back_sub).
% 1.82/2.04     dependent: set(control_memory).
% 1.82/2.04     dependent: assign(max_mem, 12000).
% 1.82/2.04     dependent: assign(pick_given_ratio, 4).
% 1.82/2.04     dependent: assign(stats_level, 1).
% 1.82/2.04     dependent: assign(max_seconds, 10800).
% 1.82/2.04  clear(print_given).
% 1.82/2.04  
% 1.82/2.04  list(usable).
% 1.82/2.04  0 [] A=A.
% 1.82/2.04  0 [] divide(divide(A,B),divide(divide(A,C),B))=C.
% 1.82/2.04  0 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.82/2.04  0 [] inverse(A)=divide(divide(B,B),A).
% 1.82/2.04  0 [] identity=divide(A,A).
% 1.82/2.04  0 [] multiply(multiply(inverse(b2),b2),a2)!=a2.
% 1.82/2.04  end_of_list.
% 1.82/2.04  
% 1.82/2.04  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.82/2.04  
% 1.82/2.04  All clauses are units, and equality is present; the
% 1.82/2.04  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.82/2.04  
% 1.82/2.04     dependent: set(knuth_bendix).
% 1.82/2.04     dependent: set(anl_eq).
% 1.82/2.04     dependent: set(para_from).
% 1.82/2.04     dependent: set(para_into).
% 1.82/2.04     dependent: clear(para_from_right).
% 1.82/2.04     dependent: clear(para_into_right).
% 1.82/2.04     dependent: set(para_from_vars).
% 1.82/2.04     dependent: set(eq_units_both_ways).
% 1.82/2.04     dependent: set(dynamic_demod_all).
% 1.82/2.04     dependent: set(dynamic_demod).
% 1.82/2.04     dependent: set(order_eq).
% 1.82/2.04     dependent: set(back_demod).
% 1.82/2.04     dependent: set(lrpo).
% 1.82/2.04  
% 1.82/2.04  ------------> process usable:
% 1.82/2.04  ** KEPT (pick-wt=8): 1 [] multiply(multiply(inverse(b2),b2),a2)!=a2.
% 1.82/2.04  
% 1.82/2.04  ------------> process sos:
% 1.82/2.04  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.82/2.04  ** KEPT (pick-wt=11): 3 [] divide(divide(A,B),divide(divide(A,C),B))=C.
% 1.82/2.04  ---> New Demodulator: 4 [new_demod,3] divide(divide(A,B),divide(divide(A,C),B))=C.
% 1.82/2.04  ** KEPT (pick-wt=11): 5 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.82/2.04  ** KEPT (pick-wt=8): 6 [] inverse(A)=divide(divide(B,B),A).
% 1.82/2.04  ** KEPT (pick-wt=5): 8 [copy,7,flip.1] divide(A,A)=identity.
% 1.82/2.04  ---> New Demodulator: 9 [new_demod,8] divide(A,A)=identity.
% 1.82/2.04    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.82/2.04  >>>> Starting back demodulation with 4.
% 1.82/2.04  ** KEPT (pick-wt=9): 10 [copy,5,flip.1,demod,9,flip.1] multiply(A,B)=divide(A,divide(identity,B)).
% 1.82/2.04  ---> New Demodulator: 11 [new_demod,10] multiply(A,B)=divide(A,divide(identity,B)).
% 1.82/2.04  ** KEPT (pick-wt=6): 12 [copy,6,flip.1,demod,9,flip.1] inverse(A)=divide(identity,A).
% 1.82/2.04  ---> New Demodulator: 13 [new_demod,12] inverse(A)=divide(identity,A).
% 1.82/2.04  >>>> Starting back demodulation with 9.
% 1.82/2.04      >> back demodulating 6 with 9.
% 1.82/2.04      >> back demodulating 5 with 9.
% 1.82/2.04  >>>> Starting back demodulation with 11.
% 1.82/2.04      >> back demodulating 1 with 11.
% 1.82/2.04  >>>> Starting back demodulation with 13.
% 1.82/2.04  
% 1.82/2.04  ======= end of input processing =======
% 1.82/2.04  
% 1.82/2.04  =========== start of search ===========
% 1.82/2.04  
% 1.82/2.04  -------- PROOF -------- 
% 1.82/2.04  
% 1.82/2.04  ----> UNIT CONFLICT at   0.00 sec ----> 31 [binary,29.1,14.1] $F.
% 1.82/2.04  
% 1.82/2.04  Length of proof is 6.  Level of proof is 3.
% 1.82/2.04  
% 1.82/2.04  ---------------- PROOF ----------------
% 1.82/2.04  % SZS status Unsatisfiable
% 1.82/2.04  % SZS output start Refutation
% See solution above
% 1.82/2.04  ------------ end of proof -------------
% 1.82/2.04  
% 1.82/2.04  
% 1.82/2.04  Search stopped by max_proofs option.
% 1.82/2.04  
% 1.82/2.04  
% 1.82/2.04  Search stopped by max_proofs option.
% 1.82/2.04  
% 1.82/2.04  ============ end of search ============
% 1.82/2.04  
% 1.82/2.04  -------------- statistics -------------
% 1.82/2.04  clauses given                  7
% 1.82/2.04  clauses generated             19
% 1.82/2.04  clauses kept                  18
% 1.82/2.04  clauses forward subsumed      15
% 1.82/2.04  clauses back subsumed          0
% 1.82/2.04  Kbytes malloced              976
% 1.82/2.04  
% 1.82/2.04  ----------- times (seconds) -----------
% 1.82/2.04  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.82/2.04  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.82/2.04  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.82/2.04  
% 1.82/2.04  That finishes the proof of the theorem.
% 1.82/2.04  
% 1.82/2.04  Process 30677 finished Wed Jul 27 05:10:55 2022
% 1.82/2.04  Otter interrupted
% 1.82/2.04  PROOF FOUND
%------------------------------------------------------------------------------