TSTP Solution File: GRP464-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP464-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:04 EDT 2022

% Result   : Unsatisfiable 1.92s 2.11s
% Output   : Refutation 1.92s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    4
% Syntax   : Number of clauses     :   12 (  12 unt;   0 nHn;   3 RR)
%            Number of literals    :   12 (  11 equ;   2 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    6 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :   16 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(identity,a2) != a2,
    file('GRP464-1.p',unknown),
    [] ).

cnf(3,axiom,
    divide(A,divide(divide(divide(divide(A,A),B),C),divide(divide(identity,A),C))) = B,
    file('GRP464-1.p',unknown),
    [] ).

cnf(6,axiom,
    multiply(A,B) = divide(A,divide(identity,B)),
    file('GRP464-1.p',unknown),
    [] ).

cnf(9,axiom,
    identity = divide(A,A),
    file('GRP464-1.p',unknown),
    [] ).

cnf(11,plain,
    divide(A,A) = identity,
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[9])]),
    [iquote('copy,9,flip.1')] ).

cnf(12,plain,
    divide(identity,divide(identity,a2)) != a2,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[1]),6]),
    [iquote('back_demod,1,demod,6')] ).

cnf(13,plain,
    divide(A,divide(divide(divide(identity,B),C),divide(divide(identity,A),C))) = B,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[3]),11]),
    [iquote('back_demod,3,demod,11')] ).

cnf(28,plain,
    divide(A,divide(divide(divide(identity,B),divide(identity,A)),identity)) = B,
    inference(para_into,[status(thm),theory(equality)],[13,11]),
    [iquote('para_into,13.1.1.2.2,10.1.1')] ).

cnf(31,plain,
    divide(A,identity) = A,
    inference(para_into,[status(thm),theory(equality)],[13,11]),
    [iquote('para_into,13.1.1.2,10.1.1')] ).

cnf(33,plain,
    divide(A,divide(divide(identity,B),divide(identity,A))) = B,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[28]),31]),
    [iquote('back_demod,28,demod,31')] ).

cnf(41,plain,
    divide(identity,divide(identity,A)) = A,
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[33,31]),31]),
    [iquote('para_into,33.1.1.2.2,30.1.1,demod,31')] ).

cnf(43,plain,
    $false,
    inference(binary,[status(thm)],[41,12]),
    [iquote('binary,41.1,12.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : GRP464-1 : TPTP v8.1.0. Released v2.6.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n026.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:40:24 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.92/2.11  ----- Otter 3.3f, August 2004 -----
% 1.92/2.11  The process was started by sandbox on n026.cluster.edu,
% 1.92/2.11  Wed Jul 27 05:40:24 2022
% 1.92/2.11  The command was "./otter".  The process ID is 22722.
% 1.92/2.11  
% 1.92/2.11  set(prolog_style_variables).
% 1.92/2.11  set(auto).
% 1.92/2.11     dependent: set(auto1).
% 1.92/2.11     dependent: set(process_input).
% 1.92/2.11     dependent: clear(print_kept).
% 1.92/2.11     dependent: clear(print_new_demod).
% 1.92/2.11     dependent: clear(print_back_demod).
% 1.92/2.11     dependent: clear(print_back_sub).
% 1.92/2.11     dependent: set(control_memory).
% 1.92/2.11     dependent: assign(max_mem, 12000).
% 1.92/2.11     dependent: assign(pick_given_ratio, 4).
% 1.92/2.11     dependent: assign(stats_level, 1).
% 1.92/2.11     dependent: assign(max_seconds, 10800).
% 1.92/2.11  clear(print_given).
% 1.92/2.11  
% 1.92/2.11  list(usable).
% 1.92/2.11  0 [] A=A.
% 1.92/2.11  0 [] divide(A,divide(divide(divide(divide(A,A),B),C),divide(divide(identity,A),C)))=B.
% 1.92/2.11  0 [] multiply(A,B)=divide(A,divide(identity,B)).
% 1.92/2.11  0 [] inverse(A)=divide(identity,A).
% 1.92/2.11  0 [] identity=divide(A,A).
% 1.92/2.11  0 [] multiply(identity,a2)!=a2.
% 1.92/2.11  end_of_list.
% 1.92/2.11  
% 1.92/2.11  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.92/2.11  
% 1.92/2.11  All clauses are units, and equality is present; the
% 1.92/2.11  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.92/2.11  
% 1.92/2.11     dependent: set(knuth_bendix).
% 1.92/2.11     dependent: set(anl_eq).
% 1.92/2.11     dependent: set(para_from).
% 1.92/2.11     dependent: set(para_into).
% 1.92/2.11     dependent: clear(para_from_right).
% 1.92/2.11     dependent: clear(para_into_right).
% 1.92/2.11     dependent: set(para_from_vars).
% 1.92/2.11     dependent: set(eq_units_both_ways).
% 1.92/2.11     dependent: set(dynamic_demod_all).
% 1.92/2.11     dependent: set(dynamic_demod).
% 1.92/2.11     dependent: set(order_eq).
% 1.92/2.11     dependent: set(back_demod).
% 1.92/2.11     dependent: set(lrpo).
% 1.92/2.11  
% 1.92/2.11  ------------> process usable:
% 1.92/2.11  ** KEPT (pick-wt=5): 1 [] multiply(identity,a2)!=a2.
% 1.92/2.11  
% 1.92/2.11  ------------> process sos:
% 1.92/2.11  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.92/2.11  ** KEPT (pick-wt=17): 3 [] divide(A,divide(divide(divide(divide(A,A),B),C),divide(divide(identity,A),C)))=B.
% 1.92/2.11  ---> New Demodulator: 4 [new_demod,3] divide(A,divide(divide(divide(divide(A,A),B),C),divide(divide(identity,A),C)))=B.
% 1.92/2.11  ** KEPT (pick-wt=9): 5 [] multiply(A,B)=divide(A,divide(identity,B)).
% 1.92/2.11  ---> New Demodulator: 6 [new_demod,5] multiply(A,B)=divide(A,divide(identity,B)).
% 1.92/2.11  ** KEPT (pick-wt=6): 7 [] inverse(A)=divide(identity,A).
% 1.92/2.11  ---> New Demodulator: 8 [new_demod,7] inverse(A)=divide(identity,A).
% 1.92/2.11  ** KEPT (pick-wt=5): 10 [copy,9,flip.1] divide(A,A)=identity.
% 1.92/2.11  ---> New Demodulator: 11 [new_demod,10] divide(A,A)=identity.
% 1.92/2.11    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.92/2.11  >>>> Starting back demodulation with 4.
% 1.92/2.11  >>>> Starting back demodulation with 6.
% 1.92/2.11      >> back demodulating 1 with 6.
% 1.92/2.11  >>>> Starting back demodulation with 8.
% 1.92/2.11  >>>> Starting back demodulation with 11.
% 1.92/2.11      >> back demodulating 3 with 11.
% 1.92/2.11  >>>> Starting back demodulation with 14.
% 1.92/2.11  
% 1.92/2.11  ======= end of input processing =======
% 1.92/2.11  
% 1.92/2.11  =========== start of search ===========
% 1.92/2.11  
% 1.92/2.11  -------- PROOF -------- 
% 1.92/2.11  
% 1.92/2.11  ----> UNIT CONFLICT at   0.00 sec ----> 43 [binary,41.1,12.1] $F.
% 1.92/2.11  
% 1.92/2.11  Length of proof is 7.  Level of proof is 5.
% 1.92/2.11  
% 1.92/2.11  ---------------- PROOF ----------------
% 1.92/2.11  % SZS status Unsatisfiable
% 1.92/2.11  % SZS output start Refutation
% See solution above
% 1.92/2.11  ------------ end of proof -------------
% 1.92/2.11  
% 1.92/2.11  
% 1.92/2.11  Search stopped by max_proofs option.
% 1.92/2.11  
% 1.92/2.11  
% 1.92/2.11  Search stopped by max_proofs option.
% 1.92/2.11  
% 1.92/2.11  ============ end of search ============
% 1.92/2.11  
% 1.92/2.11  -------------- statistics -------------
% 1.92/2.11  clauses given                  8
% 1.92/2.11  clauses generated             35
% 1.92/2.11  clauses kept                  24
% 1.92/2.11  clauses forward subsumed      23
% 1.92/2.11  clauses back subsumed          0
% 1.92/2.11  Kbytes malloced              976
% 1.92/2.11  
% 1.92/2.11  ----------- times (seconds) -----------
% 1.92/2.11  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.92/2.11  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.92/2.11  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.92/2.11  
% 1.92/2.11  That finishes the proof of the theorem.
% 1.92/2.11  
% 1.92/2.11  Process 22722 finished Wed Jul 27 05:40:25 2022
% 1.92/2.11  Otter interrupted
% 1.92/2.11  PROOF FOUND
%------------------------------------------------------------------------------