TSTP Solution File: GEO566+1 by Twee---2.4.2

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Twee---2.4.2
% Problem  : GEO566+1 : TPTP v8.1.2. Released v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 30 23:29:20 EDT 2023

% Result   : Theorem 11.30s 1.83s
% Output   : Proof 11.30s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem  : GEO566+1 : TPTP v8.1.2. Released v7.5.0.
% 0.12/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.34  % Computer : n012.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit : 300
% 0.14/0.34  % WCLimit  : 300
% 0.14/0.34  % DateTime : Tue Aug 29 21:10:23 EDT 2023
% 0.14/0.34  % CPUTime  : 
% 11.30/1.83  Command-line arguments: --no-flatten-goal
% 11.30/1.83  
% 11.30/1.83  % SZS status Theorem
% 11.30/1.83  
% 11.30/1.84  % SZS output start Proof
% 11.30/1.84  Take the following subset of the input axioms:
% 11.30/1.84    fof(exemplo6GDDFULL214028, conjecture, ![A, B, C, F, P, Q, H, T]: ((perp(F, C, A, B) & (coll(F, A, B) & (perp(B, C, A, H) & (perp(A, C, B, H) & (perp(T, F, B, C) & (coll(T, B, C) & (perp(Q, F, A, H) & (coll(Q, A, H) & (perp(P, F, A, C) & coll(P, A, C)))))))))) => coll(P, Q, T))).
% 11.30/1.84    fof(ruleD1, axiom, ![A2, B2, C2]: (coll(A2, B2, C2) => coll(A2, C2, B2))).
% 11.30/1.84    fof(ruleD19, axiom, ![D, U, V, B2, C2, A2_2, P2, Q2]: (eqangle(A2_2, B2, C2, D, P2, Q2, U, V) => eqangle(C2, D, A2_2, B2, U, V, P2, Q2))).
% 11.30/1.84    fof(ruleD2, axiom, ![B2, C2, A2_2]: (coll(A2_2, B2, C2) => coll(B2, A2_2, C2))).
% 11.30/1.84    fof(ruleD3, axiom, ![B2, C2, D2, A2_2]: ((coll(A2_2, B2, C2) & coll(A2_2, B2, D2)) => coll(C2, D2, A2_2))).
% 11.30/1.84    fof(ruleD39, axiom, ![B2, C2, D2, A2_2, P2, Q2]: (eqangle(A2_2, B2, P2, Q2, C2, D2, P2, Q2) => para(A2_2, B2, C2, D2))).
% 11.30/1.84    fof(ruleD40, axiom, ![B2, C2, D2, A2_2, P2, Q2]: (para(A2_2, B2, C2, D2) => eqangle(A2_2, B2, P2, Q2, C2, D2, P2, Q2))).
% 11.30/1.84    fof(ruleD66, axiom, ![B2, C2, A2_2]: (para(A2_2, B2, A2_2, C2) => coll(A2_2, B2, C2))).
% 11.30/1.84    fof(ruleD8, axiom, ![B2, C2, D2, A2_2]: (perp(A2_2, B2, C2, D2) => perp(C2, D2, A2_2, B2))).
% 11.30/1.84    fof(ruleD9, axiom, ![E, B2, C2, D2, F2, A2_2]: ((perp(A2_2, B2, C2, D2) & perp(C2, D2, E, F2)) => para(A2_2, B2, E, F2))).
% 11.30/1.84  
% 11.30/1.84  Now clausify the problem and encode Horn clauses using encoding 3 of
% 11.30/1.84  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 11.30/1.84  We repeatedly replace C & s=t => u=v by the two clauses:
% 11.30/1.84    fresh(y, y, x1...xn) = u
% 11.30/1.84    C => fresh(s, t, x1...xn) = v
% 11.30/1.84  where fresh is a fresh function symbol and x1..xn are the free
% 11.30/1.84  variables of u and v.
% 11.30/1.84  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 11.30/1.84  input problem has no model of domain size 1).
% 11.30/1.84  
% 11.30/1.84  The encoding turns the above axioms into the following unit equations and goals:
% 11.30/1.84  
% 11.30/1.84  Axiom 1 (exemplo6GDDFULL214028_6): perp(q, f, a, h) = true.
% 11.30/1.84  Axiom 2 (ruleD1): fresh146(X, X, Y, Z, W) = true.
% 11.30/1.84  Axiom 3 (ruleD2): fresh133(X, X, Y, Z, W) = true.
% 11.30/1.84  Axiom 4 (ruleD3): fresh119(X, X, Y, Z, W) = true.
% 11.30/1.84  Axiom 5 (ruleD66): fresh66(X, X, Y, Z, W) = true.
% 11.30/1.84  Axiom 6 (ruleD3): fresh120(X, X, Y, Z, W, V) = coll(W, V, Y).
% 11.30/1.84  Axiom 7 (ruleD39): fresh106(X, X, Y, Z, W, V) = true.
% 11.30/1.84  Axiom 8 (ruleD8): fresh52(X, X, Y, Z, W, V) = true.
% 11.30/1.84  Axiom 9 (ruleD9): fresh50(X, X, Y, Z, W, V) = true.
% 11.30/1.84  Axiom 10 (ruleD1): fresh146(coll(X, Y, Z), true, X, Y, Z) = coll(X, Z, Y).
% 11.30/1.84  Axiom 11 (ruleD2): fresh133(coll(X, Y, Z), true, X, Y, Z) = coll(Y, X, Z).
% 11.30/1.84  Axiom 12 (ruleD40): fresh104(X, X, Y, Z, W, V, U, T) = true.
% 11.30/1.84  Axiom 13 (ruleD9): fresh51(X, X, Y, Z, W, V, U, T) = para(Y, Z, U, T).
% 11.30/1.84  Axiom 14 (ruleD3): fresh120(coll(X, Y, Z), true, X, Y, W, Z) = fresh119(coll(X, Y, W), true, X, W, Z).
% 11.30/1.84  Axiom 15 (ruleD66): fresh66(para(X, Y, X, Z), true, X, Y, Z) = coll(X, Y, Z).
% 11.30/1.84  Axiom 16 (ruleD19): fresh134(X, X, Y, Z, W, V, U, T, S, X2) = true.
% 11.30/1.84  Axiom 17 (ruleD8): fresh52(perp(X, Y, Z, W), true, X, Y, Z, W) = perp(Z, W, X, Y).
% 11.30/1.84  Axiom 18 (ruleD40): fresh104(para(X, Y, Z, W), true, X, Y, Z, W, V, U) = eqangle(X, Y, V, U, Z, W, V, U).
% 11.30/1.84  Axiom 19 (ruleD9): fresh51(perp(X, Y, Z, W), true, V, U, X, Y, Z, W) = fresh50(perp(V, U, X, Y), true, V, U, Z, W).
% 11.30/1.84  Axiom 20 (ruleD39): fresh106(eqangle(X, Y, Z, W, V, U, Z, W), true, X, Y, V, U) = para(X, Y, V, U).
% 11.30/1.84  Axiom 21 (ruleD19): fresh134(eqangle(X, Y, Z, W, V, U, T, S), true, X, Y, Z, W, V, U, T, S) = eqangle(Z, W, X, Y, T, S, V, U).
% 11.30/1.84  
% 11.30/1.84  Lemma 22: coll(X, X, Y) = true.
% 11.30/1.84  Proof:
% 11.30/1.84    coll(X, X, Y)
% 11.30/1.84  = { by axiom 10 (ruleD1) R->L }
% 11.30/1.84    fresh146(coll(X, Y, X), true, X, Y, X)
% 11.30/1.84  = { by axiom 11 (ruleD2) R->L }
% 11.30/1.84    fresh146(fresh133(coll(Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.84  = { by axiom 15 (ruleD66) R->L }
% 11.30/1.84    fresh146(fresh133(fresh66(para(Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.84  = { by axiom 20 (ruleD39) R->L }
% 11.30/1.84    fresh146(fresh133(fresh66(fresh106(eqangle(Y, X, a, h, Y, X, a, h), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.84  = { by axiom 21 (ruleD19) R->L }
% 11.30/1.84    fresh146(fresh133(fresh66(fresh106(fresh134(eqangle(a, h, Y, X, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.84  = { by axiom 18 (ruleD40) R->L }
% 11.30/1.84    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(para(a, h, a, h), true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.84  = { by axiom 13 (ruleD9) R->L }
% 11.30/1.84    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(fresh51(true, true, a, h, q, f, a, h), true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.84  = { by axiom 1 (exemplo6GDDFULL214028_6) R->L }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(fresh51(perp(q, f, a, h), true, a, h, q, f, a, h), true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 19 (ruleD9) }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(fresh50(perp(a, h, q, f), true, a, h, a, h), true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 17 (ruleD8) R->L }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(fresh50(fresh52(perp(q, f, a, h), true, q, f, a, h), true, a, h, a, h), true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 1 (exemplo6GDDFULL214028_6) }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(fresh50(fresh52(true, true, q, f, a, h), true, a, h, a, h), true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 8 (ruleD8) }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(fresh50(true, true, a, h, a, h), true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 9 (ruleD9) }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(fresh134(fresh104(true, true, a, h, a, h, Y, X), true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 12 (ruleD40) }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(fresh134(true, true, a, h, Y, X, a, h, Y, X), true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 16 (ruleD19) }
% 11.30/1.85    fresh146(fresh133(fresh66(fresh106(true, true, Y, X, Y, X), true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 7 (ruleD39) }
% 11.30/1.85    fresh146(fresh133(fresh66(true, true, Y, X, X), true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 5 (ruleD66) }
% 11.30/1.85    fresh146(fresh133(true, true, Y, X, X), true, X, Y, X)
% 11.30/1.85  = { by axiom 3 (ruleD2) }
% 11.30/1.85    fresh146(true, true, X, Y, X)
% 11.30/1.85  = { by axiom 2 (ruleD1) }
% 11.30/1.85    true
% 11.30/1.85  
% 11.30/1.85  Goal 1 (exemplo6GDDFULL214028_10): coll(p, q, t) = true.
% 11.30/1.85  Proof:
% 11.30/1.85    coll(p, q, t)
% 11.30/1.85  = { by axiom 6 (ruleD3) R->L }
% 11.30/1.85    fresh120(true, true, t, t, p, q)
% 11.30/1.85  = { by lemma 22 R->L }
% 11.30/1.85    fresh120(coll(t, t, q), true, t, t, p, q)
% 11.30/1.85  = { by axiom 14 (ruleD3) }
% 11.30/1.85    fresh119(coll(t, t, p), true, t, p, q)
% 11.30/1.85  = { by lemma 22 }
% 11.30/1.85    fresh119(true, true, t, p, q)
% 11.30/1.85  = { by axiom 4 (ruleD3) }
% 11.30/1.85    true
% 11.30/1.85  % SZS output end Proof
% 11.30/1.85  
% 11.30/1.85  RESULT: Theorem (the conjecture is true).
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