%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : GEO227+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 06:23:42 EDT 2022

% Result   : Theorem 0.21s 0.48s
% Output   : Refutation 0.21s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   11 (   6 unt;   2 nHn;  11 RR)
%            Number of literals    :   16 (   0 equ;   7 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   4 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    equally_directed_lines(skc2,skc3),
    file('GEO227+3.p',unknown),
    [] ).

cnf(2,axiom,
    equally_directed_opposite_lines(skc2,skc3),
    file('GEO227+3.p',unknown),
    [] ).

cnf(19,axiom,
    ( unequally_directed_lines(u,v)
    | unequally_directed_lines(u,reverse_line(v)) ),
    file('GEO227+3.p',unknown),
    [] ).

cnf(21,axiom,
    ( ~ unequally_directed_lines(u,reverse_line(v))
    | unequally_directed_opposite_lines(u,v) ),
    file('GEO227+3.p',unknown),
    [] ).

cnf(26,axiom,
    ( ~ unequally_directed_lines(u,v)
    | ~ equally_directed_lines(u,v) ),
    file('GEO227+3.p',unknown),
    [] ).

cnf(27,axiom,
    ( ~ unequally_directed_opposite_lines(u,v)
    | ~ equally_directed_opposite_lines(u,v) ),
    file('GEO227+3.p',unknown),
    [] ).

cnf(73,plain,
    ~ unequally_directed_opposite_lines(skc2,skc3),
    inference(res,[status(thm),theory(equality)],[2,27]),
    [iquote('0:Res:2.0,27.0')] ).

cnf(74,plain,
    ~ unequally_directed_lines(skc2,skc3),
    inference(res,[status(thm),theory(equality)],[1,26]),
    [iquote('0:Res:1.0,26.0')] ).

cnf(82,plain,
    ( unequally_directed_lines(u,v)
    | unequally_directed_opposite_lines(u,v) ),
    inference(res,[status(thm),theory(equality)],[19,21]),
    [iquote('0:Res:19.1,21.0')] ).

cnf(84,plain,
    unequally_directed_opposite_lines(skc2,skc3),
    inference(res,[status(thm),theory(equality)],[82,74]),
    [iquote('0:Res:82.0,74.0')] ).

cnf(86,plain,
    $false,
    inference(mrr,[status(thm)],[84,73]),
    [iquote('0:MRR:84.0,73.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14  % Problem  : GEO227+3 : TPTP v8.1.0. Released v4.0.0.
% 0.08/0.14  % Command  : run_spass %d %s
% 0.14/0.36  % Computer : n029.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit : 300
% 0.14/0.36  % WCLimit  : 600
% 0.14/0.36  % DateTime : Sat Jun 18 14:46:29 EDT 2022
% 0.14/0.36  % CPUTime  : 
% 0.21/0.48  
% 0.21/0.48  SPASS V 3.9 
% 0.21/0.48  SPASS beiseite: Proof found.
% 0.21/0.48  % SZS status Theorem
% 0.21/0.48  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.21/0.48  SPASS derived 10 clauses, backtracked 0 clauses, performed 0 splits and kept 58 clauses.
% 0.21/0.48  SPASS allocated 97776 KBytes.
% 0.21/0.48  SPASS spent	0:00:00.11 on the problem.
% 0.21/0.48  		0:00:00.05 for the input.
% 0.21/0.48  		0:00:00.03 for the FLOTTER CNF translation.
% 0.21/0.48  		0:00:00.00 for inferences.
% 0.21/0.48  		0:00:00.00 for the backtracking.
% 0.21/0.48  		0:00:00.00 for the reduction.
% 0.21/0.48  
% 0.21/0.48  
% 0.21/0.48  Here is a proof with depth 2, length 11 :
% 0.21/0.48  % SZS output start Refutation
% See solution above
% 0.21/0.48  Formulae used in the proof : con ax8_basics a1_defns a4_defns a5_defns
% 0.21/0.48  
%------------------------------------------------------------------------------