TSTP Solution File: GEO080+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : GEO080+1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 06:17:57 EDT 2022

% Result   : Theorem 0.18s 0.49s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem  : GEO080+1 : TPTP v8.1.0. Released v2.4.0.
% 0.03/0.12  % Command  : sos-script %s
% 0.12/0.33  % Computer : n004.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jun 18 11:15:53 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.35  ----- Otter 3.2, August 2001 -----
% 0.12/0.35  The process was started by sandbox2 on n004.cluster.edu,
% 0.12/0.35  Sat Jun 18 11:15:53 2022
% 0.12/0.35  The command was "./sos".  The process ID is 16394.
% 0.12/0.35  
% 0.12/0.35  set(prolog_style_variables).
% 0.12/0.35  set(auto).
% 0.12/0.35     dependent: set(auto1).
% 0.12/0.35     dependent: set(process_input).
% 0.12/0.35     dependent: clear(print_kept).
% 0.12/0.35     dependent: clear(print_new_demod).
% 0.12/0.35     dependent: clear(print_back_demod).
% 0.12/0.35     dependent: clear(print_back_sub).
% 0.12/0.35     dependent: set(control_memory).
% 0.12/0.35     dependent: assign(max_mem, 12000).
% 0.12/0.35     dependent: assign(pick_given_ratio, 4).
% 0.12/0.35     dependent: assign(stats_level, 1).
% 0.12/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35     dependent: assign(sos_limit, 5000).
% 0.12/0.35     dependent: assign(max_weight, 60).
% 0.12/0.35  clear(print_given).
% 0.12/0.35  
% 0.12/0.35  formula_list(usable).
% 0.12/0.35  
% 0.12/0.35  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=12.
% 0.12/0.35  
% 0.12/0.35  This ia a non-Horn set with equality.  The strategy will be
% 0.12/0.35  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.35  unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.35  clauses in usable.
% 0.12/0.35  
% 0.12/0.35     dependent: set(knuth_bendix).
% 0.12/0.35     dependent: set(para_from).
% 0.12/0.35     dependent: set(para_into).
% 0.12/0.35     dependent: clear(para_from_right).
% 0.12/0.35     dependent: clear(para_into_right).
% 0.12/0.35     dependent: set(para_from_vars).
% 0.12/0.35     dependent: set(eq_units_both_ways).
% 0.12/0.35     dependent: set(dynamic_demod_all).
% 0.12/0.35     dependent: set(dynamic_demod).
% 0.12/0.35     dependent: set(order_eq).
% 0.12/0.35     dependent: set(back_demod).
% 0.12/0.35     dependent: set(lrpo).
% 0.12/0.35     dependent: set(hyper_res).
% 0.12/0.35     dependent: set(unit_deletion).
% 0.12/0.35     dependent: set(factor).
% 0.12/0.35  
% 0.12/0.35  ------------> process usable:
% 0.12/0.35  
% 0.12/0.35  ------------> process sos:
% 0.12/0.35    Following clause subsumed by 58 during input processing: 0 [copy,58,flip.1] {-} A=A.
% 0.12/0.35  58 back subsumes 52.
% 0.12/0.35  58 back subsumes 51.
% 0.12/0.35  
% 0.12/0.35  ======= end of input processing =======
% 0.18/0.41  
% 0.18/0.41  Model 1 (0.00 seconds, 0 Inserts)
% 0.18/0.41  
% 0.18/0.41  Stopped by limit on number of solutions
% 0.18/0.41  
% 0.18/0.41  
% 0.18/0.41  -------------- Softie stats --------------
% 0.18/0.41  
% 0.18/0.41  UPDATE_STOP: 300
% 0.18/0.41  SFINDER_TIME_LIMIT: 2
% 0.18/0.41  SHORT_CLAUSE_CUTOFF: 4
% 0.18/0.41  number of clauses in intial UL: 47
% 0.18/0.41  number of clauses initially in problem: 57
% 0.18/0.41  percentage of clauses intially in UL: 82
% 0.18/0.41  percentage of distinct symbols occuring in initial UL: 91
% 0.18/0.41  percent of all initial clauses that are short: 100
% 0.18/0.41  absolute distinct symbol count: 23
% 0.18/0.41     distinct predicate count: 8
% 0.18/0.41     distinct function count: 14
% 0.18/0.41     distinct constant count: 1
% 0.18/0.41  
% 0.18/0.41  ---------- no more Softie stats ----------
% 0.18/0.41  
% 0.18/0.41  
% 0.18/0.41  
% 0.18/0.41  =========== start of search ===========
% 0.18/0.49  
% 0.18/0.49  -------- PROOF -------- 
% 0.18/0.49  % SZS status Theorem
% 0.18/0.49  % SZS output start Refutation
% 0.18/0.49  
% 0.18/0.49  Model 2 [ 6 3 14875 ] (0.00 seconds, 26036 Inserts)
% 0.18/0.49  
% 0.18/0.49  ----> UNIT CONFLICT at   0.12 sec ----> 113 [binary,112.1,42.1] {+} $F.
% 0.18/0.49  
% 0.18/0.49  Length of proof is 2.  Level of proof is 2.
% 0.18/0.49  
% 0.18/0.49  ---------------- PROOF ----------------
% 0.18/0.49  % SZS status Theorem
% 0.18/0.49  % SZS output start Refutation
% 0.18/0.49  
% 0.18/0.49  2 [] {+} part_of(A,B)| -incident_c($f1(B,A),B).
% 0.18/0.49  42 [] {+} -part_of($c1,$c1).
% 0.18/0.49  53 [] {-} part_of(A,B)|incident_c($f1(B,A),A).
% 0.18/0.49  63 [hyper,53,42] {-} incident_c($f1($c1,$c1),$c1).
% 0.18/0.49  112 [hyper,63,2] {-} part_of($c1,$c1).
% 0.18/0.49  113 [binary,112.1,42.1] {+} $F.
% 0.18/0.49  
% 0.18/0.49  % SZS output end Refutation
% 0.18/0.49  ------------ end of proof -------------
% 0.18/0.49  
% 0.18/0.49  
% 0.18/0.49  Search stopped by max_proofs option.
% 0.18/0.49  
% 0.18/0.49  
% 0.18/0.49  Search stopped by max_proofs option.
% 0.18/0.49  
% 0.18/0.49  ============ end of search ============
% 0.18/0.49  
% 0.18/0.49  ----------- soft-scott stats ----------
% 0.18/0.49  
% 0.18/0.49  true clauses given           0      (0.0%)
% 0.18/0.49  false clauses given          4
% 0.18/0.49  
% 0.18/0.49        FALSE     TRUE
% 0.18/0.49     3  0         1
% 0.18/0.49     6  1         0
% 0.18/0.49     9  0         1
% 0.18/0.49    10  0         5
% 0.18/0.49    11  2         3
% 0.18/0.49    12  0         1
% 0.18/0.49    13  1         0
% 0.18/0.49    15  2         3
% 0.18/0.49    16  1         1
% 0.18/0.49    17  3         0
% 0.18/0.49    18  0         2
% 0.18/0.49    20  5         5
% 0.18/0.49    22  0         3
% 0.18/0.49    23  1         0
% 0.18/0.49    25  0         3
% 0.18/0.49    26  2         0
% 0.18/0.49  tot:  18        28      (60.9% true)
% 0.18/0.49  
% 0.18/0.49  
% 0.18/0.49  Model 2 [ 6 -3 14875 ] (0.00 seconds, 26036 Inserts)
% 0.18/0.49  
% 0.18/0.49  That finishes the proof of the theorem.
% 0.18/0.49  
% 0.18/0.49  Process 16394 finished Sat Jun 18 11:15:53 2022
%------------------------------------------------------------------------------