TSTP Solution File: GEO080+1 by Duper---1.0
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% File : Duper---1.0
% Problem : GEO080+1 : TPTP v8.1.2. Released v2.4.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n010.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 30 22:54:58 EDT 2023
% Result : Theorem 5.93s 6.13s
% Output : Proof 5.93s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.17 % Problem : GEO080+1 : TPTP v8.1.2. Released v2.4.0.
% 0.11/0.18 % Command : duper %s
% 0.18/0.39 % Computer : n010.cluster.edu
% 0.18/0.39 % Model : x86_64 x86_64
% 0.18/0.39 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.18/0.39 % Memory : 8042.1875MB
% 0.18/0.39 % OS : Linux 3.10.0-693.el7.x86_64
% 0.18/0.39 % CPULimit : 300
% 0.18/0.39 % WCLimit : 300
% 0.18/0.39 % DateTime : Tue Aug 29 22:34:49 EDT 2023
% 0.18/0.40 % CPUTime :
% 5.93/6.13 SZS status Theorem for theBenchmark.p
% 5.93/6.13 SZS output start Proof for theBenchmark.p
% 5.93/6.13 Clause #0 (by assumption #[]): Eq (∀ (C C1 : Iota), Iff (part_of C1 C) (∀ (P : Iota), incident_c P C1 → incident_c P C)) True
% 5.93/6.13 Clause #16 (by assumption #[]): Eq (Not (∀ (C : Iota), part_of C C)) True
% 5.93/6.13 Clause #17 (by clausification #[16]): Eq (∀ (C : Iota), part_of C C) False
% 5.93/6.13 Clause #18 (by clausification #[17]): ∀ (a : Iota), Eq (Not (part_of (skS.0 0 a) (skS.0 0 a))) True
% 5.93/6.13 Clause #19 (by clausification #[18]): ∀ (a : Iota), Eq (part_of (skS.0 0 a) (skS.0 0 a)) False
% 5.93/6.13 Clause #39 (by clausification #[0]): ∀ (a : Iota), Eq (∀ (C1 : Iota), Iff (part_of C1 a) (∀ (P : Iota), incident_c P C1 → incident_c P a)) True
% 5.93/6.13 Clause #40 (by clausification #[39]): ∀ (a a_1 : Iota), Eq (Iff (part_of a a_1) (∀ (P : Iota), incident_c P a → incident_c P a_1)) True
% 5.93/6.13 Clause #41 (by clausification #[40]): ∀ (a a_1 : Iota), Or (Eq (part_of a a_1) True) (Eq (∀ (P : Iota), incident_c P a → incident_c P a_1) False)
% 5.93/6.13 Clause #43 (by clausification #[41]): ∀ (a a_1 a_2 : Iota),
% 5.93/6.13 Or (Eq (part_of a a_1) True) (Eq (Not (incident_c (skS.0 3 a a_1 a_2) a → incident_c (skS.0 3 a a_1 a_2) a_1)) True)
% 5.93/6.13 Clause #44 (by clausification #[43]): ∀ (a a_1 a_2 : Iota),
% 5.93/6.13 Or (Eq (part_of a a_1) True) (Eq (incident_c (skS.0 3 a a_1 a_2) a → incident_c (skS.0 3 a a_1 a_2) a_1) False)
% 5.93/6.13 Clause #45 (by clausification #[44]): ∀ (a a_1 a_2 : Iota), Or (Eq (part_of a a_1) True) (Eq (incident_c (skS.0 3 a a_1 a_2) a) True)
% 5.93/6.13 Clause #46 (by clausification #[44]): ∀ (a a_1 a_2 : Iota), Or (Eq (part_of a a_1) True) (Eq (incident_c (skS.0 3 a a_1 a_2) a_1) False)
% 5.93/6.13 Clause #129 (by superposition #[46, 45]): ∀ (a : Iota), Or (Eq (part_of a a) True) (Or (Eq (part_of a a) True) (Eq False True))
% 5.93/6.13 Clause #145 (by clausification #[129]): ∀ (a : Iota), Or (Eq (part_of a a) True) (Eq (part_of a a) True)
% 5.93/6.13 Clause #146 (by eliminate duplicate literals #[145]): ∀ (a : Iota), Eq (part_of a a) True
% 5.93/6.13 Clause #147 (by superposition #[146, 19]): Eq True False
% 5.93/6.13 Clause #149 (by clausification #[147]): False
% 5.93/6.13 SZS output end Proof for theBenchmark.p
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