%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : DAT159^1 : TPTP v8.1.2. Released v7.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 30 22:12:24 EDT 2023

% Result   : Theorem 6.25s 6.51s
% Output   : Proof 6.25s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : DAT159^1 : TPTP v8.1.2. Released v7.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.14/0.34  % Computer : n014.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Thu Aug 24 14:18:34 EDT 2023
% 0.20/0.34  % CPUTime    : 
% 6.25/6.51  SZS status Theorem for theBenchmark.p
% 6.25/6.51  SZS output start Proof for theBenchmark.p
% 6.25/6.51  Clause #0 (by assumption #[]): Eq (Not (hammin1195055315smooth (zero_zero nat))) True
% 6.25/6.51  Clause #1 (by assumption #[]): Eq (∀ (N : nat), Eq (Ne N (zero_zero nat)) (ord_less nat (zero_zero nat) N)) True
% 6.25/6.51  Clause #298 (by assumption #[]): Eq (hammin1195055315smooth n) True
% 6.25/6.51  Clause #299 (by assumption #[]): Eq (Not (ord_less nat (zero_zero nat) n)) True
% 6.25/6.51  Clause #300 (by clausification #[0]): Eq (hammin1195055315smooth (zero_zero nat)) False
% 6.25/6.51  Clause #301 (by clausification #[1]): ∀ (a : nat), Eq (Eq (Ne a (zero_zero nat)) (ord_less nat (zero_zero nat) a)) True
% 6.25/6.51  Clause #302 (by clausification #[301]): ∀ (a : nat), Eq (Ne a (zero_zero nat)) (ord_less nat (zero_zero nat) a)
% 6.25/6.51  Clause #304 (by clausify Prop equality #[302]): ∀ (a : nat), Or (Eq (Ne a (zero_zero nat)) False) (Eq (ord_less nat (zero_zero nat) a) True)
% 6.25/6.51  Clause #316 (by clausification #[304]): ∀ (a : nat), Or (Eq (ord_less nat (zero_zero nat) a) True) (Eq a (zero_zero nat))
% 6.25/6.51  Clause #1828 (by clausification #[299]): Eq (ord_less nat (zero_zero nat) n) False
% 6.25/6.51  Clause #1829 (by superposition #[1828, 316]): Or (Eq False True) (Eq n (zero_zero nat))
% 6.25/6.51  Clause #1840 (by clausification #[1829]): Eq n (zero_zero nat)
% 6.25/6.51  Clause #1841 (by backward demodulation #[1840, 300]): Eq (hammin1195055315smooth n) False
% 6.25/6.51  Clause #1867 (by superposition #[1841, 298]): Eq False True
% 6.25/6.51  Clause #1964 (by clausification #[1867]): False
% 6.25/6.51  SZS output end Proof for theBenchmark.p
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