TSTP Solution File: DAT062_1 by SPASS+T---2.2.22
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% File : SPASS+T---2.2.22
% Problem : DAT062_1 : TPTP v8.1.0. Released v5.5.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n014.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 01:32:02 EDT 2022
% Result : Theorem 0.80s 1.07s
% Output : Refutation 0.80s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : DAT062_1 : TPTP v8.1.0. Released v5.5.0.
% 0.06/0.13 % Command : spasst-tptp-script %s %d
% 0.12/0.34 % Computer : n014.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Fri Jul 1 16:57:10 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.19/0.47 % Using integer theory
% 0.80/1.07
% 0.80/1.07
% 0.80/1.07 % SZS status Theorem for /tmp/SPASST_18367_n014.cluster.edu
% 0.80/1.07
% 0.80/1.07 SPASS V 2.2.22 in combination with yices.
% 0.80/1.07 SPASS beiseite: Proof found by SPASS and SMT.
% 0.80/1.07 Problem: /tmp/SPASST_18367_n014.cluster.edu
% 0.80/1.07 SPASS derived 140 clauses, backtracked 54 clauses and kept 186 clauses.
% 0.80/1.07 SPASS backtracked 2 times (1 times due to theory inconsistency).
% 0.80/1.07 SPASS allocated 6374 KBytes.
% 0.80/1.07 SPASS spent 0:00:00.03 on the problem.
% 0.80/1.07 0:00:00.00 for the input.
% 0.80/1.07 0:00:00.01 for the FLOTTER CNF translation.
% 0.80/1.07 0:00:00.00 for inferences.
% 0.80/1.07 0:00:00.00 for the backtracking.
% 0.80/1.07 0:00:00.01 for the reduction.
% 0.80/1.07 0:00:00.00 for interacting with the SMT procedure.
% 0.80/1.07
% 0.80/1.07
% 0.80/1.07 % SZS output start CNFRefutation for /tmp/SPASST_18367_n014.cluster.edu
% 0.80/1.07
% 0.80/1.07 % Here is a proof with depth 0, length 8 :
% 0.80/1.07 5[0:Inp] || -> heap(skc5)*.
% 0.80/1.07 6[0:Inp] || -> heap(skc4)*.
% 0.80/1.07 8[0:Inp] || -> lsls(skc5,app(skc4,skc6))*.
% 0.80/1.07 13[0:Inp] || less(length(skc5),length(app(skc4,skc6)))* -> .
% 0.80/1.07 17[0:Inp] || heap(U) -> equal(length(app(U,V)),plus(1,length(U)))**.
% 0.80/1.07 18(e)[0:Inp] || heap(U) lsls(U,skc4) -> less(length(U),length(skc4))*.
% 0.80/1.07 24(e)[0:Inp] || heap(U) heap(V) lsls(U,app(V,W))* -> lsls(U,V) equal(U,V).
% 0.80/1.07 251(e)[0:ThR:24,18,17,13,8,6,5] || -> .
% 0.80/1.07
% 0.80/1.07 % SZS output end CNFRefutation for /tmp/SPASST_18367_n014.cluster.edu
% 0.80/1.07
% 0.80/1.07 Formulae used in the proof : fof_heap_type fof_th_lem_1a fof_ax_22 fof_app_type fof_ax_17 fof_ax_23 fof_ax_19
% 0.80/1.07
% 0.80/1.08 SPASS+T ended
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