TSTP Solution File: DAT062_1 by SPASS+T---2.2.22

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS+T---2.2.22
% Problem  : DAT062_1 : TPTP v8.1.0. Released v5.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : spasst-tptp-script %s %d

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 01:32:02 EDT 2022

% Result   : Theorem 0.80s 1.07s
% Output   : Refutation 0.80s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : DAT062_1 : TPTP v8.1.0. Released v5.5.0.
% 0.06/0.13  % Command  : spasst-tptp-script %s %d
% 0.12/0.34  % Computer : n014.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Fri Jul  1 16:57:10 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.19/0.47  % Using integer theory
% 0.80/1.07  
% 0.80/1.07  
% 0.80/1.07  % SZS status Theorem for /tmp/SPASST_18367_n014.cluster.edu
% 0.80/1.07  
% 0.80/1.07  SPASS V 2.2.22  in combination with yices.
% 0.80/1.07  SPASS beiseite: Proof found by SPASS and SMT.
% 0.80/1.07  Problem: /tmp/SPASST_18367_n014.cluster.edu 
% 0.80/1.07  SPASS derived 140 clauses, backtracked 54 clauses and kept 186 clauses.
% 0.80/1.07  SPASS backtracked 2 times (1 times due to theory inconsistency).
% 0.80/1.07  SPASS allocated 6374 KBytes.
% 0.80/1.07  SPASS spent	0:00:00.03 on the problem.
% 0.80/1.07  		0:00:00.00 for the input.
% 0.80/1.07  		0:00:00.01 for the FLOTTER CNF translation.
% 0.80/1.07  		0:00:00.00 for inferences.
% 0.80/1.07  		0:00:00.00 for the backtracking.
% 0.80/1.07  		0:00:00.01 for the reduction.
% 0.80/1.07  		0:00:00.00 for interacting with the SMT procedure.
% 0.80/1.07  		
% 0.80/1.07  
% 0.80/1.07  % SZS output start CNFRefutation for /tmp/SPASST_18367_n014.cluster.edu
% 0.80/1.07  
% 0.80/1.07  % Here is a proof with depth 0, length 8 :
% 0.80/1.07  5[0:Inp] ||  -> heap(skc5)*.
% 0.80/1.07  6[0:Inp] ||  -> heap(skc4)*.
% 0.80/1.07  8[0:Inp] ||  -> lsls(skc5,app(skc4,skc6))*.
% 0.80/1.07  13[0:Inp] || less(length(skc5),length(app(skc4,skc6)))* -> .
% 0.80/1.07  17[0:Inp] || heap(U) -> equal(length(app(U,V)),plus(1,length(U)))**.
% 0.80/1.07  18(e)[0:Inp] || heap(U) lsls(U,skc4) -> less(length(U),length(skc4))*.
% 0.80/1.07  24(e)[0:Inp] || heap(U) heap(V) lsls(U,app(V,W))* -> lsls(U,V) equal(U,V).
% 0.80/1.07  251(e)[0:ThR:24,18,17,13,8,6,5] ||  -> .
% 0.80/1.07  
% 0.80/1.07  % SZS output end CNFRefutation for /tmp/SPASST_18367_n014.cluster.edu
% 0.80/1.07  
% 0.80/1.07  Formulae used in the proof : fof_heap_type fof_th_lem_1a fof_ax_22 fof_app_type fof_ax_17 fof_ax_23 fof_ax_19
% 0.80/1.07  
% 0.80/1.08  SPASS+T ended
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