TSTP Solution File: CSR069+2 by Twee---2.4.2
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : CSR069+2 : TPTP v8.1.2. Released v3.4.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 30 21:41:41 EDT 2023
% Result : Theorem 24.66s 3.62s
% Output : Proof 24.93s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : CSR069+2 : TPTP v8.1.2. Released v3.4.0.
% 0.00/0.13 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.34 % Computer : n008.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Mon Aug 28 12:04:32 EDT 2023
% 0.14/0.34 % CPUTime :
% 24.66/3.62 Command-line arguments: --flip-ordering --lhs-weight 1 --depth-weight 60 --distributivity-heuristic
% 24.66/3.62
% 24.66/3.62 % SZS status Theorem
% 24.66/3.62
% 24.66/3.62 % SZS output start Proof
% 24.66/3.62 Take the following subset of the input axioms:
% 24.93/3.62 fof(ax1_463, axiom, mtvisible(c_tptpgeo_member1_mt) => borderson(c_georegion_l4_x38_y24, c_georegion_l4_x39_y24)).
% 24.93/3.62 fof(query119, conjecture, mtvisible(c_tptpgeo_member1_mt) => borderson(c_georegion_l4_x38_y24, c_georegion_l4_x39_y24)).
% 24.93/3.62
% 24.93/3.63 Now clausify the problem and encode Horn clauses using encoding 3 of
% 24.93/3.63 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 24.93/3.63 We repeatedly replace C & s=t => u=v by the two clauses:
% 24.93/3.63 fresh(y, y, x1...xn) = u
% 24.93/3.63 C => fresh(s, t, x1...xn) = v
% 24.93/3.63 where fresh is a fresh function symbol and x1..xn are the free
% 24.93/3.63 variables of u and v.
% 24.93/3.63 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 24.93/3.63 input problem has no model of domain size 1).
% 24.93/3.63
% 24.93/3.63 The encoding turns the above axioms into the following unit equations and goals:
% 24.93/3.63
% 24.93/3.63 Axiom 1 (query119): mtvisible(c_tptpgeo_member1_mt) = true2.
% 24.93/3.63 Axiom 2 (ax1_463): fresh501(X, X) = true2.
% 24.93/3.63 Axiom 3 (ax1_463): fresh501(mtvisible(c_tptpgeo_member1_mt), true2) = borderson(c_georegion_l4_x38_y24, c_georegion_l4_x39_y24).
% 24.93/3.63
% 24.93/3.63 Goal 1 (query119_1): borderson(c_georegion_l4_x38_y24, c_georegion_l4_x39_y24) = true2.
% 24.93/3.63 Proof:
% 24.93/3.63 borderson(c_georegion_l4_x38_y24, c_georegion_l4_x39_y24)
% 24.93/3.63 = { by axiom 3 (ax1_463) R->L }
% 24.93/3.63 fresh501(mtvisible(c_tptpgeo_member1_mt), true2)
% 24.93/3.63 = { by axiom 1 (query119) }
% 24.93/3.63 fresh501(true2, true2)
% 24.93/3.63 = { by axiom 2 (ax1_463) }
% 24.93/3.63 true2
% 24.93/3.63 % SZS output end Proof
% 24.93/3.63
% 24.93/3.63 RESULT: Theorem (the conjecture is true).
%------------------------------------------------------------------------------