TSTP Solution File: CSR058+2 by Twee---2.4.2
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : CSR058+2 : TPTP v8.1.2. Released v3.4.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n024.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 30 21:41:31 EDT 2023
% Result : Theorem 24.74s 3.50s
% Output : Proof 24.74s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : CSR058+2 : TPTP v8.1.2. Released v3.4.0.
% 0.06/0.12 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.12/0.33 % Computer : n024.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Mon Aug 28 08:59:53 EDT 2023
% 0.12/0.33 % CPUTime :
% 24.74/3.50 Command-line arguments: --kbo-weight0 --lhs-weight 5 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --goal-heuristic
% 24.74/3.50
% 24.74/3.50 % SZS status Theorem
% 24.74/3.50
% 24.74/3.50 % SZS output start Proof
% 24.74/3.50 Take the following subset of the input axioms:
% 24.74/3.50 fof(ax1_126, axiom, mtvisible(c_englishmt) => prettystring(f_subcollectionofwithrelationfromtypefn(c_terrorist, c_hasmembers, c_terroristgroup), s_terroristthathasbeenamemberofaterroristorganization)).
% 24.74/3.50 fof(ax1_153, axiom, ![OBJ]: ~(tptpcol_1_1(OBJ) & tptpcol_1_65536(OBJ))).
% 24.74/3.50 fof(ax1_167, axiom, ![OBJ2]: ~(individual(OBJ2) & setorcollection(OBJ2))).
% 24.74/3.50 fof(ax1_289, axiom, ![OBJ2]: ~(collection(OBJ2) & individual(OBJ2))).
% 24.74/3.50 fof(ax1_3, axiom, ![OBJ2]: ~(intangible(OBJ2) & partiallytangible(OBJ2))).
% 24.74/3.50 fof(ax1_363, axiom, ![COL1, COL2, OBJ2]: ~(isa(OBJ2, COL1) & (isa(OBJ2, COL2) & disjointwith(COL1, COL2)))).
% 24.74/3.50 fof(ax1_488, axiom, ![OBJ2]: ~(tptpcol_3_98305(OBJ2) & tptpcol_3_114688(OBJ2))).
% 24.74/3.50 fof(ax1_521, axiom, ![X]: ~affiliatedwith(X, X)).
% 24.74/3.50 fof(ax1_698, axiom, ![X2]: ~objectfoundinlocation(X2, X2)).
% 24.74/3.50 fof(ax1_901, axiom, ![X2]: ~borderson(X2, X2)).
% 24.74/3.50 fof(query108, conjecture, ?[X2]: (mtvisible(c_englishmt) => prettystring(f_subcollectionofwithrelationfromtypefn(c_terrorist, c_hasmembers, c_terroristgroup), X2))).
% 24.74/3.50
% 24.74/3.50 Now clausify the problem and encode Horn clauses using encoding 3 of
% 24.74/3.50 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 24.74/3.50 We repeatedly replace C & s=t => u=v by the two clauses:
% 24.74/3.50 fresh(y, y, x1...xn) = u
% 24.74/3.50 C => fresh(s, t, x1...xn) = v
% 24.74/3.50 where fresh is a fresh function symbol and x1..xn are the free
% 24.74/3.50 variables of u and v.
% 24.74/3.50 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 24.74/3.50 input problem has no model of domain size 1).
% 24.74/3.50
% 24.74/3.50 The encoding turns the above axioms into the following unit equations and goals:
% 24.74/3.50
% 24.74/3.50 Axiom 1 (query108): mtvisible(c_englishmt) = true2.
% 24.74/3.50 Axiom 2 (ax1_126): fresh665(X, X) = true2.
% 24.74/3.50 Axiom 3 (ax1_126): fresh665(mtvisible(c_englishmt), true2) = prettystring(f_subcollectionofwithrelationfromtypefn(c_terrorist, c_hasmembers, c_terroristgroup), s_terroristthathasbeenamemberofaterroristorganization).
% 24.74/3.50
% 24.74/3.50 Goal 1 (query108_1): prettystring(f_subcollectionofwithrelationfromtypefn(c_terrorist, c_hasmembers, c_terroristgroup), X) = true2.
% 24.74/3.50 The goal is true when:
% 24.74/3.50 X = s_terroristthathasbeenamemberofaterroristorganization
% 24.74/3.50
% 24.74/3.50 Proof:
% 24.74/3.50 prettystring(f_subcollectionofwithrelationfromtypefn(c_terrorist, c_hasmembers, c_terroristgroup), s_terroristthathasbeenamemberofaterroristorganization)
% 24.74/3.50 = { by axiom 3 (ax1_126) R->L }
% 24.74/3.50 fresh665(mtvisible(c_englishmt), true2)
% 24.74/3.50 = { by axiom 1 (query108) }
% 24.74/3.50 fresh665(true2, true2)
% 24.74/3.50 = { by axiom 2 (ax1_126) }
% 24.74/3.50 true2
% 24.74/3.50 % SZS output end Proof
% 24.74/3.50
% 24.74/3.50 RESULT: Theorem (the conjecture is true).
%------------------------------------------------------------------------------