TSTP Solution File: CSR042+2 by Twee---2.4.2
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%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : CSR042+2 : TPTP v8.1.2. Released v3.4.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n023.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 30 21:41:16 EDT 2023
% Result : Theorem 37.90s 5.19s
% Output : Proof 37.90s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14 % Problem : CSR042+2 : TPTP v8.1.2. Released v3.4.0.
% 0.08/0.15 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.16/0.37 % Computer : n023.cluster.edu
% 0.16/0.37 % Model : x86_64 x86_64
% 0.16/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.37 % Memory : 8042.1875MB
% 0.16/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.16/0.37 % CPULimit : 300
% 0.16/0.37 % WCLimit : 300
% 0.16/0.37 % DateTime : Mon Aug 28 10:02:25 EDT 2023
% 0.16/0.37 % CPUTime :
% 37.90/5.19 Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10
% 37.90/5.19
% 37.90/5.19 % SZS status Theorem
% 37.90/5.19
% 37.90/5.20 % SZS output start Proof
% 37.90/5.20 Take the following subset of the input axioms:
% 37.90/5.20 fof(ax1_122, axiom, mtvisible(c_tptpgeo_member7_mt) => borderson(c_georegion_l4_x27_y64, c_georegion_l4_x27_y65)).
% 37.90/5.20 fof(ax1_153, axiom, ![OBJ]: ~(tptpcol_1_1(OBJ) & tptpcol_1_65536(OBJ))).
% 37.90/5.20 fof(ax1_167, axiom, ![OBJ2]: ~(individual(OBJ2) & setorcollection(OBJ2))).
% 37.90/5.20 fof(ax1_289, axiom, ![OBJ2]: ~(collection(OBJ2) & individual(OBJ2))).
% 37.90/5.20 fof(ax1_3, axiom, ![OBJ2]: ~(intangible(OBJ2) & partiallytangible(OBJ2))).
% 37.90/5.20 fof(ax1_363, axiom, ![COL1, COL2, OBJ2]: ~(isa(OBJ2, COL1) & (isa(OBJ2, COL2) & disjointwith(COL1, COL2)))).
% 37.90/5.20 fof(ax1_488, axiom, ![OBJ2]: ~(tptpcol_3_98305(OBJ2) & tptpcol_3_114688(OBJ2))).
% 37.90/5.20 fof(ax1_521, axiom, ![X]: ~affiliatedwith(X, X)).
% 37.90/5.20 fof(ax1_698, axiom, ![X2]: ~objectfoundinlocation(X2, X2)).
% 37.90/5.20 fof(ax1_900, axiom, ![Y, X2]: (borderson(X2, Y) => borderson(Y, X2))).
% 37.90/5.20 fof(ax1_901, axiom, ![X2]: ~borderson(X2, X2)).
% 37.90/5.20 fof(query92, conjecture, ?[ARG1]: (mtvisible(c_tptpgeo_member7_mt) => borderson(ARG1, c_georegion_l4_x27_y64))).
% 37.90/5.20
% 37.90/5.20 Now clausify the problem and encode Horn clauses using encoding 3 of
% 37.90/5.20 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 37.90/5.20 We repeatedly replace C & s=t => u=v by the two clauses:
% 37.90/5.20 fresh(y, y, x1...xn) = u
% 37.90/5.20 C => fresh(s, t, x1...xn) = v
% 37.90/5.20 where fresh is a fresh function symbol and x1..xn are the free
% 37.90/5.20 variables of u and v.
% 37.90/5.20 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 37.90/5.20 input problem has no model of domain size 1).
% 37.90/5.20
% 37.90/5.20 The encoding turns the above axioms into the following unit equations and goals:
% 37.90/5.20
% 37.90/5.20 Axiom 1 (query92): mtvisible(c_tptpgeo_member7_mt) = true2.
% 37.90/5.20 Axiom 2 (ax1_122): fresh667(X, X) = true2.
% 37.90/5.20 Axiom 3 (ax1_122): fresh667(mtvisible(c_tptpgeo_member7_mt), true2) = borderson(c_georegion_l4_x27_y64, c_georegion_l4_x27_y65).
% 37.90/5.20 Axiom 4 (ax1_900): fresh93(X, X, Y, Z) = true2.
% 37.90/5.20 Axiom 5 (ax1_900): fresh93(borderson(X, Y), true2, X, Y) = borderson(Y, X).
% 37.90/5.20
% 37.90/5.20 Goal 1 (query92_1): borderson(X, c_georegion_l4_x27_y64) = true2.
% 37.90/5.20 The goal is true when:
% 37.90/5.20 X = c_georegion_l4_x27_y65
% 37.90/5.20
% 37.90/5.20 Proof:
% 37.90/5.20 borderson(c_georegion_l4_x27_y65, c_georegion_l4_x27_y64)
% 37.90/5.20 = { by axiom 5 (ax1_900) R->L }
% 37.90/5.20 fresh93(borderson(c_georegion_l4_x27_y64, c_georegion_l4_x27_y65), true2, c_georegion_l4_x27_y64, c_georegion_l4_x27_y65)
% 37.90/5.20 = { by axiom 3 (ax1_122) R->L }
% 37.90/5.20 fresh93(fresh667(mtvisible(c_tptpgeo_member7_mt), true2), true2, c_georegion_l4_x27_y64, c_georegion_l4_x27_y65)
% 37.90/5.20 = { by axiom 1 (query92) }
% 37.90/5.20 fresh93(fresh667(true2, true2), true2, c_georegion_l4_x27_y64, c_georegion_l4_x27_y65)
% 37.90/5.20 = { by axiom 2 (ax1_122) }
% 37.90/5.20 fresh93(true2, true2, c_georegion_l4_x27_y64, c_georegion_l4_x27_y65)
% 37.90/5.20 = { by axiom 4 (ax1_900) }
% 37.90/5.20 true2
% 37.90/5.20 % SZS output end Proof
% 37.90/5.20
% 37.90/5.20 RESULT: Theorem (the conjecture is true).
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