TSTP Solution File: CSR035+2 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : CSR035+2 : TPTP v8.1.2. Released v3.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 30 21:41:10 EDT 2023

% Result   : Theorem 25.45s 3.66s
% Output   : Proof 25.45s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem  : CSR035+2 : TPTP v8.1.2. Released v3.4.0.
% 0.00/0.14  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.35  % Computer : n025.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % WCLimit  : 300
% 0.14/0.35  % DateTime : Mon Aug 28 14:41:10 EDT 2023
% 0.14/0.35  % CPUTime  : 
% 25.45/3.66  Command-line arguments: --kbo-weight0 --lhs-weight 5 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --goal-heuristic
% 25.45/3.66  
% 25.45/3.66  % SZS status Theorem
% 25.45/3.66  
% 25.45/3.66  % SZS output start Proof
% 25.45/3.66  Take the following subset of the input axioms:
% 25.45/3.67    fof(ax1_153, axiom, ![OBJ]: ~(tptpcol_1_1(OBJ) & tptpcol_1_65536(OBJ))).
% 25.45/3.67    fof(ax1_167, axiom, ![OBJ2]: ~(individual(OBJ2) & setorcollection(OBJ2))).
% 25.45/3.67    fof(ax1_289, axiom, ![OBJ2]: ~(collection(OBJ2) & individual(OBJ2))).
% 25.45/3.67    fof(ax1_3, axiom, ![OBJ2]: ~(intangible(OBJ2) & partiallytangible(OBJ2))).
% 25.45/3.67    fof(ax1_363, axiom, ![COL1, COL2, OBJ2]: ~(isa(OBJ2, COL1) & (isa(OBJ2, COL2) & disjointwith(COL1, COL2)))).
% 25.45/3.67    fof(ax1_452, axiom, mtvisible(c_englishmt) => prettystring(f_instancewithrelationtofn(c_footballteam, c_affiliatedwith, c_beloitcollege), s_thefootballteamwhohasbeenaffiliatedwithbeloitcollege)).
% 25.45/3.67    fof(ax1_488, axiom, ![OBJ2]: ~(tptpcol_3_98305(OBJ2) & tptpcol_3_114688(OBJ2))).
% 25.45/3.67    fof(ax1_521, axiom, ![X]: ~affiliatedwith(X, X)).
% 25.45/3.67    fof(ax1_698, axiom, ![X2]: ~objectfoundinlocation(X2, X2)).
% 25.45/3.67    fof(ax1_901, axiom, ![X2]: ~borderson(X2, X2)).
% 25.45/3.67    fof(query85, conjecture, ?[X2]: (mtvisible(c_englishmt) => prettystring(f_instancewithrelationtofn(c_footballteam, c_affiliatedwith, c_beloitcollege), X2))).
% 25.45/3.67  
% 25.45/3.67  Now clausify the problem and encode Horn clauses using encoding 3 of
% 25.45/3.67  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 25.45/3.67  We repeatedly replace C & s=t => u=v by the two clauses:
% 25.45/3.67    fresh(y, y, x1...xn) = u
% 25.45/3.67    C => fresh(s, t, x1...xn) = v
% 25.45/3.67  where fresh is a fresh function symbol and x1..xn are the free
% 25.45/3.67  variables of u and v.
% 25.45/3.67  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 25.45/3.67  input problem has no model of domain size 1).
% 25.45/3.67  
% 25.45/3.67  The encoding turns the above axioms into the following unit equations and goals:
% 25.45/3.67  
% 25.45/3.67  Axiom 1 (query85): mtvisible(c_englishmt) = true2.
% 25.45/3.67  Axiom 2 (ax1_452): fresh507(X, X) = true2.
% 25.45/3.67  Axiom 3 (ax1_452): fresh507(mtvisible(c_englishmt), true2) = prettystring(f_instancewithrelationtofn(c_footballteam, c_affiliatedwith, c_beloitcollege), s_thefootballteamwhohasbeenaffiliatedwithbeloitcollege).
% 25.45/3.67  
% 25.45/3.67  Goal 1 (query85_1): prettystring(f_instancewithrelationtofn(c_footballteam, c_affiliatedwith, c_beloitcollege), X) = true2.
% 25.45/3.67  The goal is true when:
% 25.45/3.67    X = s_thefootballteamwhohasbeenaffiliatedwithbeloitcollege
% 25.45/3.67  
% 25.45/3.67  Proof:
% 25.45/3.67    prettystring(f_instancewithrelationtofn(c_footballteam, c_affiliatedwith, c_beloitcollege), s_thefootballteamwhohasbeenaffiliatedwithbeloitcollege)
% 25.45/3.67  = { by axiom 3 (ax1_452) R->L }
% 25.45/3.67    fresh507(mtvisible(c_englishmt), true2)
% 25.45/3.67  = { by axiom 1 (query85) }
% 25.45/3.67    fresh507(true2, true2)
% 25.45/3.67  = { by axiom 2 (ax1_452) }
% 25.45/3.67    true2
% 25.45/3.67  % SZS output end Proof
% 25.45/3.67  
% 25.45/3.67  RESULT: Theorem (the conjecture is true).
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