TSTP Solution File: CSR025+2 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : CSR025+2 : TPTP v8.1.0. Released v3.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Fri Jul 15 23:24:16 EDT 2022

% Result   : Theorem 0.61s 0.83s
% Output   : Refutation 0.61s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : CSR025+2 : TPTP v8.1.0. Released v3.4.0.
% 0.03/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n010.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jun 11 04:46:10 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.61/0.83  
% 0.61/0.83  SPASS V 3.9 
% 0.61/0.83  SPASS beiseite: Proof found.
% 0.61/0.83  % SZS status Theorem
% 0.61/0.83  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.61/0.83  SPASS derived 0 clauses, backtracked 0 clauses, performed 0 splits and kept 1013 clauses.
% 0.61/0.83  SPASS allocated 99764 KBytes.
% 0.61/0.83  SPASS spent	0:00:00.46 on the problem.
% 0.61/0.83  		0:00:00.04 for the input.
% 0.61/0.83  		0:00:00.17 for the FLOTTER CNF translation.
% 0.61/0.83  		0:00:00.00 for inferences.
% 0.61/0.83  		0:00:00.00 for the backtracking.
% 0.61/0.83  		0:00:00.12 for the reduction.
% 0.61/0.83  
% 0.61/0.83  
% 0.61/0.83  Here is a proof with depth 0, length 3 :
% 0.61/0.83  % SZS output start Refutation
% 0.61/0.83  174[0:Inp] ||  -> genls(c_tptpcol_16_130933,c_tptpcol_15_130931)*l.
% 0.61/0.83  268[0:Inp] || genls(c_tptpcol_16_130933,c_tptpcol_15_130931)*l -> .
% 0.61/0.83  1134[0:MRR:268.0,174.0] ||  -> .
% 0.61/0.83  % SZS output end Refutation
% 0.61/0.83  Formulae used in the proof : ax1_327 query75
% 0.61/0.83  
%------------------------------------------------------------------------------