TSTP Solution File: COL029-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : COL029-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:48:01 EDT 2022

% Result   : Unsatisfiable 1.74s 1.95s
% Output   : Refutation 1.74s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    2
%            Number of leaves      :    2
% Syntax   : Number of clauses     :    5 (   5 unt;   0 nHn;   3 RR)
%            Number of literals    :    5 (   4 equ;   2 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   1 con; 0-2 aty)
%            Number of variables   :    6 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    apply(A,f(A)) != apply(f(A),apply(A,f(A))),
    file('COL029-1.p',unknown),
    [] ).

cnf(2,plain,
    apply(f(A),apply(A,f(A))) != apply(A,f(A)),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
    [iquote('copy,1,flip.1')] ).

cnf(4,axiom,
    apply(apply(u,A),B) = apply(B,apply(apply(A,A),B)),
    file('COL029-1.p',unknown),
    [] ).

cnf(5,plain,
    apply(A,apply(apply(B,B),A)) = apply(apply(u,B),A),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[4])]),
    [iquote('copy,4,flip.1')] ).

cnf(6,plain,
    $false,
    inference(binary,[status(thm)],[5,2]),
    [iquote('binary,5.1,2.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : COL029-1 : TPTP v8.1.0. Released v1.0.0.
% 0.07/0.13  % Command  : otter-tptp-script %s
% 0.13/0.34  % Computer : n022.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Wed Jul 27 02:25:50 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 1.74/1.95  
% 1.74/1.95  -------- PROOF -------- 
% 1.74/1.95  ----- Otter 3.3f, August 2004 -----
% 1.74/1.95  The process was started by sandbox2 on n022.cluster.edu,
% 1.74/1.95  Wed Jul 27 02:25:50 2022
% 1.74/1.95  The command was "./otter".  The process ID is 11270.
% 1.74/1.95  
% 1.74/1.95  set(prolog_style_variables).
% 1.74/1.95  set(auto).
% 1.74/1.95     dependent: set(auto1).
% 1.74/1.95     dependent: set(process_input).
% 1.74/1.95     dependent: clear(print_kept).
% 1.74/1.95     dependent: clear(print_new_demod).
% 1.74/1.95     dependent: clear(print_back_demod).
% 1.74/1.95     dependent: clear(print_back_sub).
% 1.74/1.95     dependent: set(control_memory).
% 1.74/1.95     dependent: assign(max_mem, 12000).
% 1.74/1.95     dependent: assign(pick_given_ratio, 4).
% 1.74/1.95     dependent: assign(stats_level, 1).
% 1.74/1.95     dependent: assign(max_seconds, 10800).
% 1.74/1.95  clear(print_given).
% 1.74/1.95  
% 1.74/1.95  list(usable).
% 1.74/1.95  0 [] A=A.
% 1.74/1.95  0 [] apply(apply(u,X),Y)=apply(Y,apply(apply(X,X),Y)).
% 1.74/1.95  0 [] apply(Y,f(Y))!=apply(f(Y),apply(Y,f(Y))).
% 1.74/1.95  end_of_list.
% 1.74/1.95  
% 1.74/1.95  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.74/1.95  
% 1.74/1.95  All clauses are units, and equality is present; the
% 1.74/1.95  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.74/1.95  
% 1.74/1.95     dependent: set(knuth_bendix).
% 1.74/1.95     dependent: set(anl_eq).
% 1.74/1.95     dependent: set(para_from).
% 1.74/1.95     dependent: set(para_into).
% 1.74/1.95     dependent: clear(para_from_right).
% 1.74/1.95     dependent: clear(para_into_right).
% 1.74/1.95     dependent: set(para_from_vars).
% 1.74/1.95     dependent: set(eq_units_both_ways).
% 1.74/1.95     dependent: set(dynamic_demod_all).
% 1.74/1.95     dependent: set(dynamic_demod).
% 1.74/1.95     dependent: set(order_eq).
% 1.74/1.95     dependent: set(back_demod).
% 1.74/1.95     dependent: set(lrpo).
% 1.74/1.95  
% 1.74/1.95  ------------> process usable:
% 1.74/1.95  ** KEPT (pick-wt=12): 2 [copy,1,flip.1] apply(f(A),apply(A,f(A)))!=apply(A,f(A)).
% 1.74/1.95  
% 1.74/1.95  ------------> process sos:
% 1.74/1.95  ** KEPT (pick-wt=3): 3 [] A=A.
% 1.74/1.95  ** KEPT (pick-wt=13): 4 [] apply(apply(u,A),B)=apply(B,apply(apply(A,A),B)).
% 1.74/1.95    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.74/1.95  ** KEPT (pick-wt=13): 5 [copy,4,flip.1] apply(A,apply(apply(B,B),A))=apply(apply(u,B),A).
% 1.74/1.95  
% 1.74/1.95  ----> UNIT CONFLICT at   0.00 sec ----> 6 [binary,5.1,2.1] $F.
% 1.74/1.95  
% 1.74/1.95  Length of proof is 2.  Level of proof is 1.
% 1.74/1.95  
% 1.74/1.95  ---------------- PROOF ----------------
% 1.74/1.95  % SZS status Unsatisfiable
% 1.74/1.95  % SZS output start Refutation
% See solution above
% 1.74/1.95  ------------ end of proof -------------
% 1.74/1.95  
% 1.74/1.95  
% 1.74/1.95  Search stopped by max_proofs option.
% 1.74/1.95  
% 1.74/1.95  
% 1.74/1.95  Search stopped by max_proofs option.
% 1.74/1.95  
% 1.74/1.95  ============ end of search ============
% 1.74/1.95  
% 1.74/1.95  -------------- statistics -------------
% 1.74/1.95  clauses given                  0
% 1.74/1.95  clauses generated              0
% 1.74/1.95  clauses kept                   4
% 1.74/1.95  clauses forward subsumed       1
% 1.74/1.95  clauses back subsumed          0
% 1.74/1.95  Kbytes malloced              976
% 1.74/1.95  
% 1.74/1.95  ----------- times (seconds) -----------
% 1.74/1.95  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.74/1.95  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.74/1.95  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.74/1.95  
% 1.74/1.95  That finishes the proof of the theorem.
% 1.74/1.95  
% 1.74/1.95  Process 11270 finished Wed Jul 27 02:25:52 2022
% 1.74/1.95  Otter interrupted
% 1.74/1.95  PROOF FOUND
%------------------------------------------------------------------------------