TSTP Solution File: CAT014-2 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : CAT014-2 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:47:49 EDT 2022

% Result   : Unsatisfiable 1.69s 1.90s
% Output   : Refutation 1.69s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    2
%            Number of leaves      :    3
% Syntax   : Number of clauses     :    5 (   5 unt;   0 nHn;   2 RR)
%            Number of literals    :    5 (   4 equ;   1 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    3 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   1 con; 0-1 aty)
%            Number of variables   :    3 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(5,axiom,
    codomain(codomain(a)) != codomain(a),
    file('CAT014-2.p',unknown),
    [] ).

cnf(7,axiom,
    codomain(domain(A)) = domain(A),
    file('CAT014-2.p',unknown),
    [] ).

cnf(10,axiom,
    domain(codomain(A)) = codomain(A),
    file('CAT014-2.p',unknown),
    [] ).

cnf(23,plain,
    codomain(codomain(A)) = codomain(A),
    inference(demod,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[10,7]),10]),
    [iquote('para_from,9.1.1,7.1.1.1,demod,10')] ).

cnf(25,plain,
    $false,
    inference(binary,[status(thm)],[23,5]),
    [iquote('binary,23.1,5.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : CAT014-2 : TPTP v8.1.0. Released v1.0.0.
% 0.11/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n003.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 01:54:26 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.69/1.90  ----- Otter 3.3f, August 2004 -----
% 1.69/1.90  The process was started by sandbox on n003.cluster.edu,
% 1.69/1.90  Wed Jul 27 01:54:26 2022
% 1.69/1.90  The command was "./otter".  The process ID is 18376.
% 1.69/1.90  
% 1.69/1.90  set(prolog_style_variables).
% 1.69/1.90  set(auto).
% 1.69/1.90     dependent: set(auto1).
% 1.69/1.90     dependent: set(process_input).
% 1.69/1.90     dependent: clear(print_kept).
% 1.69/1.90     dependent: clear(print_new_demod).
% 1.69/1.90     dependent: clear(print_back_demod).
% 1.69/1.90     dependent: clear(print_back_sub).
% 1.69/1.90     dependent: set(control_memory).
% 1.69/1.90     dependent: assign(max_mem, 12000).
% 1.69/1.90     dependent: assign(pick_given_ratio, 4).
% 1.69/1.90     dependent: assign(stats_level, 1).
% 1.69/1.90     dependent: assign(max_seconds, 10800).
% 1.69/1.90  clear(print_given).
% 1.69/1.90  
% 1.69/1.90  list(usable).
% 1.69/1.90  0 [] A=A.
% 1.69/1.90  0 [] codomain(domain(X))=domain(X).
% 1.69/1.90  0 [] domain(codomain(X))=codomain(X).
% 1.69/1.90  0 [] compose(domain(X),X)=X.
% 1.69/1.90  0 [] compose(X,codomain(X))=X.
% 1.69/1.90  0 [] codomain(X)!=domain(Y)|domain(compose(X,Y))=domain(X).
% 1.69/1.90  0 [] codomain(X)!=domain(Y)|codomain(compose(X,Y))=codomain(Y).
% 1.69/1.90  0 [] codomain(X)!=domain(Y)|codomain(Y)!=domain(Z)|compose(X,compose(Y,Z))=compose(compose(X,Y),Z).
% 1.69/1.90  0 [] codomain(codomain(a))!=codomain(a).
% 1.69/1.90  end_of_list.
% 1.69/1.90  
% 1.69/1.90  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=3.
% 1.69/1.90  
% 1.69/1.90  This is a Horn set with equality.  The strategy will be
% 1.69/1.90  Knuth-Bendix and hyper_res, with positive clauses in
% 1.69/1.90  sos and nonpositive clauses in usable.
% 1.69/1.90  
% 1.69/1.90     dependent: set(knuth_bendix).
% 1.69/1.90     dependent: set(anl_eq).
% 1.69/1.90     dependent: set(para_from).
% 1.69/1.90     dependent: set(para_into).
% 1.69/1.90     dependent: clear(para_from_right).
% 1.69/1.90     dependent: clear(para_into_right).
% 1.69/1.90     dependent: set(para_from_vars).
% 1.69/1.90     dependent: set(eq_units_both_ways).
% 1.69/1.90     dependent: set(dynamic_demod_all).
% 1.69/1.90     dependent: set(dynamic_demod).
% 1.69/1.90     dependent: set(order_eq).
% 1.69/1.90     dependent: set(back_demod).
% 1.69/1.90     dependent: set(lrpo).
% 1.69/1.90     dependent: set(hyper_res).
% 1.69/1.90     dependent: clear(order_hyper).
% 1.69/1.90  
% 1.69/1.90  ------------> process usable:
% 1.69/1.90  ** KEPT (pick-wt=12): 1 [] codomain(A)!=domain(B)|domain(compose(A,B))=domain(A).
% 1.69/1.90  ** KEPT (pick-wt=12): 2 [] codomain(A)!=domain(B)|codomain(compose(A,B))=codomain(B).
% 1.69/1.90  ** KEPT (pick-wt=21): 4 [copy,3,flip.3] codomain(A)!=domain(B)|codomain(B)!=domain(C)|compose(compose(A,B),C)=compose(A,compose(B,C)).
% 1.69/1.90  ** KEPT (pick-wt=6): 5 [] codomain(codomain(a))!=codomain(a).
% 1.69/1.90  
% 1.69/1.90  ------------> process sos:
% 1.69/1.90  ** KEPT (pick-wt=3): 6 [] A=A.
% 1.69/1.90  ** KEPT (pick-wt=6): 7 [] codomain(domain(A))=domain(A).
% 1.69/1.90  ---> New Demodulator: 8 [new_demod,7] codomain(domain(A))=domain(A).
% 1.69/1.90  ** KEPT (pick-wt=6): 9 [] domain(codomain(A))=codomain(A).
% 1.69/1.90  ---> New Demodulator: 10 [new_demod,9] domain(codomain(A))=codomain(A).
% 1.69/1.90  ** KEPT (pick-wt=6): 11 [] compose(domain(A),A)=A.
% 1.69/1.90  ---> New Demodulator: 12 [new_demod,11] compose(domain(A),A)=A.
% 1.69/1.90  ** KEPT (pick-wt=6): 13 [] compose(A,codomain(A))=A.
% 1.69/1.90  ---> New Demodulator: 14 [new_demod,13] compose(A,codomain(A))=A.
% 1.69/1.90    Following clause subsumed by 6 during input processing: 0 [copy,6,flip.1] A=A.
% 1.69/1.90  >>>> Starting back demodulation with 8.
% 1.69/1.90  >>>> Starting back demodulation with 10.
% 1.69/1.90  >>>> Starting back demodulation with 12.
% 1.69/1.90  >>>> Starting back demodulation with 14.
% 1.69/1.90  
% 1.69/1.90  ======= end of input processing =======
% 1.69/1.90  
% 1.69/1.90  =========== start of search ===========
% 1.69/1.90  
% 1.69/1.90  -------- PROOF -------- 
% 1.69/1.90  
% 1.69/1.90  ----> UNIT CONFLICT at   0.00 sec ----> 25 [binary,23.1,5.1] $F.
% 1.69/1.90  
% 1.69/1.90  Length of proof is 1.  Level of proof is 1.
% 1.69/1.90  
% 1.69/1.90  ---------------- PROOF ----------------
% 1.69/1.90  % SZS status Unsatisfiable
% 1.69/1.90  % SZS output start Refutation
% See solution above
% 1.69/1.90  ------------ end of proof -------------
% 1.69/1.90  
% 1.69/1.90  
% 1.69/1.90  Search stopped by max_proofs option.
% 1.69/1.90  
% 1.69/1.90  
% 1.69/1.90  Search stopped by max_proofs option.
% 1.69/1.90  
% 1.69/1.90  ============ end of search ============
% 1.69/1.90  
% 1.69/1.90  -------------- statistics -------------
% 1.69/1.90  clauses given                  3
% 1.69/1.90  clauses generated             16
% 1.69/1.90  clauses kept                  16
% 1.69/1.90  clauses forward subsumed      11
% 1.69/1.90  clauses back subsumed          0
% 1.69/1.90  Kbytes malloced              976
% 1.69/1.90  
% 1.69/1.90  ----------- times (seconds) -----------
% 1.69/1.90  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.69/1.90  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.69/1.90  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.69/1.90  
% 1.69/1.90  That finishes the proof of the theorem.
% 1.69/1.90  
% 1.69/1.90  Process 18376 finished Wed Jul 27 01:54:28 2022
% 1.69/1.90  Otter interrupted
% 1.69/1.90  PROOF FOUND
%------------------------------------------------------------------------------