TSTP Solution File: CAT012-4 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : CAT012-4 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:47:48 EDT 2022

% Result   : Unsatisfiable 1.73s 1.93s
% Output   : Refutation 1.73s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    5
% Syntax   : Number of clauses     :    9 (   6 unt;   0 nHn;   8 RR)
%            Number of literals    :   12 (   5 equ;   4 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    3 (   2 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   1 con; 0-2 aty)
%            Number of variables   :    5 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(4,axiom,
    ( ~ there_exists(domain(A))
    | there_exists(A) ),
    file('CAT012-4.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ there_exists(compose(A,B))
    | domain(A) = codomain(B) ),
    file('CAT012-4.p',unknown),
    [] ).

cnf(9,axiom,
    codomain(domain(a)) != domain(a),
    file('CAT012-4.p',unknown),
    [] ).

cnf(14,axiom,
    compose(A,domain(A)) = A,
    file('CAT012-4.p',unknown),
    [] ).

cnf(18,axiom,
    there_exists(domain(a)),
    file('CAT012-4.p',unknown),
    [] ).

cnf(19,plain,
    there_exists(a),
    inference(hyper,[status(thm)],[18,4]),
    [iquote('hyper,18,4')] ).

cnf(45,plain,
    ( ~ there_exists(A)
    | codomain(domain(A)) = domain(A) ),
    inference(flip,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[14,7])]),
    [iquote('para_from,14.1.1,7.1.1,flip.2')] ).

cnf(923,plain,
    codomain(domain(a)) = domain(a),
    inference(hyper,[status(thm)],[45,19]),
    [iquote('hyper,45,19')] ).

cnf(925,plain,
    $false,
    inference(binary,[status(thm)],[923,9]),
    [iquote('binary,923.1,9.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : CAT012-4 : TPTP v8.1.0. Released v1.0.0.
% 0.11/0.12  % Command  : otter-tptp-script %s
% 0.11/0.33  % Computer : n028.cluster.edu
% 0.11/0.33  % Model    : x86_64 x86_64
% 0.11/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33  % Memory   : 8042.1875MB
% 0.11/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33  % CPULimit : 300
% 0.11/0.33  % WCLimit  : 300
% 0.11/0.33  % DateTime : Wed Jul 27 02:11:33 EDT 2022
% 0.11/0.33  % CPUTime  : 
% 1.73/1.93  ----- Otter 3.3f, August 2004 -----
% 1.73/1.93  The process was started by sandbox on n028.cluster.edu,
% 1.73/1.93  Wed Jul 27 02:11:33 2022
% 1.73/1.93  The command was "./otter".  The process ID is 23763.
% 1.73/1.93  
% 1.73/1.93  set(prolog_style_variables).
% 1.73/1.93  set(auto).
% 1.73/1.93     dependent: set(auto1).
% 1.73/1.93     dependent: set(process_input).
% 1.73/1.93     dependent: clear(print_kept).
% 1.73/1.93     dependent: clear(print_new_demod).
% 1.73/1.93     dependent: clear(print_back_demod).
% 1.73/1.93     dependent: clear(print_back_sub).
% 1.73/1.93     dependent: set(control_memory).
% 1.73/1.93     dependent: assign(max_mem, 12000).
% 1.73/1.93     dependent: assign(pick_given_ratio, 4).
% 1.73/1.93     dependent: assign(stats_level, 1).
% 1.73/1.93     dependent: assign(max_seconds, 10800).
% 1.73/1.93  clear(print_given).
% 1.73/1.93  
% 1.73/1.93  list(usable).
% 1.73/1.93  0 [] A=A.
% 1.73/1.93  0 [] -e_quivalent(X,Y)|there_exists(X).
% 1.73/1.93  0 [] -e_quivalent(X,Y)|X=Y.
% 1.73/1.93  0 [] -there_exists(X)|X!=Y|e_quivalent(X,Y).
% 1.73/1.93  0 [] -there_exists(domain(X))|there_exists(X).
% 1.73/1.93  0 [] -there_exists(codomain(X))|there_exists(X).
% 1.73/1.93  0 [] -there_exists(compose(X,Y))|there_exists(domain(X)).
% 1.73/1.93  0 [] -there_exists(compose(X,Y))|domain(X)=codomain(Y).
% 1.73/1.93  0 [] -there_exists(domain(X))|domain(X)!=codomain(Y)|there_exists(compose(X,Y)).
% 1.73/1.93  0 [] compose(X,compose(Y,Z))=compose(compose(X,Y),Z).
% 1.73/1.93  0 [] compose(X,domain(X))=X.
% 1.73/1.93  0 [] compose(codomain(X),X)=X.
% 1.73/1.93  0 [] there_exists(domain(a)).
% 1.73/1.93  0 [] codomain(domain(a))!=domain(a).
% 1.73/1.93  end_of_list.
% 1.73/1.93  
% 1.73/1.93  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=3.
% 1.73/1.93  
% 1.73/1.93  This is a Horn set with equality.  The strategy will be
% 1.73/1.93  Knuth-Bendix and hyper_res, with positive clauses in
% 1.73/1.93  sos and nonpositive clauses in usable.
% 1.73/1.93  
% 1.73/1.93     dependent: set(knuth_bendix).
% 1.73/1.93     dependent: set(anl_eq).
% 1.73/1.93     dependent: set(para_from).
% 1.73/1.93     dependent: set(para_into).
% 1.73/1.93     dependent: clear(para_from_right).
% 1.73/1.93     dependent: clear(para_into_right).
% 1.73/1.93     dependent: set(para_from_vars).
% 1.73/1.93     dependent: set(eq_units_both_ways).
% 1.73/1.93     dependent: set(dynamic_demod_all).
% 1.73/1.93     dependent: set(dynamic_demod).
% 1.73/1.93     dependent: set(order_eq).
% 1.73/1.93     dependent: set(back_demod).
% 1.73/1.93     dependent: set(lrpo).
% 1.73/1.93     dependent: set(hyper_res).
% 1.73/1.93     dependent: clear(order_hyper).
% 1.73/1.93  
% 1.73/1.93  ------------> process usable:
% 1.73/1.93  ** KEPT (pick-wt=5): 1 [] -e_quivalent(A,B)|there_exists(A).
% 1.73/1.93  ** KEPT (pick-wt=6): 2 [] -e_quivalent(A,B)|A=B.
% 1.73/1.93  ** KEPT (pick-wt=8): 3 [] -there_exists(A)|A!=B|e_quivalent(A,B).
% 1.73/1.93  ** KEPT (pick-wt=5): 4 [] -there_exists(domain(A))|there_exists(A).
% 1.73/1.93  ** KEPT (pick-wt=5): 5 [] -there_exists(codomain(A))|there_exists(A).
% 1.73/1.93  ** KEPT (pick-wt=7): 6 [] -there_exists(compose(A,B))|there_exists(domain(A)).
% 1.73/1.93  ** KEPT (pick-wt=9): 7 [] -there_exists(compose(A,B))|domain(A)=codomain(B).
% 1.73/1.93  ** KEPT (pick-wt=12): 8 [] -there_exists(domain(A))|domain(A)!=codomain(B)|there_exists(compose(A,B)).
% 1.73/1.93  ** KEPT (pick-wt=6): 9 [] codomain(domain(a))!=domain(a).
% 1.73/1.93  
% 1.73/1.93  ------------> process sos:
% 1.73/1.93  ** KEPT (pick-wt=3): 10 [] A=A.
% 1.73/1.93  ** KEPT (pick-wt=11): 12 [copy,11,flip.1] compose(compose(A,B),C)=compose(A,compose(B,C)).
% 1.73/1.93  ---> New Demodulator: 13 [new_demod,12] compose(compose(A,B),C)=compose(A,compose(B,C)).
% 1.73/1.93  ** KEPT (pick-wt=6): 14 [] compose(A,domain(A))=A.
% 1.73/1.93  ---> New Demodulator: 15 [new_demod,14] compose(A,domain(A))=A.
% 1.73/1.93  ** KEPT (pick-wt=6): 16 [] compose(codomain(A),A)=A.
% 1.73/1.93  ---> New Demodulator: 17 [new_demod,16] compose(codomain(A),A)=A.
% 1.73/1.93  ** KEPT (pick-wt=3): 18 [] there_exists(domain(a)).
% 1.73/1.93    Following clause subsumed by 10 during input processing: 0 [copy,10,flip.1] A=A.
% 1.73/1.93  >>>> Starting back demodulation with 13.
% 1.73/1.93  >>>> Starting back demodulation with 15.
% 1.73/1.93  >>>> Starting back demodulation with 17.
% 1.73/1.93  
% 1.73/1.93  ======= end of input processing =======
% 1.73/1.93  
% 1.73/1.93  =========== start of search ===========
% 1.73/1.93  
% 1.73/1.93  -------- PROOF -------- 
% 1.73/1.93  
% 1.73/1.93  ----> UNIT CONFLICT at   0.05 sec ----> 925 [binary,923.1,9.1] $F.
% 1.73/1.93  
% 1.73/1.93  Length of proof is 3.  Level of proof is 2.
% 1.73/1.93  
% 1.73/1.93  ---------------- PROOF ----------------
% 1.73/1.93  % SZS status Unsatisfiable
% 1.73/1.93  % SZS output start Refutation
% See solution above
% 1.73/1.93  ------------ end of proof -------------
% 1.73/1.93  
% 1.73/1.93  
% 1.73/1.93  Search stopped by max_proofs option.
% 1.73/1.93  
% 1.73/1.93  
% 1.73/1.93  Search stopped by max_proofs option.
% 1.73/1.93  
% 1.73/1.93  ============ end of search ============
% 1.73/1.93  
% 1.73/1.93  -------------- statistics -------------
% 1.73/1.93  clauses given                 91
% 1.73/1.93  clauses generated           1209
% 1.73/1.93  clauses kept                 883
% 1.73/1.93  clauses forward subsumed     331
% 1.73/1.93  clauses back subsumed          7
% 1.73/1.93  Kbytes malloced             3906
% 1.73/1.93  
% 1.73/1.93  ----------- times (seconds) -----------
% 1.73/1.93  user CPU time          0.05          (0 hr, 0 min, 0 sec)
% 1.73/1.93  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.73/1.93  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.73/1.93  
% 1.73/1.93  That finishes the proof of the theorem.
% 1.73/1.93  
% 1.73/1.93  Process 23763 finished Wed Jul 27 02:11:35 2022
% 1.73/1.93  Otter interrupted
% 1.73/1.93  PROOF FOUND
%------------------------------------------------------------------------------