TSTP Solution File: ARI610_1 by SPASS+T---2.2.22
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% File : SPASS+T---2.2.22
% Problem : ARI610_1 : TPTP v8.1.0. Released v5.1.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n027.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 14 22:18:18 EDT 2022
% Result : Theorem 0.45s 1.02s
% Output : Refutation 0.45s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : ARI610_1 : TPTP v8.1.0. Released v5.1.0.
% 0.03/0.13 % Command : spasst-tptp-script %s %d
% 0.13/0.34 % Computer : n027.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Fri Jun 17 12:56:36 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.20/0.47 % Using integer theory
% 0.45/1.02
% 0.45/1.02
% 0.45/1.02 % SZS status Theorem for /tmp/SPASST_10205_n027.cluster.edu
% 0.45/1.02
% 0.45/1.02 SPASS V 2.2.22 in combination with yices.
% 0.45/1.02 SPASS beiseite: Proof found by SPASS and SMT.
% 0.45/1.02 Problem: /tmp/SPASST_10205_n027.cluster.edu
% 0.45/1.02 SPASS derived 128 clauses, backtracked 51 clauses and kept 164 clauses.
% 0.45/1.02 SPASS backtracked 3 times (1 times due to theory inconsistency).
% 0.45/1.02 SPASS allocated 6327 KBytes.
% 0.45/1.02 SPASS spent 0:00:00.02 on the problem.
% 0.45/1.02 0:00:00.00 for the input.
% 0.45/1.02 0:00:00.00 for the FLOTTER CNF translation.
% 0.45/1.02 0:00:00.00 for inferences.
% 0.45/1.02 0:00:00.00 for the backtracking.
% 0.45/1.02 0:00:00.01 for the reduction.
% 0.45/1.02 0:00:00.00 for interacting with the SMT procedure.
% 0.45/1.02
% 0.45/1.02
% 0.45/1.02 % SZS output start CNFRefutation for /tmp/SPASST_10205_n027.cluster.edu
% 0.45/1.02
% 0.45/1.02 % Here is a proof with depth 0, length 4 :
% 0.45/1.02 4(e)[0:Inp] || -> less(f(b),f(a))*.
% 0.45/1.02 5[0:Inp] || lesseq(U,V) -> lesseq(f(U),f(V))*.
% 0.45/1.02 6[0:Inp] || lesseq(f(0),f(plus(a,uminus(b))))* -> .
% 0.45/1.02 213(e)[0:ThR:6,5,4] || -> .
% 0.45/1.02
% 0.45/1.02 % SZS output end CNFRefutation for /tmp/SPASST_10205_n027.cluster.edu
% 0.45/1.02
% 0.45/1.02 Formulae used in the proof : fof_f_type fof_f_mon_implies_f_a_b_2
% 0.45/1.02
% 0.45/1.02 SPASS+T ended
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