TSTP Solution File: ARI576_1 by SPASS+T---2.2.22
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- Process Solution
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% File : SPASS+T---2.2.22
% Problem : ARI576_1 : TPTP v8.1.0. Released v5.1.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n028.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 14 22:18:09 EDT 2022
% Result : Theorem 0.43s 1.00s
% Output : Refutation 0.43s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : ARI576_1 : TPTP v8.1.0. Released v5.1.0.
% 0.12/0.12 % Command : spasst-tptp-script %s %d
% 0.12/0.33 % Computer : n028.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Fri Jun 17 13:18:13 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.46 % Using integer theory
% 0.43/1.00
% 0.43/1.00
% 0.43/1.00 % SZS status Theorem for /tmp/SPASST_4547_n028.cluster.edu
% 0.43/1.00
% 0.43/1.00 SPASS V 2.2.22 in combination with yices.
% 0.43/1.00 SPASS beiseite: Proof found by SPASS.
% 0.43/1.00 Problem: /tmp/SPASST_4547_n028.cluster.edu
% 0.43/1.00 SPASS derived 14 clauses, backtracked 0 clauses and kept 38 clauses.
% 0.43/1.00 SPASS backtracked 0 times (0 times due to theory inconsistency).
% 0.43/1.00 SPASS allocated 6215 KBytes.
% 0.43/1.00 SPASS spent 0:00:00.01 on the problem.
% 0.43/1.00 0:00:00.00 for the input.
% 0.43/1.00 0:00:00.00 for the FLOTTER CNF translation.
% 0.43/1.00 0:00:00.00 for inferences.
% 0.43/1.00 0:00:00.00 for the backtracking.
% 0.43/1.00 0:00:00.00 for the reduction.
% 0.43/1.00 0:00:00.00 for interacting with the SMT procedure.
% 0.43/1.00
% 0.43/1.00
% 0.43/1.00 % SZS output start CNFRefutation for /tmp/SPASST_4547_n028.cluster.edu
% 0.43/1.00
% 0.43/1.00 % Here is a proof with depth 1, length 5 :
% 0.43/1.00 1[0:Inp] || lesseq(29,times(3,U))* lesseq(times(2,U),21) -> .
% 0.43/1.00 33[0:ArS:1.1] || lesseq(10,U)* lesseq(U,10)* -> .
% 0.43/1.00 34[0:TOC:33.1] || -> less(U,10)* less(10,U)*.
% 0.43/1.00 35[0:Fac:34.0,34.1] || -> less(10,10)*.
% 0.43/1.00 49(e)[0:ArS:35.0] || -> .
% 0.43/1.00
% 0.43/1.00 % SZS output end CNFRefutation for /tmp/SPASST_4547_n028.cluster.edu
% 0.43/1.00
% 0.43/1.00 Formulae used in the proof :
% 0.74/1.02
% 0.74/1.02 SPASS+T ended
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