TSTP Solution File: ALG036+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : ALG036+1 : TPTP v8.1.0. Released v2.7.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 14 16:51:18 EDT 2022
% Result : Theorem 0.20s 0.37s
% Output : CNFRefutation 0.20s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 5
% Syntax : Number of formulae : 14 ( 7 unt; 0 def)
% Number of atoms : 95 ( 84 equ)
% Maximal formula atoms : 32 ( 6 avg)
% Number of connectives : 97 ( 16 ~; 23 |; 57 &)
% ( 1 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 12 ( 5 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 3 ( 1 usr; 2 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 5 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn 0 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(co1,conjecture,
( ( op(e0,e0) = e0
& op(e1,e1) = e0
& op(e2,e2) = e0
& op(e3,e3) = e0 )
| ( op(e0,e0) = e1
& op(e1,e1) = e1
& op(e2,e2) = e1
& op(e3,e3) = e1 )
| ( op(e0,e0) = e2
& op(e1,e1) = e2
& op(e2,e2) = e2
& op(e3,e3) = e2 )
| ( op(e0,e0) = e3
& op(e1,e1) = e3
& op(e2,e2) = e3
& op(e3,e3) = e3 )
| ~ ( ( op(e0,e0) = e0
& op(e1,e1) = e0
& op(e2,e2) = e0
& op(e3,e3) = e0 )
| ( op(e0,e0) = e1
& op(e1,e1) = e1
& op(e2,e2) = e1
& op(e3,e3) = e1 )
| ( op(e0,e0) = e2
& op(e1,e1) = e2
& op(e2,e2) = e2
& op(e3,e3) = e2 )
| ( op(e0,e0) = e3
& op(e1,e1) = e3
& op(e2,e2) = e3
& op(e3,e3) = e3 ) ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',co1) ).
fof(ax2,axiom,
( op(unit,e0) = e0
& op(e0,unit) = e0
& op(unit,e1) = e1
& op(e1,unit) = e1
& op(unit,e2) = e2
& op(e2,unit) = e2
& op(unit,e3) = e3
& op(e3,unit) = e3
& ( unit = e0
| unit = e1
| unit = e2
| unit = e3 ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',ax2) ).
fof(ax4,axiom,
unit = e0,
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',ax4) ).
fof(ax6,axiom,
( e0 != e1
& e0 != e2
& e0 != e3
& e1 != e2
& e1 != e3
& e2 != e3 ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',ax6) ).
fof(c_0_4,plain,
( epred1_0
<=> ( ( op(e0,e0) = e0
& op(e1,e1) = e0
& op(e2,e2) = e0
& op(e3,e3) = e0 )
| ( op(e0,e0) = e1
& op(e1,e1) = e1
& op(e2,e2) = e1
& op(e3,e3) = e1 )
| ( op(e0,e0) = e2
& op(e1,e1) = e2
& op(e2,e2) = e2
& op(e3,e3) = e2 ) ) ),
introduced(definition) ).
fof(c_0_5,negated_conjecture,
~ ( epred1_0
| ( op(e0,e0) = e3
& op(e1,e1) = e3
& op(e2,e2) = e3
& op(e3,e3) = e3 )
| ~ ( epred1_0
| ( op(e0,e0) = e3
& op(e1,e1) = e3
& op(e2,e2) = e3
& op(e3,e3) = e3 ) ) ),
inference(apply_def,[status(thm)],[inference(apply_def,[status(thm)],[inference(assume_negation,[status(cth)],[co1]),c_0_4]),c_0_4]) ).
fof(c_0_6,negated_conjecture,
( ~ epred1_0
& ( op(e0,e0) != e3
| op(e1,e1) != e3
| op(e2,e2) != e3
| op(e3,e3) != e3 )
& ( op(e0,e0) = e3
| epred1_0 )
& ( op(e1,e1) = e3
| epred1_0 )
& ( op(e2,e2) = e3
| epred1_0 )
& ( op(e3,e3) = e3
| epred1_0 ) ),
inference(distribute,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_5])]) ).
cnf(c_0_7,plain,
op(e0,unit) = e0,
inference(split_conjunct,[status(thm)],[ax2]) ).
cnf(c_0_8,plain,
unit = e0,
inference(split_conjunct,[status(thm)],[ax4]) ).
cnf(c_0_9,negated_conjecture,
( op(e0,e0) = e3
| epred1_0 ),
inference(split_conjunct,[status(thm)],[c_0_6]) ).
cnf(c_0_10,plain,
op(e0,e0) = e0,
inference(rw,[status(thm)],[c_0_7,c_0_8]) ).
cnf(c_0_11,plain,
e0 != e3,
inference(split_conjunct,[status(thm)],[ax6]) ).
cnf(c_0_12,negated_conjecture,
~ epred1_0,
inference(split_conjunct,[status(thm)],[c_0_6]) ).
cnf(c_0_13,negated_conjecture,
$false,
inference(sr,[status(thm)],[inference(sr,[status(thm)],[inference(rw,[status(thm)],[c_0_9,c_0_10]),c_0_11]),c_0_12]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : ALG036+1 : TPTP v8.1.0. Released v2.7.0.
% 0.03/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.14/0.34 % Computer : n020.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 600
% 0.14/0.34 % DateTime : Thu Jun 9 04:23:06 EDT 2022
% 0.14/0.34 % CPUTime :
% 0.20/0.37 # No SInE strategy applied
% 0.20/0.37 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.20/0.37 # and selection function SelectComplexExceptUniqMaxHorn.
% 0.20/0.37 #
% 0.20/0.37 # Presaturation interreduction done
% 0.20/0.37
% 0.20/0.37 # Proof found!
% 0.20/0.37 # SZS status Theorem
% 0.20/0.37 # SZS output start CNFRefutation
% See solution above
% 0.20/0.37 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------